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Making Solutions Worksheet, Study notes of Chemistry

Universiteit Antwerpen, UFSIAChemistry

1). Explain how you would make 750. mL of a 1.35 M KOH solution. 2). If you dilute 15.0 mL of a 12.0 M HCl solution to make a 2.50 M ...

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Making Solutions Worksheet
W 330
Evere tt Community College
Student Support S ervice s Pro gram
1) Explain how you would make 750. mL of a 1.35 M KOH solution.
2) If you dilute 15.0 mL of a 12.0 M HCl solution to make a 2.50 M HCl solution what will
the final volume be?
3) How many grams of magnesium bromide are needed to make 1.0 L of a 4.0 M
magnesium bromide solution?
4) Why is the following procedure is incorrect: To make 1.00 L of a 1.00 M CaCl2 solution,
dissolve 111 grams of calcium chloride in 1.00 L of water.
pf2

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Making Solutions Worksheet

W 330

Everett Community College Student Support Services Program

  1. Explain how you would make 750. mL of a 1.35 M KOH solution.

  2. If you dilute 15.0 mL of a 12.0 M HCl solution to make a 2.50 M HCl solution what will the final volume be?

  3. How many grams of magnesium bromide are needed to make 1.0 L of a 4.0 M magnesium bromide solution?

  4. Why is the following procedure is incorrect: To make 1.00 L of a 1.00 M CaCl 2 solution, dissolve 111 grams of calcium chloride in 1.00 L of water.

Solutions

  1. Explain how you would make 750. mL of a 1.35 M KOH solution.

0.750 L KOH x 1.35 mole KOH x 59 g KOH = 56.7 g KOH 1 L KOH 1 mole KOH Measure 56.7 g KOH into a container and add water to 750 mL volume.

  1. If you dilute 15.0 mL of a 12.0 M HCl solution to make a 2.50 M HCl solution what will the final volume be?

(12.0 M)(15.0 mL) = (2.50 M) V 2 V 2 = (12.0 M)(15.0 mL) = 72.0 mL (2.50 M)

  1. How many grams of magnesium bromide are needed to make 1.0 L of a 4.0 M magnesium bromide solution? 1.0 L MgBr 2 x 4.0 mole MgBr 2 x 184.3 g MgBr 2 = 737.2 g MgBr 2 1 L MgBr 2 1 mole MgBr 2

  2. Why is the following procedure is incorrect: To make 1.00 L of a 1.00 M CaCl 2 solution, dissolve 111 grams of calcium chloride in 1.00 L of water.

Making a solution this way would result in a final volume greater than 1.00 L because the calcium chloride has volume too. The proper method would be to measure 111 g CaCl 2 into a container, then add water to 1.00 L volume.