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Solution of Transcendental Equations, Solution of Transcendental Equations, Curve Fitting, Calculus of Finite Difference, Interpolation, Numerical Differentiation, Numerical Integration are main topics for this course. This assignment includes: Interpolation, Newton, Forward, Difference, Backward, Formula. Langrange, Divided, Polynomial, Error, Degree
Typology: Exercises
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Q -1. Find y(3.2) from the following data:
x : 0 1 2 3 4 5 y: 0 1 14 51 124 245 using: (a) Gregory – Newton Forward Difference interpolation Formula (b) Gregory – Newton Backward Difference interpolation Formula (c) Lagrange Interpolation Formula (d) Newton’s Divided Difference interpolation Formula
Comment on the accuracy of your results.
Q -2. Make Lagrange Polynomial for the data:
(xi , yi) = (-2, 0), (0, 2), (1, 0), (2, 4) and hence find: y (1.1), y (2.1), y (2.5) Comment on the error involved in these interpolated values
x : 0 1 4 5
Q -4. What is the degree of the interpolation polynomial for the data
(1, 5), (2, 18), (3, 37), (4, 62), (5, 93)
Q -5. The following table gives pressure of a steam at a given temperature. Using Newton’s formula, compute the pressure for a temperature of 142oC.
Temperature, oC 140 150 160 170 180 Pressure, kgf/cm^2 3.685 4.854 6.302 8.076 10.
Q -6. Find Newton’s backward interpolating polynomial for the following data: ________________________________________________ x 1 2 3 4 5 y 1 -1 1 -1 1
Q -7. A second degree polynomial passes through (0, 1) (1, 3) (2, 7) and (3, 13). Find the polynomial, using Newton’s forward difference formula.
Q -8. Find the interpolating polynomial for the function f ( x ) given by __________________________________________ x 0 1 2 5 y=f(x) 2 3 12 147
Q -9. Find the interpolating polynomial for the following data using Lagrange’s formula ___________________________________________________ x 1 2 - y =f(x) 3 -5 4
Q -10. Find the interpolating polynomial by (i) Newton’s divided difference formula (ii) Lagrange’s formula, for the following data and hence show that both the methods give raise to the same polynomial. ___________________________________________________ x 1 2 3 5 y 0 7 26 124
Q -1. 62.336 Q -2. x^3 -3 x + 2
Q -3. 3.04175 Q -4. 2
Q -5. 3.8988 Kg f / cm^2 Q -6. y (x) = 1 / 3 (2x^4 – 24x^3 + 100x^2 – 168x + 93)
Q -7. f (x) = x^2 +x + 1 Q -8. f (x)^3 + x^2 – x + 2
Q -9. y = - 1 / 30 (39x^2 + 123 x – 252) Q -10. x^3 – 1