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Newton's third law of motion, also known as the conservation of momentum, in the context of systems with multiple particles. How to calculate the forces between particles, potential energies, and total energies, and shows how conservation of momentum and energy can be derived from newton's second law. The document also includes homework problems to test understanding.
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Today we are going to talk about conservation of momentum. This is a modern name for New- ton’s 3rd^ law. We haven’t discussed this law yet. It says:
All forces occur in pairs and these two forces are equal in magnitude and opposite in direction.
picture of Earth and apple with f orces acting on eachother
To understand this idea, we must consider systems with more than one particle — say n particles in R^3 with positions qi: R → R^3 , (i = 1,... , n). Suppose the jth^ particle exerts some force on the ith^ particle (i 6 = j), Fij (t). Newton’s 3rd^ law says
Fij (t) = − Fji (t).
We will go further and assume our forces are central:
picture of arrows pointing along same line notalong distinct lines
(to get conservation of angular momentum). More precisely:
Fij (t) = fij (| qi(t) − qj (t) |)
qi(t) − qj (t) || qi(t) − qj (t) ||)
where fij : (0, ∞) → R. (Note the force is undefined when the particles collide!) Then Newton’s 3rd law says fji = fji , (i 6 = j).
As for a single particle, we can define potentials Vij : (0, ∞) → R with
V (^) ij′ = − fij.
For example:
Vij (r) = −
∫ (^) r
c
fij (s)ds
for some fixed c. Note: Vij = Vji
so “the potential energy of the ith^ particle due to the jth^ particle equals the potential energy of the jth^ particle due to the ith^ particle.” We define the total potential energy of the ith^ particle:
Vi(t) =
j 6 =i
Vij (| qi(t) − qj (t) |)
and the total potential energy
V (t) =
∑^ n
i=
Vi(t)
Similarly, we have the total kinetic energy
T (t) =
∑^ n
i=
mi q˙i(t)^2.
These add up to give the total energy
E(t) = T (t) + V (t)
This will be conserved if the particles move according to Newton’s 2nd^ law:
Fi(t) = mi q¨i(t), (i = 1, ·, n)
where m > 0 is the mass of the ith^ particle and the force on the ith^ particle is
Fi(t) =
j 6 =i
Fij (t)
where Fij is given as before.
Homework 1: Show that if Newton’s 2nd^ law (Fi(t) = mi q¨i(t)) holds then energy is conserved:
d dt E(t) = 0.
More interestingly, Newton’s 3rd^ law (Fij = Fji ) gives conservation of momentum. The momentum of the ith^ particle is: pi(t) = mi q˙i(t)
and the total momentum is:
p(t) =
∑^ n
i=
pi(t).
This is conserved:
d dt
p(t) =
∑^ n
i=
d dt
pi(t) (1)
∑^ n
i=
mi q¨i(t) (2)
∑^ n
i=
Fi(t) (3)
∑^ n
i=
j 6 =i
Fij (t) (4)
since Fij (t) = −Fji (t). We also have a third conservation law: conservation of angular momentum. The angular momentum of the ith^ particle is
Ji(t) = miqi(t) × q˙i(t).
(If the particle and its velocity are in the xy plane then Ji(t) points along the z direction and its z component is mr(t)^2 θ˙(t).) The total angular momentum is:
J(t) =
∑^ n
i=
Ji(t)