Normal Distribution - Engineering Perspectives - Lecture Slides, Slides of Process Engineering

The key points in the lecture slides of the Engineering Perspectives are:Normal Distribution, Gaussian Distribution, Continuous Probability, Density Function, Statistical Inference, Area Under Curve, Carbon Composition, Student’s T-Distribution, Standard Deviation, Confidence Interval

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2012/2013

Uploaded on 05/06/2013

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Normal Distribution
The normal distribution (also known as Gaussian distribution)
with parameters μ and σ, N(μ,σ), is the continuous probability
distribution with the following probability density function:
Normal distribution is the cornerstone of the field of
statistical inference
Many distributions can be well approximated by the normal
distribution
e.g. weight, height, bolt diameter, resistance of wire, construction
error, etc.
1
<<−∞=
xexf x
X,),;( 2
2
2
)(
2
1
σ
µ
πσ
σµ
Where π = 3.14159…, e = 2.71828…
(Eq. 1)
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Normal Distribution

  • The normal distribution (also known as Gaussian distribution)

with parameters μ and σ , N ( μ ,σ), is the continuous probability

distribution with the following probability density function:

  • Normal distribution is the cornerstone of the field of

statistical inference

  • Many distributions can be well approximated by the normal

distribution

  • e.g. weight, height, bolt diameter, resistance of wire, construction error, etc.

1

− −

f x e x

x

X

2 2

( )^2

2

(^1) σ

μ

σ π

Where π = 3.14159…, e = 2.71828…

(Eq. 1)

Normal Distribution

2

Graph of the Probability Dense

Function of Normal Distribution

  • A bell curve, symmetric about X = μ
  • Shape of the curve is determined by σ
    • the larger σ is, the flatter the curve is

σ 2 > σ 1

4

μ

Z =

Z

P( Z <1) = 0.

What is the total area under curve?

5

P( Z <- z ) = P ( Z > z ), for z >

Z =-1^ Z =

μ

P( Z <-1) = 0.159 (^) P( Z >1) = 0.

Z

7

Suppose the resistance of a carbon composition resistor is normally

distributed with mean μ = 1,000 and variance σ^2 = 900. What is the

probability that the resistor has measurement in excess of 1,060 ohms?

X ~ N ( μ =1000, σ=30), P ( X >1060)=?

ZX = ( X -1000)/

P ( X >1060)= P ( ZX > (1060-1000)/30) = P ( ZX >2) = 1- P ( ZX < 2)

X = the resistance of a carbon composition

Define X

Student’s t-Distribution

  • Student’s t-distribution or t-distribution is used to replace normal

distribution when the standard deviation σ is not known and thus

has to be estimated using sample standard deviation s

8

df = ∞ (becomes normal distribution) df = 10 df = 5 df = 2 df = 1

Confidence Interval

  • A confidence interval gives an estimated range of values

which is likely to include an unknown population parameter;

it is calculated from a given set of sample data

  • Confidence Level
    • How sure the confidence interval includes the true value of the

population parameter to be estimated

10

“We are 95% confident that between 60% and 70% people will agree

with this proposal.”

95% is our confidence level; (60%, 70%) is our confidence interval

Confidence Interval for Mean

  • Suppose a random sample of size n is drawn from a normal

distribution with mean μ and standard deviation σ

(unknown), then the confidence interval for μ is:

11

( ( 1 ) , ( 1 ) )^ (Eq. 6)

/ 2 / (^2) n

s

n

s

x − t n − ⋅ x + t n − ⋅

α α

where α is significance level and equal to (1 – confidence level)

 t-distribution table can be downloaded from the course website

13

Sample Grades

1 88

2 85

3 90

4 87

5 85

6 80

7 75

8 92

9 95

10 85

  1. 75

  2. 2

=

=

s

x

Suppose these grades are sampled from a normal distribution with mean μ and standard deviation σ (unknown), find the confidence interval of the mean of the grades with 95% confidence level

t α/2 (10-1) = t α/2 (9) = 2.

The confidence interval for μ is: (86.2-2.262∙5.75/√10, 86.2+2.262∙5.75/√10) = (82.09, 91.31)

α = 0.05, n =

X = grades of student

Exponential Distribution

  • Often used to model the time interval between independent

events that happen at a constant average rate

  • The probability density function of an exponential function

has the form

14

x

e x

f x

x

X

λ λ (Eq. 7)

λ > 0 is a parameter of the distribution, often called the rate parameter

 The cumulative distribution is given by

x

e x F x

λ x

λ (Eq. 8)

 Mean and Variance

E( X ) = 1/λ (Eq. 9) var( X ) = 1/λ^2 (Eq. 10)

16

Suppose the life in hours of a certain type of tube is a random variable that has an

exponential distribution with a mean of 1,000 hours. What is its probability density

function? What is the probability that such a tube will last at least 1,250 hours?

E( X ) = 1000 = 1/λ → λ = 1/

f ( x ) = 1/1000 × e(-1/1000)∙ x

P ( X ≥1250) = 1 - P ( X <1250) = 1- F ( X =1250) = 1- (1- e(-1/1000)∙1250^ ) = e(-1/1000)∙ = 0.

X = life in hours of the tube