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Material Type: Notes; Class: HOW THINGS WORK; Subject: PHYSICS; University: University of North Carolina - Chapel Hill; Term: Fall 2006;
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Lecture 2, Newton’s Laws Phys 100, How Things Work
What’s a force and what’s it do? What are Newton’s three laws of motion? What are they good for? Rosencrantz: “ Heads. Heads. Heads. Heads. …” Rosencrantz and Guildenstern are Dead by Stoppard Lecture 2, Newton’s Laws Phys 100, How Things Work
1: Objects have inertia Motion under no force does not change momentum is constant 2: F = ma aka (force) = (mass)×(acceleration) if you push on something you can change its motion decrease, increase or re-direct the momentum 3: Each (action) force causes and equal and opposite reaction F (A on B) = − F (B on A) Lecture 2, Newton’s Laws^ Phys 100, How Things Work
There is more than one spatial direction Write boldface or symbols with arrows F Position r (or whatever) Velocity v Acceleration a Force F Lecture 2, Newton’s Laws^ Phys 100, How Things Work
Newton 2: F = ma Force is gravity or weight and constant here So: (drum roll…..) Acceleration is constant it’s 9.8m/s^2 it points down Only vy changes, vx is constant y x
Lecture 2, Newton’s Laws Phys 100, How Things Work
For constant acceleration Horizontal component x = x 0 + vxΔt Vertical component y = y 0 + vyΔt + ay (Δt)^2 / Both components r = r 0 + vΔt + a(Δt)^2 / y Velocity v = v 0 + aΔt x Lecture 2, Newton’s Laws Phys 100, How Things Work
Use what we know to get what we want (in stages) So we can use vy = v0y + ayΔt to get Δt And then use y = y 0 + v0yΔt + ay(Δt)^2 / 2 to get y at the top of the arc We know v0y (30m/s) and ay (-10m/s^2 ), but not vy and Δt vy = 0 at the top of the arc, so 0 = (30m/s) + (-10m/s^2 )Δt and hence Δt = 3 seconds y = y 0 + v0yΔt + ay(Δt)^2 / 2 = 0 + (30)(3) + (-10)(3^2 )/ = 45 m Lecture 2, Newton’s Laws^ Phys 100, How Things Work
Lecture 2, Newton’s Laws Phys 100, How Things Work
Work to lift the boulder is (W)(Δy) = mg(y-y 0 ) You’re tired at the top of the ramp because you gave your energy to the boulder’s potential energy You push against the force W(Δy)/[(Δx)^2 + (Δy)^2 ]1/ which is always smaller than W The ramp gives you a mechanical advantage. You do the same work with less effort over a longer distance Δy Δx
The mammoth’s headache comes from releasing that potential energy as kinetic energy Lecture 2, Newton’s Laws Phys 100, How Things Work