Metric Spaces and Valued Random Variables: Isometries and Self-Discerning Spaces, Papers of Cryptography and System Security

The relationship between metric spaces, probability spaces, and valued random variables. It discusses the identification of function spaces and the concept of self-discerning metric spaces. The document also includes a proof of a theorem stating that if two metric spaces are isometric to the space of v-valued random variables on a sub-σ-algebra of a probability space, then they are isometric to each other.

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METRIC SPACE VALUED RANDOM VARIABLES
CLINTON T. CONLEY
Given a bounded metric space (V, d) and a probability space (X, µ), we denote by
MALG(X, µ) the σ-algebra of µ-measurable subsets of X(taken modulo null sets),
and we denote by L(X, µ, V ) the space of V-valued random variables, i.e., the set
of µ-measurable functions from Xto V. After making the standard identification
between functions agreeing µ-almost everywhere, L(X, µ, V ) may be equipped with
the metric e
d(f, g) = Rd(f(x), g (x)) (x). For vV, let cvL(X, µ, V ) denote
the constant vfunction (so cv(x) = vfor all xX), and let CV={cv:vV}.
Henceforth, we fix a standard probability space (X, µ).
Let add(null) denote the smallest cardinal κfor which there exists a sequence
(Aα)α<κ of µ-null subsets of Xsuch that Sα<κ Aαis not µ-null. If A MALG(X, µ)
is a sub-σ-algebra, we denote by µAthe restriction of µto A. Observe that the
measure algebra of (X×X, µ ×µA) is separable and non-atomic, and is therefore
isomorphic to MALG(X, µ) (see, e.g., Exercise 17.44 in [1]). If πis an isomorphism
witnessing this, and if (W, d) is a bounded metric space with |W|<add(null), we
have an isometry f7→ ˜
fbetween L(X×X, µ ×µA, W ) and L(X, µ,W ) defined by
˜
f1(w) = π(f1(w)).
We immediately see the following.
Theorem 1. Suppose that (V, dV)and (W, dW)are bounded metric spaces with
|W|<add(null), and suppose there exists some sub-σ-algebra A MALG(X, µ)
such that V
=L(X, µA, W ). Then L(X, µ, V )
=L(X, µ, W ).
Proof. Fix a sub-σ-algebra A MALG(X, µ) such that Vis isometric to L(X, µA, W ).
We see by Fubini that
L(X, µ, V )
=L(X, µ, L(X, µA, W ))
=L(X×X, µ ×µA, W)
=L(X, µ, W ),
completing the proof. 2
The main focus of this paper is to examine when the converse of Theorem 1
holds. Given any metric space (W,d), we may associate with each wWa partial
order wof Wdefined by
w1ww2d(w1, w) + d(w1, w2)d(w2, w) = 0.
1
pf3
pf4
pf5

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METRIC SPACE VALUED RANDOM VARIABLES

CLINTON T. CONLEY

Given a bounded metric space (V, d) and a probability space (X, μ), we denote by MALG(X, μ) the σ-algebra of μ-measurable subsets of X (taken modulo null sets), and we denote by L(X, μ, V ) the space of V -valued random variables, i.e., the set of μ-measurable functions from X to V. After making the standard identification between functions agreeing μ-almost everywhere, L(X, μ, V ) may be equipped with the metric d˜(f, g) =

d(f (x), g(x)) dμ(x). For v ∈ V , let cv ∈ L(X, μ, V ) denote the constant v function (so cv (x) = v for all x ∈ X), and let CV = {cv : v ∈ V }. Henceforth, we fix a standard probability space (X, μ). Let add(null) denote the smallest cardinal κ for which there exists a sequence (Aα)α<κ of μ-null subsets of X such that

α<κ Aα^ is not^ μ-null. If^ A ⊆^ MALG(X, μ) is a sub-σ-algebra, we denote by μA the restriction of μ to A. Observe that the measure algebra of (X × X, μ × μA) is separable and non-atomic, and is therefore isomorphic to MALG(X, μ) (see, e.g., Exercise 17.44 in [1]). If π is an isomorphism witnessing this, and if (W, d) is a bounded metric space with |W | < add(null), we have an isometry f 7 → f˜ between L(X × X, μ × μA, W ) and L(X, μ, W ) defined by

f˜ −^1 (w) = π(f −^1 (w)).

We immediately see the following.

Theorem 1. Suppose that (V, dV ) and (W, dW ) are bounded metric spaces with |W | < add(null), and suppose there exists some sub-σ-algebra A ⊆ MALG(X, μ) such that V ∼= L(X, μA, W ). Then L(X, μ, V ) ∼= L(X, μ, W ).

Proof. Fix a sub-σ-algebra A ⊆ MALG(X, μ) such that V is isometric to L(X, μA, W ). We see by Fubini that

L(X, μ, V ) ∼= L(X, μ, L(X, μA, W )) ∼= L(X × X, μ × μA, W ) ∼= L(X, μ, W ),

completing the proof. 2

The main focus of this paper is to examine when the converse of Theorem 1 holds. Given any metric space (W, d), we may associate with each w ∈ W a partial order ≤w of W defined by

w 1 ≤w w 2 ⇔ d(w 1 , w) + d(w 1 , w 2 ) − d(w 2 , w) = 0.

Let us confirm that ≤w is transitive. Suppose that w 1 , w 2 , w 3 ∈ W are such that w 1 ≤w w 2 and w 2 ≤w w 3. Twice using the triangle inequality, we see

d(w 1 , w) + d(w 1 , w 3 ) ≥ d(w 3 , w) = d(w 2 , w) + d(w 2 , w 3 ) = d(w 1 , w) + d(w 1 , w 2 ) + d(w 2 , w 3 ) ≥ d(w 1 , w) + d(w 1 , w 3 ),

so d(w 1 , w) + d(w 1 , w 3 ) = d(w 3 , w) and hence w 1 ≤w w 3. We may view w 1 ≤w w 2 as expressing that w 1 “lies on a geodesic” between w and w 2. For convenience of notation, we fix some element 0 ∈ W and suppress the subscript in ≤ 0. If (W, d) is a bounded metric space, we use the symbol (^4) w to denote the partial order ≤cw of L(X, μ, W ). Again, when there is no danger of confusion we write 4 instead of 40. It is immediate that w 1 ≤w w 2 if and only if cw 1 4 w cw 2. The following proposition generalizes this fact.

Proposition 2. Suppose that (W, d) is a bounded metric space, w ∈ W , and f, g ∈ L(X, μ, W ). Then f (^4) w g if and only if f (x) ≤w g(x) on a set of full measure.

Proof. Note that q : x 7 → d(f (x), w) + d(f (x), g(x)) − d(g(x), w) is a non-negative function. Thus,

q(x) dμ(x) = 0 if and only if ∀μx (q(x) = 0). Then

f (^4) w g ⇔ d˜(f, cw) + d˜(f, g) − d˜(g, cw) = 0

q(x) dμ(x) = 0

⇔ ∀μx (q(x) = 0) ⇔ ∀μx (f (x) ≤w g(x)). 2

Given a poset (P, ≤P ), we say that a set A ⊆ P is closed under meets in (P, ≤P ) if for all sequences (ai)i∈I in A with |I| < add(null), if

i∈I ai^ exists in^ P^ then it is in A. Analogously, we say that A is closed under joins in (P, ≤P ) if for all sequences (ai)i∈I in A with |I| < add(null), if

i∈I ai^ exists in^ P^ then it is in^ A.

Proposition 3. Suppose that (W, d) is a bounded metric space. Then for all w ∈ W , the set of constant functions is closed under meets and joins in (L(X, μ, W ), (^4) w).

Proof. Without loss of generality, we may assume w = 0 and work with the partial order 4. We show that the set CW = {cw : w ∈ W } is closed under meets in (L(X, μ, W ), 4 ). The argument that C is closed under joins is similar. Fix a sequence (wi)i∈I , |I| < add(null), of elements of W , and suppose that f =

i∈I cwi exists in^ L(X, μ, W^ ). By Proposition 2, we know that for all^ i^ ∈^ I, ∀μx (f (x) ≤ wi). Since |I| < add(null), this implies that ∀μx ∀i (f (x) ≤ wi). Equivalently, ∀μx ∀i (cf (x) 4 cwi ). Since f is the greatest lower bound of (cwi )i∈I , we have that ∀μx (cf (x) 4 f ). Upon appealing once more to Proposition 2, we see that ∀μx ∀μy (f (x) ≤ f (y)), implying that f is constant on a set of full measure. 2

Given a metric space (W, d) and w 0 , w 1 ∈ W , we let w 0 w 1 denote the set {w ∈ W : w ≤w 0 w 1 }, that is, the set of points between w 0 and w 1. We say that w 2 ∈ W discerns the endpoints of w 0 w 1 if w 2 6 ∈ w 0 w 1 and, for i ∈ { 0 , 1 },

∀w ∈ w 0 w 1 \ {wi} (w ∧w 2 wi = w 2 ).

We say that a bounded metric space W is L-minimal if whenever L(X, μ, W ) ∼= L(X, μ, V ), there exists an isometry ϕ : L(X, μ, W ) → L(X, μ, V ) such that ϕ[CW ] ⊆ CV. For example, all sets of cardinality less than add(null), equipped with the dis- crete metric, are L-minimal.

Theorem 5. Suppose that (V, dV ) is a bounded metric space, and suppose that (W, dW ) is a bounded, self-discerning, L-minimal metric space with |W | < add(null). Then the following are equivalent:

  1. V is isometric to L(X, μA, W ) for some sub-σ-algebra A ⊆ MALG(X, μ);
  2. L(X, μ, V ) is isometric to L(X, μ, W ).

Proof. (1) ⇒ (2) is simply an instance of Theorem 1. (2) ⇒ (1): Fix an isometry ϕ : L(X, μ, W ) → L(X, μ, V ) such that ϕ[CW ] ⊆ CV. Let F = ϕ−^1 (CV ), so F ∼= V. We have that F contains CW and, by Proposition 3, F is closed under meets and joins. Thus, by Proposition 4, there exists a sub-σ-algebra A ⊆ MALG(X, μ) such that F ∼= L(X, μA, W ) as desired. 2

Corollary 6. Suppose that V and W satisfy the hypotheses of Theorem 5. Suppose in addition that W is a metric group. If L(X, μ, V ) ∼= L(X, μ, W ), then V can be given a group structure compatible with its metric.

Proof. By Theorem 5, we have that V ∼= L(X, μA, W ) for some sub-σ-algebra A ⊆ MALG(X, μ). V then forms a metric group under the operations of pointwise multiplication and inversion. 2

If we equip { 0 , 1 } with the discrete metric, it is easily seen that L(X, μ,{0,1}) ∼= (MALG(X, μ), dμ), where dμ(A, B) = μ(A 4 B). As mentioned, { 0 , 1 } is L-minimal, but it fails to be self discerning. Nevertheless, the analogue of Theorem 5 remains true.

Theorem 7. Suppose that (V, d) is a bounded metric space. The following are equivalent:

  1. V is isometric to the restriction of MALG(X, μ) to a sub-σ-algebra;
  2. L(X, μ, V ) is isometric to MALG(X, μ).

Proof. (1) ⇒ (2) is yet another instance of Theorem 1. (2) ⇒ (1): Fix an isometry ϕ : L(X, μ, V ) → MALG(X, μ). We may assume ϕ(c 0 ) = ∅: if this is not the case, we replace ϕ by ϕ′^ defined by ϕ′(f ) = ϕ(f ) 4 ϕ(c 0 ). We will show that A = {ϕ(cv ) : v ∈ V } forms a sub-σ-algebra of MALG(X, μ). Since v 7 → ϕ(cv ) is an isometry between V and A, this will complete the proof of the theorem. We first notice that if we have such a ϕ, then for each v ∈ V there is a unique v ∈ V with d(v, v) = 1. To see existence, we consider f = ϕ−^1 (X \ ϕ(cv )). Since

d^ ˜(cv , f ) = dμ(ϕ(cv ), ϕ(f )) = 1, we may find a v ∈ V with d(v, v) ≥ 1. Of course, we must have that the diameter of V is at most 1, so d(v, v) = 1. On the other hand, if v 1 and v 2 are such that d(v, v 1 ) = d(v, v 2 ) = 1, then dμ(ϕ(cv ), ϕ(cv 1 )) = dμ(ϕ(cv ), ϕ(cv 1 )) = 1. Thus, ϕ(cv 1 ) and ϕ(cv 2 ) are both com- plements of ϕ(cv ), and hence equal, so v 1 = v 2. Since dμ(ϕ(cv ), ϕ(cv )) = 1, we conclude that A is closed under complements.

To see A is closed under countable intersections, we simply observe that ϕ induces an isomorphism between the posets (L(X, μ, V ), 4 ) and (MALG(X, μ), ⊆). Then, since MALG(X, μ) is closed under countable intersections, Proposition 3 implies that A is as well. 2

Corollary 8. Suppose that (W, d) is a bounded metric space such that |W | < c. If L(X, μ, W ) is isometric to MALG(X, μ), then W is finite.

Proof. The smallest infinite sub-σ-algebra of MALG(X, μ) has size c. 2

Regrettably, there is not yet a simple characterization of metric spaces which are both L-minimal and self discerning. Additionally, in light of Theorem 7, it appears that the definition of a self discerning space is a bit too restrictive, as it excludes the smallest nontrivial space for which the theorem is true.

References

[1] A.S. Kechris. Classical descriptive set theory, volume 156 of Graduate Texts in Mathematics. Springer-Verlag, New York, 1995.