Here aare some proof questions, Quizzes of Mathematics

The description is that you can practice these quiz proof questions for infimum/supremum

Typology: Quizzes

2024/2025

Uploaded on 04/10/2025

daniel-farlinger
daniel-farlinger ๐Ÿ‡บ๐Ÿ‡ธ

1 document

1 / 2

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
MAT 1362 โ€“ Winter 2025
Quiz 8 โ€“ DGD 2 (Friday) โ€“ Solutions
Professor: Alistair Savage
Date: March 28, 2025
Question (4 points). Consider the function
f:R>0โ†’R>0, f(x) = x+ 1
5.
(a) Is finjective? Justify your answer.
Solution: Yes, fis injective. For x1, x2โˆˆR>0, we have
f(x1) = f(x2) =โ‡’x1+ 1
5=x2+ 1
5
=โ‡’x1+ 1 = x2+ 1
=โ‡’x1=x2.
(b) Is fsurjective? Justify your answer.
Solution: No, fis not surjective. For all xโˆˆR>0, we have
x > 0 =โ‡’x+ 1 >1 =โ‡’f(x) = x+ 1
5>1
5.
Hence, for example, there is no xโˆˆR>0such that f(x) = 1
10 .
(c) Does fhave a left inverse? If it does, give one and show that it is indeed a left inverse.
Otherwise, justify why fdoes not have a left inverse.
Solution: Yes. A function has a left inverse if and only if it is injective. Since fis
injective, it has a left inverse. Define
g:R>0โ†’R>0, g(y) = |5yโˆ’1|.
pf2

Partial preview of the text

Download Here aare some proof questions and more Quizzes Mathematics in PDF only on Docsity!

MAT 1362 โ€“ Winter 2025

Quiz 8 โ€“ DGD 2 (Friday) โ€“ Solutions

Professor: Alistair Savage

Date: March 28, 2025

Question (4 points). Consider the function

f : R> 0 โ†’ R> 0 , f (x) =

x + 1 5

(a) Is f injective? Justify your answer.

Solution: Yes, f is injective. For x 1 , x 2 โˆˆ R> 0 , we have

f (x 1 ) = f (x 2 ) =โ‡’ x 1 + 1 5

x 2 + 1 5 =โ‡’ x 1 + 1 = x 2 + 1 =โ‡’ x 1 = x 2.

(b) Is f surjective? Justify your answer.

Solution: No, f is not surjective. For all x โˆˆ R> 0 , we have

x > 0 =โ‡’ x + 1 > 1 =โ‡’ f (x) = x + 1 5

Hence, for example, there is no x โˆˆ R> 0 such that f (x) = 101.

(c) Does f have a left inverse? If it does, give one and show that it is indeed a left inverse. Otherwise, justify why f does not have a left inverse.

Solution: Yes. A function has a left inverse if and only if it is injective. Since f is injective, it has a left inverse. Define

g : R> 0 โ†’ R> 0 , g(y) = | 5 y โˆ’ 1 |.

2

Then, for all x โˆˆ R> 0 , we have

(g โ—ฆ f )(x) = g(f (x)) = g

x + 1 5

x + 1 5

โˆ’ 1 = |x| = x,

since x > 0. Thus, g โ—ฆ f = idR> 0 , and so g is a left inverse of f. Important! We cannot define g by g(y) = 5y โˆ’ 1, since this does not always take values in the codomain R> 0. For example 5(0) โˆ’ 1 โˆˆ/ R> 0.

(d) Does f have a right inverse? If it does, give one and show that it is indeed a right inverse. Otherwise, justify why f does not have a right inverse.

Solution: No. A function has a right inverse if and only if it is surjective. Since f is not surjective, it does not have a right inverse.