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An in-depth analysis of different types of errors in physics experiments, including instrumental, observational, environmental, and theoretical errors. It also covers statistical analysis of random errors using gaussian and poisson distributions, and propagation of errors in calculated quantities. Examples and formulas for error estimation.
Typology: Study notes
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current
Random^ – Can be quantified by statistical
analysis
Systematic^ – Try to identify and get rid of^ – Hopefully found during
analysis; may need to repeatexperiment!
True Value True Value
For n measurements,they should grouparound the true value.For large n, theaverage should tendto the true value
=
n i
i
1
If the measurementsare independent, canfind the standarddeviation,
σ
σ
is the
width of thedistribution.
n i
i^
1
2
m
x
σ ±
Significant figures:^ –
σ
m
: one (sometimes two) sig. figs.
ave
: same accuracy as
σ
m
e = 1.602 176 5 x 10
0.000 000 1 x 10
-^
-^
m
The probability of a measurement being within+
σ
of x
ave
Probability of being within:
1
σ
= 68.3% 2
σ
= 95.5% 3
σ
= 99.7%
x x
dx) x( P
) σ in
with( P
! x
e
x
) x( P
x
x^
−
=
0 0.10.090.080.070.060.050.040.030.020.
0
5
10
15
20
25
30
35
x
P(x)
Poisson Gaussian 1 Gaussian 2
0 0.10.090.080.070.060.050.040.030.020.
0
5
10
15
20
25
30
35
x
P(x)
Applies to processesdescribed by anexponential, such asradioactive decay
-^
σ
x
For large x
ave
, i.e. for long
counting times, thePoisson distribution tendsto the Gaussiandistribution.
xave
= 20
Gaussian 1:
σ
=
√
20 = 4.
Gaussian 2:
σ
= 6
x^
Let w(x,y,z) be afunction of measuredvalues. We want tofind
δ
w, the error in
w.
-^
If the errors areuncorrelated, andwith dx
δ
x,
If the errors arecorrelated, there arecross terms like
dz w z
dy w y
dx w x
dw
al
differenti
∂^ ∂
∂ ∂
:
(^
)^
(^
)^
(^
)
(^
)
∑
∂ ∂
∂ ∂
∂ ∂
∂ ∂
=
=
i
i
w x
w z
w y
w x
x
w
z
y
x
w
i
2
2
2
2
cov( y x^
y x
w w
∂ ∂ ∂ ∂
ρ
= m/V ρ
= m/(
π
(^2) r h)
(^
)^
(^
)^
(^
(^2) )
2
2
h
d
m
h
d
m
δ
δ
δ
δρ
ρ
ρ
ρ
∂ ∂
∂ ∂
∂^ ∂
=
h
d
h m d
2 π^4 = ρ
Check yourunits!
(^
)^
(^
)^
(^
(^2) )
2
2
2
h
d
m
h
d
m
δ + δ + δ =
δρ
ρ
ρ
ρ
h m^2 πd 4 = ρ^
(^
)^
(^
)^
(^
(^2) )
2
2
2
h
d
m
h
d
m
δ + δ + δ =
δρ
ρ
ρ
ρ
Assume, after measuring d, h, and m three times each, you get
m = 492.0 +
0.5 g
h = 11.00 +
0.01 cm
d = 4.00 +
0.02 cm,
ρ^
= 3.559 g/cm
3
(^
)^
(^
)^
(^
)
3
3 3
(^0356). 0
(^0009). 0
(^01). 0
(^001). 0
(^559). 3
(^559). 3
2
2
2
2
(^00). 11
(^01). 0
2
(^02). 0 00. 4 2
2 (^0). 492
g 5
. 0
g cm
g cm
cmcm
cmcm
g
g cm
=
=
=
×
ρ^
= 3.56 +
0.04 g/cm
3 ,
δρ
/ρ
= 0.011, 1% error