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The solutions to quiz 3 of the linear algebra course math 205a,b, held in winter 2013. It includes the parametric form of the solutions to the homogeneous equation a⃗x = ⃗0, the determination of linear independence of the columns of matrix a, and the explanation of why the columns of a do not span r3.
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QUIZ 3
NAME: Section:(Circle one) A(1 : 10) B(2 : 40)
Show ALL your work CAREFULLY.
Let
A =
(a) Express the solutions to the homogeneous equation A~x = ~0 in parametric form. The coefficient matrix A can be reduced as follows.
The solutions to A~x = ~ 0 are
~x =
x 1 x 2 x 3
2 x 2 x 2 0
(^) = x 2
where x 2 is the parameter. (b) Based on your answer to (a), determine whether the columns of A are linearly independent? Justify your answer. The columns of A are NOT linearly independent since ~ 0 can be written as a non-trivial linear combinations of the columns ~a 1 , ~a 2 , ~a 3. For instance, ~0 = (2)~a 1 + (1)~a 2 + (0)~a 3 (take x 2 = 1). (c) Do the columns of A span R^3? Explain.
The columns of A do NOT span R^3. For any vector ~b =
b 1 b 2 b 3
(^) where b 3 6 = 0, the system
A~x = ~b does not have a solution because the row reduced echelon form of A has a row of zeroes and thus the system would be inconsistent.
Date: January 25, 2013. 1