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A 240v, 24a, Single-Phase Load Is Located 160 Ft From The Panelboard. The Load Is Wired With 10 Awg Conductors. What's The Approximate Voltage Drop Of The Branch-Circuit Conductors? A. 3.2v B. 4.25v C. 5.9v D. 9.5v ANS: D. 9.5v Vd = (2 X K X I X D)/Cmil K = 12.90, Copper I = 24a D = 160 Ft Cmil = 10, Vd = (2 Wires X 12.90 X 24a X 160 Ft)/10,380 Cmil Vd = 9.50v During Normal Operation Of A Typical 120-Volt Appliance Circuit, Current Flows Through The Hot, Grounding, And Neutral Conductors. A. True B. False
ANS: B. False An Rlc Series Circuit Has An Applied Voltage Of 240 Volts. R = 48 Ω, Xl = 100 Ω, Xc = 36 Ω, And Z = 80 Ω. What Is The Total Current? A. 1 A B. 2 A C. 3 A D. 4 A ANS: C. 3 A 240/80 = 3 What's The Direct-Current Resistance Of A 6 Awg Copper Conductor That's 400 Ft Long? A. 0.20 Ohms B. 0.30 Ohms C. 0.40 Ohms D. 0.50 Ohms ANS: A. 0.20 Ohms 6 Awg Resistance = 0.491 Ohms/1,000 Ft [Chapter 9, Table 8] (0.491 Ohms/1,000 Ft) X 400 Ft = 0.1964 Ohms
(4 X 1000) / (85 X 0.15) = 313.
An Inductor With An Inductance Of Three Henrys (H) Is To Be Connected To A 60 Hz Circuit. What Will The Inductive Reactance Be? A. 180 Ω B. 360 Ω C. 565 Ω D. 1131 Ω ANS: D. 1131 Ω Xl = 2 X 3.1416 X Frequency X Inductance 2 X 3.1416 X 60 X 3 = 1130.98 Ohms An Electric Motor Is Running On 120 V. The Current Is Measured To Be 2 A. How Many Ohms Of Resistance Is The Motor? A. 60 B. 118 C. 122 D. 240 ANS: A. 60 E / I = R
An Inductor Has An Inductive Reactance Of 12 Ω, And A Wire Resistance Of 16 Ω. What Is The Impedance Of The Inductor? A. 4 Ω B. 20 Ω C. 28 Ω D. 400 Ω ANS: B. 20 Ω Z = Square Root ( 16 Squared + 12 Squared) = 20 Ohms In An Inductive Circuit ____________________ Leads ______________________. A. Voltage, Current B. Current, Voltage C. Power, Resistance D. Resistance, Power ANS: A. Voltage, Current Eli The Ice Man Line Voltage And Phase Voltage Are The Same In The _____ Connection.
A Two-Branch Parallel Circuit Has A 30 Ω And A 15 Ω Resistor. What Is The Total Resistance? A. 2 Ω B. 10 Ω C. 45 Ω D. 15 Ω ANS: B. 10 Ω (1/30) + (1/15) = (1/0.1) = 10 Ohms A Wye-Delta Transformer Has A Primary Line Voltage Of 7200 V And A Secondary Line Voltage Of 480 V. What Is The Turns Ratio? A. 8.66: B. 9: 66 C. 10: D. 15: ANS: A. 8.66: Turns Ratio Must Be Calculated Using Phase Voltages. Wye Line Of 7200 V Is 7200 / 1.732 = 4,157.04 Phase Volts Delta Line Of 480 V Is 480 Phase Volts 4,157.04 / 480 = 8.
A Delta-Connected Set Of Windings Has A Phase Current Of 10 A. What Is The Line Current? A. 5.77 A B. 10 A C. 17.32 A D. 30 A ANS: C. 17.32 A Iline = Iphase X 1. A Transformer Has A 240 V Primary And A 120 V Secondary. With A 30 Ohm Load Connected, What Is The Primary Volt-Amps? A. 4 B. 8 C. 480 D. 960 ANS: C. 480 Volt-Amps Stay The Same From Winding To Winding 120 Volts / 30 Ohms = 4 Amps 120 V X 4 Amps = 480 Volt-Amps
In A Capacitive Circuit ____________________ Leads ______________________. A. Voltage, Current B. Current, Voltage C. Power, Resistance D. Resistance, Power ANS: B. Current, Voltage Eli The Ice Man Refer To The Diagram Above And Solve Using The Values Provided. R1 = 50 Ω, R2 = 200 Ω, And R3 = 600 Ω, And 600 V Is Applied Between A And B. What Is The Current Flow Through R3? A. 400 A B. 3 A C. 1.25 A D. 0.75 A ANS: D. 0.75 A Add R2 And R3 Ohms In Parallel, R2,3= 150 Ohms Add R1 And R2,3 In Series Rt= 200 Ohms Use 600v / 200 Ohms To Get Total Current Of 3a
Voltage At R1 Is 50 Ohms X 3a = 150 Volts Voltage At R2,3 Is Found By Removing E1 (150 Volts) From Et (600 Volts) =450 Volts Voltage Is The Same At Every Point In Parallel, So Divide E3 (450 Volts) By R3 (600 Ohms) =. Amps What's The Approximate Distance That A 240v, 31a, Single-Phase Load Can Be Located From The Panelboard So The Voltage Drop Doesn't Exceed Three Percent? The Load Is Wired With 8 Awg Copper. A. 55 Ft B. 110 Ft C. 145 Ft D. 220 Ft ANS: C. 145 Ft D = (Cmil X Vd)/(2 X K X I) Cmil = 16, Vd = 7.20v (240v X 0.03) K = 12. I = 31a D = (16,510 Cmil X 7.20v)/(2 X 12.90 X 31a) D = 118,872/ D = 148.60 Or Approximately 145 Ft What Is The Peak Voltage Of A 277 V Rms Ac Voltage?
B. 57.45 Amperes C. 67.34 Amperes D. 80.00 Amperes ANS: A. 45.28 Amperes 1 ÷ (2 X 3.14 X Frequency X Capacitance)1 ÷( 6.28 X 1,000 Hz X 30-μ Farads) = 5.3ω240 Volts ÷ 5.3ω = 45.28 Amperes What Is The Ampere Load Of A 140kva, 3-Phase, Load Operating At 480-V? A. 16. B. 292 C. 168 D.. ANS: C. 168 (140 X 1000) ÷ (480 X 1.732) = 168.4a
A 240/120-Volt Panel Has A Load Of 7,960 Watts Connected To Line One And 3,420 Watts Connected Toline Two. Assuming All Loads Are 120-V, What Is The Current Measured On The Grounded Conductor Of Thissystem? A. 45a B. 65a C. 19a D. 38a ANS: D. 38a 7,960w - 3,420w = 4,540w4.540 ÷ 120v = 37.83amperes A Florescent Lighting Bank In A Commercial Location Operates For 8-Hours Per Day. Each Fixture Hastwo Ballasts Rated At .8 Amps Each. How Many Lights Can Be Wired To A 20-Amp Circuit Breaker? A. 5 B. 8 C. 10 D. 12 ANS: C. 10 20a ÷ 1.25 = 16 A 0.8 X 2 (Ballasts Per Fixture) = 1.6 A 16a ÷ 1.6a = 10 Fixtures
To Measure Current A Meter Must Be Connected In _____. A. Combination B. Parallel C. Series D. Series Parallel ANS: C. Series A Kitchen Circuit Is Rated For 20 Amperes. What Is The Total Connected Load On This Circuit If A Toaster Rated At 550 Watts, A Coffee Pot Rated At 375 Watts, And A Toaster Oven Rated At 1,200 Watts Are Operating On The Circuit At The Same Time? A. 12.3 Amperes B. 14.7 Amperes C. 16 Amperes D. 17.7 Amperes ANS: D. 17.7 Amperes The Magnetic Field Strength Of An Electromagnet Can Be Increased By Completing Which Of The Following: A. Increase The Number Of Windings In The Coil B. Increase The Voltage
C. Put An Iron Core Inside The Coil Of Wire D. All Of The Above Will Increase The Magnetic Field ANS: D. All Of The Above Will Increase The Magnetic Field The Rate Of Current Flow Is Equal To Electromotive Force Divided By Resistance Represents A Value Of_____. A. Coulombs B. Impedance C. Voltage D. Power ANS: A. Coulombs An Old Ceiling Fan Is To Be Replaced With A New Ceiling Fan. The Old Ceiling Fan Is Rated At 120 Volts,80% Efficiency, With A ½ Hp Motor. The New Fan Is Rated At 120 Volts, 90% Efficiency, With A ½ Hp Motor. What Is The Power Savings Of The New Motor? A. 11% B. 20% C. 60% D. 80% ANS: A. 11% (.5hp X 746) ÷ (120 Volts X .8) = 3.88 Amperes(.5hp X 746) ÷ (120 Volts X .9) = 3.45 Amperes3. Amperes ÷ 3.88 Amperes X 100 = 89%100% - 89% = 11%
A Linear Load Heating Coil Operates At 24 Volts Using 6 Watts. If The Coil Is Connected To 48 Volts, Howmuch Power Will It Use? A. 12 W B. 24 W C. 36 W D. 48 W ANS: B. 24 W E2 ÷ P = Ohmse2 ÷ Ohms = Watts24 Volts2 ÷ 6 Watts = 96ω48 Volts2 ÷ 96ω = 24 Watts A Three-Phase Motor Is Running In The Clockwise Direction, How Is This Motor Direction Changed To Counter-Clockwise? A. Add A Capacitor To The Start Windings. B. Connect The Grounded Conductor To The Stator Pole C. Reverse Motor Leads T-1 & T-3 With Their Connected Line Conductors D. Increase The Voltage With A Step-Up Transformer ANS: C. Reverse Motor Leads T-1 & T-3 With Their Connected Line Conductors A 2kw Load Is Operated At 240-V And 80% Power-Factor. Find The Current Of This Load. A. 10.4 A B. 33a C. 25a
D. 3 A
ANS: A. 10.4 A
2,000w ÷ (240v X 0.8) = 10.4a What Is The Kva Of A Three-Phase Load Operating At 480 Volts And 168.4 Amperes? A. 81 Kva B. 140 Kva C. 280 Kva D. 162 Kva ANS: B. 140 Kva E X I X 1.73 ÷ 1000 = Kva480 Volts X 168.4 Amperes X 1.732 ÷ 1,000 = 139.84 Kva Calculate The Power Loss On The Conductors For On A 100-Ft., 120-V, Single-Phase, Branch Circuit Carrying 60 Amperes, Using 6 Awg, Thw, Copper Conductors. A. 115 Watts B. 354 Watts C. 487 Watts D. 600 Watts ANS: B. 354 Watts
