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Integral calculus lectures powerpoint
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TOPIC
OBJECTIVES
. Note : The hyperbolic functions are defined in terms of the exponential functions. Its differentials may also be found by differentiating its equivalent exponential form. Similarly, the integrals of the hyperbolic functions can be derived by integrating the exponential form equivalent.
cosh x sinh x 1 2 2 1 tanh x sech x 2 2 coth x 1 csch x 2 2 sinh( xy)sinhxcoshycoshxsinh y cosh xy coshxcoshysinhxsinhy 1 tanhxtanhy tanhx tanh y tanh x y
1 tanxtany tanx tan y tan x y cos xy cosxcosysinxsiny sin x y sinxcosy cosxsiny
2 2
cos sin 1 2 2 x x
2 2
Identities: Hyperbolic Functions vs. Trigonometric Functions
Identities: Hyperbolic Functions vs. Trigonometric Functions sinh 2x = 2 sinh x cosh x sinh x cosh 2 x 1 / 2 2 cosh x cosh 2 x 1 / 2 2 x cosh x sinhx e x cosh x sinhx e
2 sin x 1 cos 2 x / 2 2 cos 2x = cos 2x – sin2x sin 2x = 2sinx cosx cosh 2x = cosh 2x +sinh2x
Example: Evaluate the following integrals:
dy cosh y a
2 tanh y
ln 3 0 2
3 2
csch xcoth xdx x 1
4 2
CLASSWORK