Minimum Variance Unbiased Estimator - Lecture Notes | STAT 312, Study notes of Mathematical Statistics

Material Type: Notes; Class: Introduction to Mathematical Statistics; Subject: STATISTICS; University: University of Wisconsin - Madison; Term: Fall 2004;

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Stat 312: Lecture 03
Minimum Variance Unbiased Estimator
Moo K. Chung
September 9, 2004
1. Population of interest is a collection of measur-
able objects we are studying. Let X1,· · · , Xnbe
a random sample from the population. Then sam-
ple mean ¯
Xand sample variance S2are unbiased
estimators of population mean µand population
variance σ2respectively.
Proof. Note that
S2=1
n1X
i=1
(Xi¯
X)2=1
n1h
n
X
i=1
X2
in¯
X2i.
Then using the fact E(¯
X)2=V¯
X+ (E¯
X)2=
σ2/n +µ2, it can be shown that ES2=σ2.
2. There may be many unbiased estimators of θ.
Given two unbiased estimators ˆ
θ1and ˆ
θ2of θ. We
choose one that gives less variance. If V(ˆ
θ1)
V(ˆ
θ2),ˆ
θ1is called more efficient than ˆ
θ2. An effi-
cient estimator has less variability so we are more
likely to make an estimate close to the true param-
eter value. The following coin flipping example
clearly demonstrate this.
> a<-rbinom(1000,1,0.5)
> a
[1]00100101100...
> mean(a)
[1] 0.517
> mean(a[1:3])
[1] 0.3333333
> mean(a[1:9])
[1] 0.4444444
> mean(a[1:11])
[1] 0.3636364
3. Among all unbiased estimators, we choose the
most efficient estimator called the minimum vari-
ance unbiased estimator (MVUE). The MVUE is
an unbiased estimator with the smallest variance.
MVUE is the most efficient estimator. An effi-
cient estimator ˆ
θwill produce an estimate closer
to the true parameter θ.¯
Xis MVUE for µ(we
will not prove this statement).
4. Given a random sample X1,· · · , Xn, a linear es-
timator of parameter θis an estimator of form
ˆ
θ=
n
X
i=1
ciXi.
Then it can be shown that ¯
Xis the MVUE for
population mean µamong all possible linear esti-
mators.
Proof. Case n= 2 will be proved. The general
statement follows inductively. Consider linear es-
timators
ˆµ=c1X1+c2X2.
To be unbiased, c1+c2= 1. To be most efficient
among all unbiased linear estimators, the variance
has to be minimized. The variance is
Vˆµ=c2
1VX1+c2
2VX2=£c2
1+ (1 c1)2¤σ2
The quadratic term in the bracket 2c2
12c1+ 1
is minimized when c1= 1/2.
Review Problems. You are not required to do these
problems but these are problems you should be able to
answer after each lecture. What is an unbiased estima-
tor of population parameter µ2? Exercise 6.3.

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Stat 312: Lecture 03

Minimum Variance Unbiased Estimator

Moo K. Chung

[email protected]

September 9, 2004

  1. Population of interest is a collection of measur- able objects we are studying. Let X 1 , · · · , Xn be a random sample from the population. Then sam- ple mean X¯ and sample variance S^2 are unbiased estimators of population mean μ and population variance σ^2 respectively. Proof. Note that

S^2 =

n − 1

i=

(Xi− X¯)^2 =

n − 1

[ (^) ∑n

i=

X i^2 −n X¯^2

]

Then using the fact E( X¯)^2 = V X¯ + (E X¯)^2 = σ^2 /n + μ^2 , it can be shown that ES^2 = σ^2.

  1. There may be many unbiased estimators of θ. Given two unbiased estimators ˆθ 1 and θˆ 2 of θ. We choose one that gives less variance. If V(θˆ 1 ) ≤ V(ˆθ 2 ), θˆ 1 is called more efficient than θˆ 2. An effi- cient estimator has less variability so we are more likely to make an estimate close to the true param- eter value. The following coin flipping example clearly demonstrate this.

a<-rbinom(1000,1,0.5) a [1] 0 0 1 0 0 1 0 1 1 0 0 ... mean(a) [1] 0. mean(a[1:3]) [1] 0. mean(a[1:9]) [1] 0. mean(a[1:11]) [1] 0.

  1. Among all unbiased estimators, we choose the most efficient estimator called the minimum vari- ance unbiased estimator (MVUE). The MVUE is an unbiased estimator with the smallest variance. MVUE is the most efficient estimator. An effi- cient estimator θˆ will produce an estimate closer

to the true parameter θ. X¯ is MVUE for μ (we will not prove this statement).

  1. Given a random sample X 1 , · · · , Xn, a linear es- timator of parameter θ is an estimator of form

θ^ ˆ =

∑^ n

i=

ciXi.

Then it can be shown that X¯ is the MVUE for population mean μ among all possible linear esti- mators. Proof. Case n = 2 will be proved. The general statement follows inductively. Consider linear es- timators μ ˆ = c 1 X 1 + c 2 X 2. To be unbiased, c 1 + c 2 = 1. To be most efficient among all unbiased linear estimators, the variance has to be minimized. The variance is

Vμˆ = c^21 VX 1 + c^22 VX 2 =

[

c^21 + (1 − c 1 )^2

]

σ^2

The quadratic term in the bracket 2 c^21 − 2 c 1 + 1 is minimized when c 1 = 1/ 2.

Review Problems. You are not required to do these problems but these are problems you should be able to answer after each lecture. What is an unbiased estima- tor of population parameter μ^2? Exercise 6.3.