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The midterm exam for the ece65 (winter 2007) course focusing on circuit design with operational amplifiers (opamps) and diodes. The exam includes three problems: designing a high-pass filter circuit, finding the output voltage for a given input voltage, and determining the range of input voltage for which a diode is off. Detailed solutions for each problem.
Typology: Exams
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Notes: 1. Write your answers on these three sheets.
Problem 1. Design a circuit with a transfer function of H(jω) = 1 1 − j 105 /ω and a
minimum input impedance of 10 kΩ. (10pts)
The transfer function is for a first-order high-pass filter with ωc = 10^5 rad/s. Since K = 1, we can (and should) use a passive filter. Prototype of the circuit is shown below with
ωc =
Zi|min = R ≥ 10 kΩ
Choosing R = 10 kΩ, we get:
Rωc
= 10−^9 F = 1 nF
Therefore, R = 10 kΩ and C = 1 nF (both commercial values).
Problem 2. Find vo/vi (Assume OpAmp is ideal). (10pts)
vi vo
v 1 v 2
vn
vp
R
R R R
R
R −
Ideal OpAmp: ip ' in ' 0.
Non-inverting terminal of the OpAmp is grounded, thus vp = 0
We have negative feedback: vn ≈ vp. Since vp = 0, vn ≈= 0
Using node-voltage method:
Node vn vn − vi R
vn − v 1 R
→ vn − vi + vn − v 1 = 0 → v 1 = −vi
Node v 1 v 1 − vn R
v 1 − 0 R
v 1 − v 2 R
→ v 1 − vn + v 1 + v 1 − v 2 = 0 → v 2 = 3v 1 = − 3 vi
Node v 2 v 2 − v 1 R
v 2 − 0 R
v 2 − vo R
→ v 2 − v 1 + v 2 + v 2 − vo = 0 → vo = 3v 2 − v 1 = − 9 vi + vi = − 8 vi
Thus vo/vi = −8.