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This is a problem set for math 110: linear algebra, consisting of 10 problems distributed in three parts. The problems cover various topics such as vector spaces, linear independence, and cross products. Part 2 includes a non-collaborative problem. Part 3 contains optional problems. The deadline for submission is friday, september 3.
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Problem Set 1 (due Friday September 3) MATH 110: Linear Algebra
PART 1 The following problems are each worth 5 points..
PART 2 Remember that the starred problem is non collaborative. Problem 1 (5) Let V = R+, the set of positive real numbers. Define the “sum” of two elements x, y in V to be their product xy (in the usual sense), and define “multiplication of an element x in V by a scalar c to be xc. Prove that V is a real linear space with 1 as the zero element. Problem 2 (10) Let V be the vector space of all real valued functions defined on the real line (F (R)). Consider the n exponential functions:
u 1 (x) = ea^1 x,... , un(x) = eanx
where a 1 , a 2 ,... , an are distinct real numbers. Show that these n functions are independent. Problem 3 ∗(5) Curtis p. 26 10. In order to do this problem you will have to read some definitions and theo- rems in Curtis (3.7, 3.9, 3.10 and 3.11). Problem 4 (15) Let V be a finite dimensional vector space and let S be a subspace of V. Prove each of the following statements:
a) S is finite dimensional and dim S ≤ dim V. b) dim S = dim V if and only if S = V. c) Every basis for S is part of a basis for V. d) A basis for V need not contain a basis for S. e) Is the union of two subspaces always a subspace? Explain.
PART 3 - Optional Problems
where A =< a 1 , a 2 , a 3 > and B =< b 1 , b 2 , b 3 >. Let i, j, k be the unit coordinate vectors in R 3. Notice that the cross product is not associative. For example,
i × (i × j) = i × k = −j but (i × i) × j = 0 × j = 0.
Thus, given k vectors v 1 , v 2 ,... , vk in R 3 , in order to make the expression
v 1 × v 2 × · · · × vk
well defined, it is necessary to insert parentheses to indicate the order of eval- uation. We will define an association to be an insertion of k − 2 parentheses so that the order of evaluation is determined. For example,
(v 1 × v 2 ) × (v 3 × v 4 ) and ((v 1 × v 2 ) × v 3 ) × v 4
are two different associations. Prove that if two associations of v 1 × v 2 × · · · × vk are given, there exists an assignment of i, j, k to v 1 , v 2 ,... , vk such that when evaluated with the assignment, the two associations are equal and nonzero (this means that you cannot set v 1 = v 2 = · · · = vk).