Graphing and Identifying Symmetries of Quadratic Equations, Study notes of Pre-Calculus

Instructions and examples for graphing quadratic equations and identifying their symmetries with respect to the x-axis, y-axis, and origin. It includes exercises for determining the x- and y-intercepts of various equations and identifying which equations are symmetric with respect to different axes or the origin.

Typology: Study notes

2015/2016

Uploaded on 04/27/2016

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2.2 B 1
1.
Sketch the graph of the equation.
y = 2x โˆ’ 3
Submission Data
line: 2*x-3
Label the x- and y-intercepts. (If an answer does not exist, enter DNE.)
x-intercept
(x, y) =
y-intercept
(x, y) =
2.
Sketch the graph of the equation.
y = โˆ’x2 + 2
parabola: -x^2+2
Label the x- and y-intercepts. (If an answer does not exist, enter DNE.)
x-intercept
(x, y) =
(smaller x-value)
x-intercept
(x, y) =
(larger x-value)
y-intercept (x, y) =
Practice Another Version
pf3
pf4
pf5

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2.2 B 1

1. Sketch the graph of the equation. y = 2 x โˆ’ 3 Submission Data line: 2*x- Label the x - and y -intercepts. (If an answer does not exist, enter DNE.) x -intercept ( x , y ) = y -intercept ( x , y ) = 2. Sketch the graph of the equation. y = โˆ’ x^2 + 2 parabola: -x^2+ Label the x - and y -intercepts. (If an answer does not exist, enter DNE.) x -intercept ( x , y ) = (smaller x -value) x -intercept ( x , y ) = (larger x -value) y -intercept ( x , y ) = Practice Another Version

2.2 B 2

3. Sketch the graph of the equation. y = x^3 Label the x - and y -intercepts. (If an answer does not exist, enter DNE.) x -intercept ( x , y ) = Practice Another Version 1 10

2.2 B 4

Label the x - and y -intercepts. (If an answer does not exist, enter DNE.) x -intercept ( x , y ) = y -intercept ( x , y ) =

2.2 B 5

5. Use tests for symmetry to determine which graphs from the lists below are symmetric with respect to the y -axis, the x -axis, and the origin. (Select all that apply.) (a) symmetric with respect to the y -axis y = 8 x โˆ’ 3 y = โˆ’ x + 8 y = โˆ’8 x^2 y = 7 x^2 โˆ’ 2 x = 1/4 y^2 x = โˆ’ y^2 + 2 y = โˆ’1/9 x^3 y = x^3 โˆ’ 9

y = sqrt

y =sqrt(x) โˆ’ 6 (b) symmetric with respect to the x -axis y = 8 x โˆ’ 3 y = โˆ’ x + 8 y = โˆ’8 x^2 y = 7 x^2 โˆ’ 2 x = 1 4 y^2 x = โˆ’ y^2 + 2 y = โˆ’ 1 9 x^3 y = x^3 โˆ’ 9 y = x y = x x x

2.2 B 7

If x^2 = d , then x = ยฑ

d 81 x^2 = 64 x = 8. Solve the equation by using the following special quadratic equation. (Enter your answers as a comma- separated list. If there is no solution, enter NO SOLUTION.)

If x^2 = d , then x = ยฑ

d ( x โˆ’ 3 )^2 = 15 x = Practice Another Version Practice Another Version