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Mole concept notes for neet exam, Lecture notes of Chemistry

Chemistry

This is very helpful for revision and deep understanding you must check out this

Typology: Lecture notes

2023/2024

Available from 06/09/2025

abhinandan-6 🇮🇳

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Formula

sheet

Mole

Concept

Sudhanshu

Sir

⑪

Atomicity

no.

atoms

molecule

Molecule

Fietro

atomiz

micity-

Homoatomiz

Molecules

Atoms

120

Sg,

siz

atomicity

Relative

②

Particles

charge

Relative

MASS

mas]

-charge

Electron

(e/e0)

1.6x10

9.1

x10-31kg

amu

proton

(24/p)

1.6x1092

10673x1824g

neutron(n)

neutral

⑧

675x1024

amu

Partial preview of the text

Download Mole concept notes for neet exam and more Lecture notes Chemistry in PDF only on Docsity!

Formula sheet

of

Mole Concept

Sudhanshu Sir

⑪ Atomicity = no. of atoms in^ a^ molecule^ Molecule

X I Fietroatomiz micity- (^) Homoatomiz Molecules Atoms^120

Sg, Py^ siz = atomicity

Relative

② (^) S Particles

charge

Relative

MASS mas]

-charge

(^) -- --

Electron

(e/e0)

1.6x10 - (^) I 9.1^ x10-31kg 0 amu proton (24/p)

1.6x1092^ +1^ 10673x1824g Iam neutron(n) neutral^ ⑧ 1 675x amu

⑰- I mass (^) ofelection: 1

(mass of

proton/neutron) 1837 ② (^) mass ofproton- mass ofneutrin=^ or^ I ③ (^) In general, Mn* (^) Mp me^

But

if (^) option is^ given in (^) Question, Mn>^ Mup> me

④ (^) Atomic mass-mass due to^ proton

mass (^) due to mass ofelectron^

is considered

negligible ⑤electron^ change causes^ chemical reactions. change in protin/neutron causes^ nuclear (^) reactions.

=> in an atom i -- Neutral/uncharged/Isolated Atom tan/ans no

of

CO = no. ofprotons^ = 2 Cations Anious

-> positively charged^ atoos -> negatively charged atom -> formed by

loss of el^

towered bygainst no. (^) ofeo^ no. of no. (^) ofe-^ no.-/ (^) chargel

no. of

28=p+ (^) (charge,

④ opes- same atomic^

Number but

different

mass number

Heavier (^) isotopes of

an element behaves

↓ ricot braveasufferent no (^) ofmeene as (^) Radioactive ⑪

4 >^ D^ > T

Average atomic mass =

2 %^ abundance^

x (^) Isotopic mass

100 > Isotopes have (^) same chemical^ properties but different physical properties.

⑥ I atomic mass^ unit (^) (a.m.u) itis defined as i thot or I wified

mass (v)

3 => mass of atom^

ofC.

1 amu = 16 x

1024kg

16x10mg = mass

of

1 proton

or neutr ⑦Imole= Aragadro's

number = 6.022 x

= 6x102=

NA

NAX

(^1) amo

I

(in

grams)

mass of 1 atom

of an element^ = (mass (^) no.Jamu=

atomicmass

Molaw mass (^) ofI mole atom (^) ofan (^) element: (mass (^) no) gram= atomic Mass

⑧ (^) if gram/ is (^) used (^) as prefix, thenit represent more

I

gram

atom of^0

= 6.022x102 (^) atoms of

concept is (^) also known as^ Gram^ concept

⑲ No.^ ofmoles^ ofX^

(^) criven mass (^) of X

-> molar volume

ofa gas atConstant & is independent of(i)^ nature^ of gas (ii) atomicity ofgas (iii)Molar^ mass (^) of gas ⑪ For^ gases

no. of moles of X=he X In general,

Vm=

molar wire^

= 22: Ul

Don't use this

-- E S

= 22400ml

=22400CM formula for solids/liquids. Here is a t

=22-4dm

=22400CC.

012 Given mass^ Given no.

of

particles (solid/liquid/Gas] solid/liquid/gay =Molar mass

HA

I X

Molar

= NA

mass

moles

=> Molas x^

Molar volume

X voi

Given volume

has only

⑭ density ofgas

density ofgas is (^) observed maximum^ at High and (^) low ⑮ (^) Vapor (^) Density (VDS^ of a gas- gas atsame

Unitless Relative Quantity density ofM2^ gas at same

roD- of

geare

⑯ Aragadio's law I -> atSame^ D equal

is

(^9) haveane equal molecules.

⑰eage composition

or

by mass ⑬one

to or

by volure mass%yX = otx e %o = of xe

) Noon aqueous solution onaqueous solution ↓ ↓ 10 go Moot is^

present

in (^100) g local

of

Moonis^ present

in

solution 100 ml^ of

solution ②massby wire meby^ mass (w/v) of X = fx x 100 [Iw) (^) of x =

7X x

total col totalmass 10% (w/v) Naon aqueous solution

Noon aqueous^

solution

logoNaot

is present in 100m/solution,^ ml^ of Moon is^ present in (^) 100g o

solution.

=> Two differentcompands^ can have^ same E.F. (Reason

same (^) % (^) composition) => M.F and (^) E.F ofa^ compound^ may be same

(Reason

atoms are already in

simplest

whole no^ ratio) ⑧ina trastacian simbaine

I I I

021 strichiometry

-> deals with the^ measurementof

quantities

of reactants and products

in a

ded chemicalreactions.

(^2) NH

(8)

34g

(^) Stand and^ of 2x 289 68 2x

can be^ written

22.4 3 22.4l

by balanced (^1 )

I mol 3 mol 2

mol I

chemical reactions I molecule^3 molecule^ (^2) molecule --

⑫ purity concept^

mostly applied on^ Reactant -> (^) Given (^) mass

ofE mass^ ofpure +

impurities Reactant (^) sample reactant

(^) Given (^) mass ofReactant^ sample (^) of mass^ of pureblatent -> purity

pure reactant x (^100) mass ofreactant sample ⑬ yield/efficient concept

mostly applied^ on products Theoretical yield I calculated^ value^ of producttri stoichiometry Actual/Real/experimentalyield^

->observed^

value of

product

during

the2xn

% yield-alfield a re ⑭Limiting Reagent/Reactant (R) (^) concept is^ applied when quantity

of

more (^) than (^) one realtant^ is given in (^) Question Reactant(L.R)

(^) Reactantwhich^ can be completely consumed during the reaction. after the reaction, amount

ofLoR^ presentin^ container^

= 0 it (^) decides theamount^ ofproducts^ formed^ during the2x

and also decides theamount

of excel reactant

consumed

during

Mole concept notes for neet exam, Lecture notes of Chemistry

Related documents

Partial preview of the text

Download Mole concept notes for neet exam and more Lecture notes Chemistry in PDF only on Docsity!

Formula sheet

of

Mole Concept

Sudhanshu Sir

Relative

charge

Relative

-charge

Electron

(mass of

But

is considered

of

loss of el^

no. of

Number but

mass number

an element behaves

4 >^ D^ > T

2 %^ abundance^

mass (v)

ofC.

1 amu = 16 x

1024kg

of

1 proton

number = 6.022 x

NA

NAX

(^1) amo

I

(in

mass of 1 atom

atomicmass

I

atom of^0

-> molar volume

Vm=

molar wire^

Don't use this

= 22400ml

=22-4dm

=22400CC.

of

HA

Molar

= NA

moles

Molar volume

Given volume

roD- of

geare

is

or

to or

present

of

in

solution 100 ml^ of

7X x

solution

logoNaot

solution.

(Reason

simplest

-> deals with the^ measurementof

quantities

in a

can be^ written

22.4 3 22.4l

I mol 3 mol 2

ofE mass^ ofpure +

->observed^

value of

during

the2xn