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and the ways it can be altered
different
aspects of
chemical reactions (fast reactions may proceed to agreat, lesser or a limited extent; same is true for slowreactions)
Equilibrium
is not
a stationary state or a
unidirectional process
Example:
If the rates of step 1 and step 2 are equal, [B]remains constant
not an equilibrium state
Equilibrium is a dynamic state
achieved by the
equalization of the forward and reverse rates of a reversible
(bidirectional)
process
Example:
If the rates of the forward and reverse reactions areequal, [A] and [B] remain constant
an
equilibrium state
At equilibrium
Rate
fwd
= Rate
rev
[A] = constant[B] = constant
oncentration C
Time
[A] [B]
Equilibrium
Rate
forward reverse
Equilibrium
Time
, the same equilibrium state is
reached even if the process is started fromdifferent starting points
Rate
fwd
= Rate
rev
2
4
(g; colorless)
2
(g; brown)
The reaction can be started from pure N
2
4
(g;
colorless) or from pure NO
2
(g; brown).
In both cases at equilibrium, the same light-browncolor is reached (the same proportion of N
2
4
and
2
is produced)
The reaction has a single step mechanism (theforward and reverse reactions are elementary), so atequilibrium: Rate
1
= Rate
-
k
1
2
4
k
-
2
2
4
2
2
2
1 1
−
→
K
is a constant which depends
on
T
(
K
= 0.211 at 100
°
C)
→
K
determines the proportion of
N
2
O
4
and NO
2
at equilibrium
17.2 The Equilibrium Constant and theReaction Quotient
The Law of Mass-Action •
Equilibrium constant
(
K
)
at equilibrium:^ a
A +
b
B
↔
c
C +
d
D
b
a
d
c
c
K
e
e
e
e
[B]
[A]
[D]
[C]
=
c
is the
equilibrium constant
in terms of
concentration (depends on
and the specific reaction)
e
e
e
, and [D]
e
are the
equilibrium
concentrations
of the reactants and products
a
b
c
, and
d
are the
stoichiometric coefficients
of
the reactants and products
Reaction quotient (
Q
)
action expression as
K
at any given time:^ a
A +
b
B
↔
c
C +
d
D
b
a
d
c
c
c
is the
reaction quotient
in terms of
concentration (
c
varies during the reaction)
[A], [B], [C], and [D] are the
current
concentrations
of the reactants and products at any
given time during the reaction
When the current concentrations become equal to the equilibrium concentrations,
c
c
⇒
At equilibrium
→
Q = K
Example:
Write the mass action expression
for the reaction:
2H
2
(g)
2
(g)
↔
2H
2
O
(g)
c
c
c
2
2
2
2
2
→
←
→
c
c
c
The mass-action expressions for
Q
and
K
depend on the form of the chemical equation
A
↔
B
or
B
↔
A
(or
) of the reverse reaction is the
reciprocal
of
(or
) of the forward reaction
1
2
c
n
c
n n
c
c
'^
A
↔
B
or
n
A
↔
n
B
Multiplying a reaction by a factor,
n
, raises
(or
) to
n
th
power
c
Q
2
1
(or
) of the sum of two or more reactions
is the
product
of their
s (or
s)