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An introduction to matrix algebra, focusing on matrices, their multiplication, and determinants. It includes examples and exercises on calculating matrix products and determinants. Suitable for students in physics or engineering courses, such as physics 351: foundations of physics ii.
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Raghuveer Parthasarathy Department of Physics, University of Oregon for Physics 351: Foundations of Physics II (Dated: November 5, 2007)
We’ll very briefly explain a few aspects of linear alge- bra. This discussion is sufficient for the problems encoun- tered in your homework assignments. To learn more, see any linear algebra textbook, e.g. Howard Anton, Elementary Linear Algebra (7th Ed.), John Wiley and Sons, New York, 1994.
I. MATRICES
A matrix is a rectangular array of numbers. The ma- trix A, below, is a 3 × 3 matrix, with elements aij , where the indices i and j run from 1 to 3:
a 11 a 12 a 13 a 21 a 22 a 23 a 31 a 32 a 33
The matrix B, below, is a 3 × 1 matrix:
B =
b 11 b 21 b 31
The product AB is C, also a 3×1 matrix. The elements ci 1 of C are given by
ci 1 =
j=
aij bj 1 ,
where Σ indicates a sum. In other words, each element of C is the sum of the products of a row of A with a column of B. (Here, B only has one column.)
C = AB =
a 11 b 11 + a 12 b 21 + a 13 b 31 a 21 b 11 + a 22 b 21 + a 23 b 31 a 31 b 11 + a 32 b 21 + a 33 b 31
This is shorthand for three linear equations: a 11 b 11 + a 12 b 21 + a 13 b 31 = c 11 (4) a 21 b 11 + a 22 b 21 + a 23 b 31 = c 21 (5) a 31 b 11 + a 32 b 21 + a 33 b 31 = c 31. (6) When dealing with N coupled oscillators, we’ll have matrix equations that look like AB = 0, where 0 is a N × 1 array of zeros. The elements of A will involve the oscillation frequencies (ω), and the elements of B will
involve the amplitudes. We’ll want to find the condi- tions such that the equation has a solution other than the “trivial” one, B = 0. A fundamental theorem of lin- ear algebra states that a non-trivial solution exists if and only if the determinant of A is zero. In the next section, we’ll look at how to calculate a determinant. Exercises. (Don’t turn these in.)
Calculate C = AB. Answer:
C =
w 1 C 1 + w 2 C 2 + w 1 C 3 = 0 (10) 2 w 1 C 1 + 2w 1 C 3 = 0 (11) w 2 C 1 + w 2 C 2 + 2w 1 C 3 = 0. (12) Answer: w 1 w 2 w 1 2 w 1 0 2 w 1 w 2 w 2 2 w 1
II. DETERMINANTS The determinant of the 2 × 2 matrix A =
[ (^) a 11 a 12 a 21 a 22
is
det(A) = a 11 a 22 − a 12 a 21. (15)
Note that this is one diagonal minus the other. The determinant of the 3 × 3 matrix
A =
a 11 a 12 a 13 a 21 a 22 a 23 a 31 a 32 a 33
is
det(A) = a 11 (a 22 a 33 − a 23 a 32 ) (17) −a 12 (a 21 a 33 − a 23 a 31 ) (18) +a 13 (a 21 a 32 − a 22 a 31 ). (19)
This looks complicated, but note that we took each ele- ment of the first row of A (we could have used any row) and multiplied it by the determinant of the 2 × 2 matrix that is formed by excluding the row and column of the element we’re considering. We then add all these terms, flipping the sign (±1) for each alternate element. In other words:
det(A) = +a 11 det
[ (^) a 22 a 23 a 32 a 33
−a 12 det
[ (^) a 21 a 23 a 31 a 33
+a 13 det
a 21 a 22 a 31 a 32
Exercises. (Don’t turn these in.)
R =
[ (^) cos(θ) sin(θ) − sin(θ) cos(θ)
Show that det(R) = 1.
w 1 w 2 w 1 2 w 1 0 2 w 1 w 2 w 2 2 w 1
Answer:
det(W ) = w 1 (− 2 w 1 w 2 ) − w 2 (4w^21 − 2 w 1 w 2 ) (25) +w 1 (2w 1 w 2 ) (26) = − 4 w 12 w 2 + 2w 1 w^22. (27)