Linear Operators - Lecture Notes - Robust Control Systems I | MEM 633, Study notes of Mechanical Engineering

Material Type: Notes; Class: Robust Control Systems I; Subject: Mechanical Engr & Mechanics; University: Drexel University; Term: Spring 2001;

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MEM633 Lectures 4&5
2-3 Linear Operators
Def: function
Let X and Y be arbitrary nonempty sets and let D
be a nonempty subset of X. A function f from D
into Y is a rule that to each x in D assigns a
unique element f(x) in Y.
Def: domain, range
The domain of f is the set D on which the function
f is defined, often written as D(f). The range of f
is the set R(f) = {f(x) : x in D }.
Def: linear operator
X, Y are linear spaces over F. A function
T
is
said to be a linear operator if and only if
T
(c1x1 + c2x2 ) = c1
T
x1 + c2
T
x2
for any vectors x1, x2 in X and any scalars c1 , c2
in F.
Example:
Consider the operator that rotates a vector in a
geometric plane counterclockwise 90° with respect
to the origin.
y
x
x1
x2
x3
This operator is a linear operator. (Why?)
Matrix Representation of a
Linear Operator
X and Y are n- and m-dimensional vector spaces
over the same field F. Let {x1, x2, ..., xn } be a basis
for X and {y1, y2, ..., ym} a basis for Y. Suppose the
linear operator
T
: X Y is defined by
Tx i= a1iy1+ a2iy2 + ... + ami ym i=1,2,...,n
where a1i , a2i , ... ,ami are scalars in F.
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13

MEM633 Lectures 4&5 2-3 Linear Operators Def

:^ functionLet^ X

and

Y^

be arbitrary nonempty sets and let

D

be a nonempty subset of

X

.^ A function

f^

from

D

into

Y

is a rule that to each

x^

in^

D^

assigns a

unique element

f(x)

in

Y.

Def

: domain, rangeThe domain of

f^

is the set

D^

on which the function

f^ is defined, often written as

D

(f). The range of

f

is the set

R (f)

f(x)

:^ x

in

D^

Def

: linear operator X ,^ Y

are linear spaces over

F. A function

T^

is

said to be a linear operator if and only if

T^

( c^1

(^1) x + c

(^2) x 2

c^1

T^ x

1 + c

^ T^ 2

(^2) x

for any vectors

(^1) x ,^ x

2

in^

X^

and any scalars

c^1

, c

2

in^ F

Example

Consider

the

operator

that

rotates

a

vector

in

a

geometric plane counterclockwise 90° with respectto the origin.

y

x (^1) x (^2) x

(^3) x

This operator is a linear operator. (Why?) Matrix Representation of aLinear Operator

X^ and

Y^

are

n - and

m

-dimensional vector spaces

over the same field

F. Let {

(^1) x, x

, x

n^ } be a basis

for

X^

and {

(^1) y, y

, y

m } a basis for

Y. Suppose the

linear operator T^ :

X^

Y

is defined by

Tx

i^ = a

y 1i 1 + a

y 2i

+ a

mi^

m y

i=1,2,...,n

where

a

1i^

,^ a

2i^

,a

mi^

are

scalars

in

F

15

Then the operator

T^

can be represented by a matrix

A^ :

T^ :

x

a^

y = Ax

with

A

= [

aij

] ,

i=1,2,...,m; j=1,2,...,n.

Example: Consider

the

rotation

operator

in

the

previous

example again. If we choose {

(^1) x, x

2 } as the basis of

both

X

and

Y

, then the matrix representation of

T

is

0

1 1

−^0 ⎡^

⎤ ⎢^

⎥ ⎣^

If we choose {

(^1) x , x

2 } as the basis of

X

and the

basis {

(^2) x , x

3 } of

Y , then the matrix representation of

T^

is

1

0 0

1 ⎡^

⎤ ⎢^

⎥ ⎣^

2-4 Linear Algebraic Equations

Consider the set of linear equations

a^11

x^1

+ a

x 12

+ a

x1n = yn^

1

a^21

x^1

+ a

x 22

+ ... + a 2

x2n

= yn^

2

:^

Am

x^1

+ a

m

x^2

+ ... + a

mn

x^ n^

= y

m

where the given

aij

's and

yi

's are assumed to be

elements of a field

F , the unknown

x^ j

' s

are also

required to be in the same field.

This set of equations can be written in matrix form as

Ax = y

where

A^

is an

mxn

matrix [

aij^

],^ x

is an

nx

vector

and

y^

is an

mx

vector. We can consider the matrix

A^ as a linear operator which maps

n F into

m F

19

Def:

null space The null space of a linear operator

A

is the set

N (

A )^

defined by^ N

( A

)^ = {

x

in

n F :^ Ax=

i.e.,

N

( A

)^ is the set of all solutions of

Ax=

Example:

Consider the matrix

A

⎡^

⎢^

=^ ⎢

⎢^

⎣^

which maps

(^5) into

(^3)

. Let

x^

= [

x^1

x^2

... x

´ ] 5

, then

Ax

= x

a 1

1 + x

(^2) a _2

  • x_

(^3) a _3

  • x_

a 4

4 + x

(^5) a 5

= x

a 1

1 + x

a 2

2 + x

( a 3

1 + a

+ x

( a 4

(^2) a ) + x

( a 5

(^2) a )

= (x

+x 1

+x^3

+x 4

)^5

(^1) a + (x

+x 2

+2x 3

+3x 4

)^ a 5

2

The

vectors

a

1 and

a

2 are

linearly

independent,

hence

Ax = 0

if and only if x+x 1

+x^3

+x 4

x+x^2

+2x^3

+3x 4

It is clear that the set of the three vectors

-1 -1^100

-1 -2^010

,^

and

-1 -3^001

form a basis of

N

( A )

Theorem:^ Let

A^

be an

mxn

matrix, then

dim

R (

A )^

  • dim

N

( A

)^ =

n.

21

2-5 Eigenvalues and EigenvectorsDef

: eigenvalue and eigenvectorLet^ A

be a linear operator that maps

n into itself

and

x^

a vector in

n

. Then

x^

is an eigenvector of

A^ corresponding to the eigenvalue

λ^

if^ x

≠^0

and

Ax

=^ λ

x. To find an eigenvalue of

A , we write

Ax=

λ x^

as

(^ A

-^ λΙ

)^ x

=^

This equation has a nontrivial solution if and only ifdet

( A -

= 0. det

( A -

is a polynomial of degree

n

in^ λ

and is called the characteristic polynomial of

A.

Example:

A^

⎡^

=^ ⎢

The eigenvalues of

A

are

λ^1

= 2 and

λ^2

= 4 and

their corresponding eigenvectors are

(^1) x

= [ 1

1 ]´

and

x

2 = [1 -1 ]´.

Example:

Suppose

that

an

nxn

matrix

A

has

n

linearly

independent eigenvectors

(^1) x , x

, x

n^

correspond-

ing to eigenvalues

λ ,^1

λ^2

λ n^

. Then any vector

y

can be written in the form

y^ = a

(^1) x _1

  • a_

(^2) x 2

+ a

x n n

where [

a^1

a^2

an^

´ ]is called the representation of

y

with respect to the basis {

(^1) x ,^ x

,^ x

n^ }. From the

fact that

A x

i =

λ i^

i x

it follows that^ A

k y^

λ^1

k^ ) a

(^1) x 1

λ^2

k^ ) a

(^2) x 2

λ n^

k^ ) a

n x n

If^

|^ λ^1

|^ > |

λ i^

|,^ i

2,3,...,n

and

a^1

then

k A y

will tend to lie along the vector

(^1) x when

k^

is large.

25

Def:

operator norm The norm of a linear operator

A^

is defined as

0

1

:^ sup

sup

x^

x Ax

A^

Ax

x ≠^

=

=^

where "sup" stands for supremum, the least upperbound.The operator norm

A^

is defined through the

vector norm

x

.^

Therefore, for different

x^ , we

have different

A

Theorem:

Let

A^

be an

mxn

matrix. Then

1

1 max(

|^

m

ij

j^

i

A^

a

=^

and

1 max(

|^

n

ij

i^

j

A^

a

∞^

=

=^

Theorem:^ Let

A^

be in

mxn

and the maximum eigenvalue of

* A

A^

is

. Then A^2

Def:

inner product The inner product of

x^

and

y^

in^

X^

is a function of

x^

and

y , denoted by

< x

, y^

> , which satisfies the

following axioms:(1)

,^

x^ y

y x

<^

>^.

,^

,^

x^

y z

x z

y z

<^

+^

>^.

,^

cx y

c^

x y

<^

>^ for all scalars

c.

,^

x^ x <

and

,^

x^ x <

if^

x^ ≠

.

Example:

In^

n , the inner product is defined as

1

n

i^ i i

x y

x y

x y =

<^

=^ ∑

27

Theorem:

(Cauchy-Schwarz Inequality)

1/ 2^

1/ 2

,^

,^

x y

x x

y y

<^

>^

<^

The equality holds if and only if

x^

and

y

are

linearly dependent. Theorem:

, x x <^

>^

has the property of a norm.

Normed Linear Spaces and Inner-Product Spaces

Def

:^

normed linear spaces A linear space on which a norm is defined is calleda normed linear space. Example

The space

n equipped with the norm

||^ x

||^ p

= ( |x

p | (^1)

  • |x

p | n 1/p)

≥p

is a normed linear space. The space is denoted by^ ( ) p^

n l^

Example

:^

l^ spaces p

Let

≤^

p <

. The space

l^ p

consists of all infinite

sequences of scalars { x

, x

..... , n

} such that

|^1

p | i i

x ∞ =

The norm in

l^ is defined by p

1/ 1 :^

|^

p pi

p^

i x^

x ∞ ⎧ =

=^ ⎨

⎩^

The space

l^ ∞

is defined to consist of the bounded

sequences { x

, x^ n

}, with the norm

:^ sup |

| i i x^

x =∞

31

Def

:^ orthogonal complementTwo

vectors

x

,^

y^

in^

a^

Hilbert

space

X

are

orthogonal if

x

,^ y

If^

M^

is a closed

subspace

of

X

,^

then

⊥ M

,^

the

orthogonal

complement of

M

, is the set of all vectors in

X

which are orthogonal to every vector in

M

. That is,

⊥ =^

X^

M^

M

Time-domain and Frequency-domainSpaces

Time-domain spaces

L^2

Consider a signal vector

x (t) = [ x

(t) x 1

(t) 2

x^ (t) ]n

where x

(t), i = 1,2,i^

...n, is a complex-valued function

defined for all time, -

∞^

< t <

. Assume that the

signals under consideration satisfy

2 1

n

i i

x t

dt

= −∞

∑∫

The

space

of

all

such

signals

is

denoted

by

( L^2

n)(-

∞), or simply by

L^2

). This space is

a Hilbert space with inner-product

,^

( )^

x^ y

x t^

y t dt ∞ −∞

<^

Then the norm of x is

1/ 2 2

2

1

n

i i

x^

x t

dt

=^ ⎜

⎝^

∑∫

Frequency-domain space

L^2

Consider a function

[^

]

1

2

(^

)^

(^

)^

(^

)^

...^

(^

T )

n

x j

x^

j^

x^

j^

x^

j

ω^

Where

(^

x^ j^ ω i

,^

i^ =

...n,

is

a

complex-valued

function defined for all frequencies, -

∞^

<^

ω^

<^

33

Assume

that

the

functions

under

consideration

satisfy

2

1

(^

n

i i

x^

j^

d

ω^

∞ =−∞

The

space

of

all

such

functions

is

denoted

by

( L^2

n ) , or simply by

L^2

. This space is a Hilbert space

with inner-product

1

,^

(^

)^

(^

x^ y

x j

y j

d

ω^

ω^

ω

∞ π−∞

<^

The norm on

L

is 2

1/ 2 2

2

1 1

(^

n

i i

x^

x^

j^

d

ω^

= −∞ ⎛^

=^ ⎜

⎝^

RL

space

the set of rational functions in

L^2

with real coeffi-

cients.

These

functions

are

strictly

proper

and

have no poles on the imaginary axis. ( H )^2

n , H

space 2

a^

closed

subspace

of

L

with

functions

x(s)

analytic in Re(s) > 0.

H^2

⊥^

space

the orthogonal complement of

H

in^

L^2

( L ∞

nxm)

, L

∞^

space

the space of nxm complex-valued matrix functionswhose

largest

singular

values

are

essentially

bounded. The

L

-norm of a matrix function∞

Φ(s)

in^

L ∞

is

[^

]

:^

sup

(^

ess

j

∞ Φ^

=^

RL

∞^

space

Φ(s)

RL

∞^

iff^

Φ(s) is proper rational with real

coefficients and has no poles on the imaginaryaxis. ( H

nxm)

, H

∞^

space

a^

closed

subspace

of

L

∞^

with

functions

(s)

analytic in Re(s) > 0. RH

space

the set of proper stable rational matrices with realcoefficients.