Matrix Algebra: Notes on Matrices, Determinants, and Matrix Equations - Prof. Raghuveer Pa, Study notes of Physics

An introduction to matrix algebra, focusing on matrices, their multiplication, and determinants. It includes examples and exercises on calculating matrix products and determinants. Suitable for students in physics or engineering courses, such as physics 351: foundations of physics ii.

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A few notes on Matrix Algebra
Raghuveer Parthasarathy
Department of Physics, University of Oregon
for Physics 351: Foundations of Physics II
(Dated: November 5, 2007)
We’ll very briefly explain a few aspects of linear alge-
bra. This discussion is sufficient for the problems encoun-
tered in your homework assignments. To learn more, see
any linear algebra textbook, e.g.
Howard Anton, Elementary Linear Algebra (7th Ed.),
John Wiley and Sons, New York, 1994.
I. MATRICES
A matrix is a rectangular array of numbers. The ma-
trix A, below, is a 3 ×3 matrix, with elements aij, where
the indices iand jrun from 1 to 3:
A=
a11 a12 a13
a21 a22 a23
a31 a32 a33
.(1)
The matrix B, below, is a 3 ×1 matrix:
B=
b11
b21
b31
.(2)
The product AB is C, also a 3×1 matrix. The elements
ci1of Care given by
ci1=
3
X
j=1
aijbj1,
where Σ indicates a sum. In other words, each element of
Cis the sum of the products of a row of Awith a column
of B. (Here, Bonly has one column.)
C=AB =
a11b11 +a12b21 +a13 b31
a21b11 +a22b21 +a23 b31
a31b11 +a32b21 +a33 b31
.(3)
This is shorthand for three linear equations:
a11b11 +a12b21 +a13 b31 =c11 (4)
a21b11 +a22b21 +a23 b31 =c21 (5)
a31b11 +a32b21 +a33 b31 =c31.(6)
When dealing with Ncoupled oscillators, we’ll have
matrix equations that look like AB = 0, where 0 is a
N×1 array of zeros. The elements of Awill involve the
oscillation frequencies (ω), and the elements of Bwill
involve the amplitudes. We’ll want to find the condi-
tions such that the equation has a solution other than
the “trivial” one, B= 0. A fundamental theorem of lin-
ear algebra states that a non-trivial solution exists if and
only if the determinant of Ais zero. In the next section,
we’ll look at how to calculate a determinant.
Exercises. (Don’t turn these in.)
1. Let
A=
136
32 2
215
.(7)
B=
2
1
0
.(8)
Calculate C=AB.
Answer:
C=
1
8
3
.(9)
2. Write the following system of equations as a matrix
equation:
w1C1+w2C2+w1C3= 0 (10)
2w1C1+ 2w1C3= 0 (11)
w2C1+w2C2+ 2w1C3= 0.(12)
Answer:
w1w2w1
2w10 2w1
w2w22w1
C1
C2
C3
.= 0 (13)
II. DETERMINANTS
The determinant of the 2 ×2 matrix
A=a11 a12
a21 a22 (14)
pf2

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A few notes on Matrix Algebra

Raghuveer Parthasarathy Department of Physics, University of Oregon for Physics 351: Foundations of Physics II (Dated: November 5, 2007)

We’ll very briefly explain a few aspects of linear alge- bra. This discussion is sufficient for the problems encoun- tered in your homework assignments. To learn more, see any linear algebra textbook, e.g. Howard Anton, Elementary Linear Algebra (7th Ed.), John Wiley and Sons, New York, 1994.

I. MATRICES

A matrix is a rectangular array of numbers. The ma- trix A, below, is a 3 × 3 matrix, with elements aij , where the indices i and j run from 1 to 3:

A =

a 11 a 12 a 13 a 21 a 22 a 23 a 31 a 32 a 33

The matrix B, below, is a 3 × 1 matrix:

B =

b 11 b 21 b 31

The product AB is C, also a 3×1 matrix. The elements ci 1 of C are given by

ci 1 =

∑^3

j=

aij bj 1 ,

where Σ indicates a sum. In other words, each element of C is the sum of the products of a row of A with a column of B. (Here, B only has one column.)

C = AB =

a 11 b 11 + a 12 b 21 + a 13 b 31 a 21 b 11 + a 22 b 21 + a 23 b 31 a 31 b 11 + a 32 b 21 + a 33 b 31

This is shorthand for three linear equations: a 11 b 11 + a 12 b 21 + a 13 b 31 = c 11 (4) a 21 b 11 + a 22 b 21 + a 23 b 31 = c 21 (5) a 31 b 11 + a 32 b 21 + a 33 b 31 = c 31. (6) When dealing with N coupled oscillators, we’ll have matrix equations that look like AB = 0, where 0 is a N × 1 array of zeros. The elements of A will involve the oscillation frequencies (ω), and the elements of B will

involve the amplitudes. We’ll want to find the condi- tions such that the equation has a solution other than the “trivial” one, B = 0. A fundamental theorem of lin- ear algebra states that a non-trivial solution exists if and only if the determinant of A is zero. In the next section, we’ll look at how to calculate a determinant. Exercises. (Don’t turn these in.)

  1. Let

A =

B =

Calculate C = AB. Answer:

C =

  1. Write the following system of equations as a matrix equation:

w 1 C 1 + w 2 C 2 + w 1 C 3 = 0 (10) 2 w 1 C 1 + 2w 1 C 3 = 0 (11) w 2 C 1 + w 2 C 2 + 2w 1 C 3 = 0. (12) Answer:   w 1 w 2 w 1 2 w 1 0 2 w 1 w 2 w 2 2 w 1

C 1

C 2

C 3

II. DETERMINANTS The determinant of the 2 × 2 matrix A =

[ (^) a 11 a 12 a 21 a 22

]

is

det(A) = a 11 a 22 − a 12 a 21. (15)

Note that this is one diagonal minus the other. The determinant of the 3 × 3 matrix

A =

a 11 a 12 a 13 a 21 a 22 a 23 a 31 a 32 a 33

is

det(A) = a 11 (a 22 a 33 − a 23 a 32 ) (17) −a 12 (a 21 a 33 − a 23 a 31 ) (18) +a 13 (a 21 a 32 − a 22 a 31 ). (19)

This looks complicated, but note that we took each ele- ment of the first row of A (we could have used any row) and multiplied it by the determinant of the 2 × 2 matrix that is formed by excluding the row and column of the element we’re considering. We then add all these terms, flipping the sign (±1) for each alternate element. In other words:

det(A) = +a 11 det

[ (^) a 22 a 23 a 32 a 33

]

−a 12 det

[ (^) a 21 a 23 a 31 a 33

]

+a 13 det

[

a 21 a 22 a 31 a 32

]

Exercises. (Don’t turn these in.)

  1. Consider a “rotation matrix:”

R =

[ (^) cos(θ) sin(θ) − sin(θ) cos(θ)

]

Show that det(R) = 1.

  1. Evaluate the determinant of the array

W =

w 1 w 2 w 1 2 w 1 0 2 w 1 w 2 w 2 2 w 1

Answer:

det(W ) = w 1 (− 2 w 1 w 2 ) − w 2 (4w^21 − 2 w 1 w 2 ) (25) +w 1 (2w 1 w 2 ) (26) = − 4 w 12 w 2 + 2w 1 w^22. (27)