Historical Development of Particle Properties of Waves: From Newton to Quantum Mechanics, Study notes of Introduction to Philosophy

The historical development of the particle properties of waves, from newton's corpuscles to the modern concept of photons and quantum mechanics. It covers the wave-particle duality of light, planck's quantum theory of radiation, and the photoelectric effect. The document also explores the lorentz invariance of the phase of a photon and the particle properties of light.

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Lecture 4. Particle properties of waves
Outline:
Light: waves vs. particles
Photons
Photoelectric effect (demonstration
of the energy of photons)
Classical
physics
Relativistic
mechanics,
El.-Mag.
(1905)
Quantum
mechanics
(1920’s-)
Relativistic
quantum
mechanics
(1927-)
v/c
h/s
S the action=momentum×distance,
units g×cm2/s
pf3
pf4
pf5
pf8
pf9
pfa
pfd
pfe

Partial preview of the text

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Lecture 4. Particle properties of waves

Outline: •^ Light: waves vs. particles•^ Photons•^ Photoelectric effect (demonstration

of the energy of

photons)

Relativisticmechanics,El.-Mag.(1905)^ Classicalphysics

Relativisticquantummechanics(1927-)^ Quantummechanics(1920’s-)

v / c

h / s S^ – the action=momentum

×distance, units g×

(^2) cm/s

Historical development

Newton

( Opticks

, 1704): light as a stream of particles (corpuscles). Descartes

(1637),

Huygens

,^ Young

,^ Fresnel

(1821),

Maxwell

: by mid-

th^ century, the

wave nature of light was firmly established (

interference

and^ diffraction

, transverse nature

of e.-m. waves). Physics of the 19

th^ century: mostly investigation of light waves; physics of the 20

th^ century –

interaction of light with matter. One of the challenges – understanding the “blackbody spectrum” of thermal radiation (to beconsidered later in the course). Planck

(1900)

suggested

a^ solution

based

a^ revolutionary

new^

idea:^ emission

and

absorption of electromagnetic radiation by matter has quantum nature: the energy of aquantum of e.-m. radiation emitted or absorbed by a harmonic oscillator with the frequency

f

is given by the famous Planck’s formula^ E

h^ f =^

where^ h^ is the Planck’s constant

34

6.^

h^

− J^ s

≈^

×^

E^ ω=^ h^

where^

34

1.^

10 J

−^ s

≈^

×^

h

2 f ω π=

Also, in terms of theangular frequency

h =h 2 π

  • at odds with the “classical” tradition, where energy was always associated with amplitude,not frequency

Waves

Wave equation in one dimensionfor any quantity

ψ:

2

(^22) 2 v^2 t^

x ψ

ψ ∂^

∂= ∂^

(^ )

Solution:

a^ plane

wave

traveling

in^ the

negative (positive) direction

x^ with velocity

v :^

f^ x^ vt ψ = ±

x

t^ = 0^

t^ =^ t^0 vt^0

(^ ) Harmonic plane wave traveling in the positive direction

x : (^

)

sin^

sin^2

sin x^ t

A^ x

vt^

A^

A^ kx

t T

ψ

π

ω

⎡^ λ

⎤ ⎛^

=^

−^ =^

−^ =

⎜^

⎟ ⎢^

⎥ ⎝^

⎠ ⎣^

phase^

x^ vt ≡ −^

constant phase

/

x^ vt^

const^

v^ x^ t

→^ −^

=^

→^ =

v^ –^ the phase velocity

x λ ψ A^0 -A^0

2 2

f π ω^ π= =^ T

2 π k = λ

ω v = k

Electromagnetic waves: (transverse in free space)^2

2

(^22) 2

2

2 (^1) E E 0 0

Ec

t^

x^

x

∂^ ∂^ ε μ

∂ =^

= ∂^

∂^

∂ 2

2

(^22) 2

2

2 (^1) B B 0 0

Bc

t^

x^

x

∂^ ∂^ ε μ

∂ =^

= ∂^

∂^

r , E^ x t^ (^ ) r , B x t ( )

angularfrequency

wavenumber

t T ψ A^0 -A^0^ (^

)^ (^ ) ,^

E^ x t^

cB x t =

Photons

According to the quantum theory of radiation, photons are

massless

bosons of spin

^1 (in units

ħ ). They move with the speed of light :

ph ph^

ph

E^

h^ f

E^

= cp =

“Light” – a shorthand notation for any e.-m. radiation (

ν^ from 0 to

∞).

(^ )^

(^ )^

(^ )

2 2

2

2 0

ph^

ph^

ph E^

cp^

m^ c −^

=^

=

Quantum character of this equation is illustrated by the fact that theenergy is associated with the

frequency

of oscillations rather than

their^ amplitude

. Particle properties of light

Wave properties of light E^ r^^ ph^ , i p^ phc

r^ ω , i k c

  • both the time-like and space-likecomponents of these 4-vectors shouldtransform under L.Tr. in a similar way

Thus, if Planck’s idea

E=ħ^ ω^

is correct, than we must conclude that

p^ ph

r k = r^ h

The phase

is a^ Lorentz-invariant quantity

,

t^ the (scalar) product of two 4-vectors:

rr^ kr ω −

(^

r , ict r ) ω , i k c

⎛^

⎞ ⎜^

⎟ ⎝^

r^ ⎠

rr t kr ω − ph

h

p^

k = =h^ λ

Photoelectric Effect

Historical Note

:^ The photoelectric effect was accidentally discovered by

Heinrich Hertz

in 1887 during the course of the experiment that discovered radio waves. Hertz died (atage 36) before the first Nobel Prize was awarded.Observation: when a negatively charged body was illuminated with UV light, its chargewas diminished. J.J. Thomson and P. Lenard

determined the ration

e/m^ for the particles emitted by the

body under illumination – the same as for electrons.The^ effect

remained

unexplained

until^

1905 when

Albert

Einstein

postulated

the

existence of quanta of light -- photons -- which, when absorbed by an electron near thesurface of a material, could give the electron enough energy to escape from the material. Robert Milliken

carried out a careful set of experiments, extending over ten years, that verified the predictions of Einstein’s photon theory of light.

Einstein was awarded the

1921 Nobel Prize in physics: "For his services to Theoretical Physics, and especially forhis discovery of the law of the photoelectric effect."

Milliken received the Prize in 1923

for his work on the elementary charge of electricity (the oil drop experiment) and on thephotoelectric effect.

Photoelectric Effect (cont’d)

Observations

:

1.^ For a given material of the cathode, the “stopping”voltage does not depend on the light intensity.2.^ The saturation current is proportional to the intensityof light at

f^ =const.

3.^ Material-specific “red boundary”

f exists: no^0

photocurrent at

f^ <^ f^0.

4.^ Practically instantaneous response – no delaybetween the light pulse and the photocurrent pulse(many applications are based on this property) V

retarding

I

intensity of lightincreases,

f^ =const^ V I^ intensity = const,

f^ increases

stoppingvoltage

light I

- e _+^ V^

f

stopping voltage

cesium

calcium

Parameters

: intensity (

S ) and frequency (

f ) of light,

applied voltage (

V ), measured photocurrent (

I )

“redboundary”

f^0

V^0 V ( f )^0

V ( f )^0 1 f > f 2 1

Photon-based explanation of Ph. E.

Absorption of a photon by an electron in metal(inelastic collision between these particles)

energy conservation

2

2 e^

ph^ e m c^

E^ m c

γ^

+^ =

the rest RF of an electronafter the collision

(^0) Eph γ^ =^

before^

(^2) m c K + e after (^2) m c e hf

However, we’ve concluded that a

free^ electron

cannot

absorb a photon!

before^

after (^2) m c K +^ e

(^2) m c e

hf What’s wrong? The electron is not “free”, it is embedded in metal, and the chunk of metal is

the second body that participates in the collision 2

2

2

2

ph^ e

met^

e^

e^ met

met

E^ m c

M^

c^ m c

K^

M^ c^

K

+^

+^

=^

+^ +

  • momentum conservation

ph^ e met p^ p

p = + r^ r

r^ met^

e M^

m >>> Thus, while the electron isstill

inside

metal

~ ph^

e^ met p^

p^ p <<

~^

e met^ e

m met v^ v

M

2 met^ ~ 2

e^

e

met^

e^

e^

e

met^

met M^

m^

m

K^

v^

K^

K

M^

M

⎛^

⎞^ =^

⎜^

⎝^

energy conservation E^ K = ph^ e

momentum conservation

(see Slide 6) The photon energy is absorbed by an electron (the energy absorbed by metal is negligibly small),but the momentum exchange between electron and metal is crucial for momentum conservation.

ph^ e met p^ p

p = + r^ r

r

Photon-based explanation of Ph. E. (cont’d)

In the experiment, the electron is observed

outside

the metal. It takes some energy to escape:

(consider an attraction between an electron and the positive

“image” charge induced on the metal surface)

metal

- q +q

The “escape” energy:

the work function W

(material-specific)

Thus, for the electron^ outside

metal^

K^ E^ e^ ph

W

=^ −

K^ f^ h^ (^ ) e

f^ W = −

0 (^0) K hfe

W

=^ →^

“red” boundary of Ph. E.

(^ )^

(^

) 0 K^ f^ e

h^ f^

f =^

f^0

Planck’s constantmeasurements:

(^ )^

(^ ) 0 0

0 K^ f^ e

eV^ f h^ f^

f^ f

f =^

W −

Problems

1.^ The work function of tungsten surface is 5.4eV. When the surface is illuminated by lightof wavelength 175nm, the maximum photoelectron energy is 1.7eV. Find Planck’s constantfrom these data.^ e

c K^ hf

W^

h^ W^ λ

=^ −^

=^ −

(^

)^ (

)^

7

15

8 15

19

34

1.^

5.^

1.75^10

1.6^10

/^

6.6^10

K^ W^ e

eV^

eV^

m

h^

eV^ s

c^

m^ s eV^ s^

J^ eV^

J^ s

λ^

−^

−^

+^

+^

×^ ×

=^

=^

=^ ×

×

=^ ×

⋅^ ×^

×^

=^ ×

2.^ The threshold wavelength for emission of electrons from a given metal surface is 380nm.(a) what will be the max kinetic energy of ejected electrons when

λ^ is changed to 240nm?

(b) what is the maximum electron speed?(c) the loss of electrons due to the photoelectric effect will cause an isolated sphere of thismetal to acquire a positive charge. Find the largest electric potential (in Volts) that couldbe achieved by this sphere for

λ^ = 240nm.

ch W = λ^0

1

1 0

c e

c^ c

K^ h

W

h^

h^

hc^

eV

λ^ λ

⎛^ λ^ λ

=^

−^ =^

−^

=^

−^ =⎜ ⎟ ⎝ ⎠

(a)^2

5 2 / 2^

8.2^10

e

e^ e

K e

K^ m v

v^

m^ s m

=^

=^

=^ ×

(b)^

(c)

K^ f^ (^ ) e h f^

W metal^

E vacuum

electronenergy in the(repulsive)electric field

Ke^ 1. hf^ W

hf^ W

eV^

V^

V

e^

e

=^ +^

→^

=^

=^ =

Inverse Photoelectric Effect (production of X-rays)X-rays:^

16

19

0.01^10

0.1^100 ph

nm^

f^

Hz^

E^

keV

λ =^

−^

=^ ×^

−^ ×^

≈^ −

Production:

The upper “cut-off” of the spectrum correspondsto^ the^

full^ conversion

of^ the

electron

kinetic

energy into the photon energy. 2 (^ )

max

min

e^ e c hf^

h^

eV^ K

m c

=^ =^ λ

=^ =

34

8

11

min^

19

5

6.6^10

/^ 1.

0.12A

1.6^10

hc^

J^ s^

m^ s^

m

eV^

C^

V

− ×^

⋅^ ×^ ×

=^ =

=^ ×

×^

× ×

o^

[^ ] [ ] 12.4min nmV kV

λ^ =

λ

γ-rays

UV X -rays 0.01 nm^^10

nm