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Integral calculus lectures powerpoint
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Review
functions
2
1 2 1 2 1 2
1
sin , 1
1
1
tan
1
1
sec , 1
1
d du
u u
dx dx u
d du
u
dx u dx
d du
u u
dx dx u u
. If a=1, you have:
sin u C
1 u
du 1
2
tan u C
1 u
du 1
2
u C
u u
du 1
2
sec
Identifying Patterns
which inverse trig function is
involved?
5
2
2
dx
x x
2
Try These
expression can be manipulated into
one of the patterns
7
2
dx
x
2
1 25
x dx
x
2
4 4 15
dx
x x
2
5
10 16
x
dx
x x
Completing the Square
functions are involved in the integration
2
the arctan function
2
Example : Evaluate the following integrals using
the formulas for integrals yielding inverse
trigonometric functions:
2
2 5
s
ds
2
2
x x
dx
2
x x
dx
16 9
2
y y
dy
1
2
x x
xdx
2 4 3
3
2
x x x
dx
2 2 3
3 1
2
x x
x dx
11
4
16 9
r
rdr
x
xdx
2
2 cos
sin
x x
dx
1
dx
x
x
2
2
4
1
dx
e
e
x
x
2
1
2
3 2
x x
xdx
d
2
1 sin
cos
2 4 3
2
2
3
x x
x dx
2
1 ln
x x
dx
9 1
2
x x
dx
1
0
2
2
t
dt
1
1 / 2
2
ln 3
ln 2
z z
e e
dz