Moments of Inertia: Calculation and Common Shapes, Study notes of Physics

An in-depth explanation of moments of inertia, including definitions, formulas, and the Parallel-Axis Theorem. It also covers the calculation of moments of inertia for common shapes and includes examples. This information is crucial for understanding beam and column behavior.

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2021/2022

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ENDS 231 Note Set 12 F2007abn
1
y
x
el
xdx
dA = ydx
θ
pole
o
r
x
x x x
Moments of Inertia
The cross section shape and how it resists bending and twisting is important to understanding
beam and column behavior.
Definition: Moment of Inertia; the second area moment
=dAxIy2
=dAyIx2
We can define a single integral using a narrow strip:
for Ix,, strip is parallel to x for Iy, strip is parallel to y
*I can be negative if the area is negative (a hole or subtraction).
A shape that has area at a greater distance away from an axis through its centroid will have a
larger value of I.
Just like for center of gravity of an area, the moment of inertia can be determined with
respect to any reference axis.
Definition: Polar Moment of Inertia; the second area moment using polar coordinate axes
+== dAydAxdArJo222
yxo IIJ +=
Definition: Radius of Gyration; the distance from the moment of
inertia axis for an area at which the entire area could be considered as
being concentrated at.
= ArI xx
2
A
I
rx
x= radius of gyration in x
A
I
ry
y= radius of gyration in y
A
J
ro
o= polar radius of gyration, and ro2 = rx2 + ry2
pf3
pf4
pf5

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y

x x (^) eldx

dA = y⋅dx

θ pole

o

r

x x x x

Moments of Inertia

  • The cross section shape and how it resists bending and twisting is important to understanding beam and column behavior.
  • Definition: Moment of Inertia; the second area moment

I y = ∫ x dA

2

I x = ∫ y dA

2

We can define a single integral using a narrow strip:

for I (^) x,, strip is parallel to x for I (^) y, strip is parallel to y

  • I can be negative if the area is negative (a hole or subtraction).
  • A shape that has area at a greater distance away from an axis through its centroid will have a larger value of I.
  • Just like for center of gravity of an area, the moment of inertia can be determined with respect to any reference axis.
  • Definition: Polar Moment of Inertia; the second area moment using polar coordinate axes

J o = ∫ rdA =∫ x dA + ∫ y dA

2 2 2

J (^) o = Ix + I y

  • Definition : Radius of Gyration; the distance from the moment of inertia axis for an area at which the entire area could be considered as being concentrated at.

I (^) x = rx^2 AA

I

rx = x radius of gyration in x

A

I

r (^) y = y radius of gyration in y

A

J

ro = o polar radius of gyration, and r (^) o^2 = rx^2 + r (^) y^2

axis through centroid at a distance d away from the other axis

axis to find moment of inertia about

y

A

dA

A′

B B′

y′

d

The Parallel-Axis Theorem

  • The moment of inertia of an area with respect to any axis not through its centroid is equal to the moment of inertia of that area with respect to its own parallel centroidal axis plus the product of the area and the square of the distance between the two axes.

y dA d ydA d dA

I y dA y-d dA 2 2

2 2

2

but ∫ y ′ dA = 0 , because the centroid is on this axis, resulting in:

2 I (^) x = Icx + Ad y (text notation) or 2 I (^) x = Ix + Ady where I (^) cx ( or Ix ) is the moment of inertia about the centroid of the area about an x axis and dy is the y distance between the parallel axes

Similarly 2 I (^) y = Iy + Adx Moment of inertia about a y axis J J Ad^2 o =^ c + Polar moment of Inertia r^2 r^2 d^2 o =^ c + Polar radius of gyration r^2 = r^2 + d^2 Radius of gyration

  • I can be negative again if the area is negative (a hole or subtraction). ** If I is not given in a chart, but x &y are: YOU MUST CALCULATE I WITH I = IAd^2

Composite Areas:

I = ∑ I +∑ Ad^2 where I is the moment of inertia about the centroid of the component area d is the distance from the centroid of the component area to the centroid of the composite area (ie. dy = y ˆ^ - y )

Basic Steps

  1. Draw a reference origin.
  2. Divide the area into basic shapes
  3. Label the basic shapes (components)
  4. Draw a table with headers of Component , Area, x , xA , y , y A, I , dx y, Ady^2 , I (^) y, dx, Adx^2
  5. Fill in the table values needed to calculate x ˆ and y ˆ for the composite
  6. Fill in the rest of the table values.
  7. Sum the moment of inertia ( I ’s ) and Ad 2 columns and add together.

Example 1 (pg 257)

Find the moments of inertia ( x ˆ = 3.05”, = 1.05”).

Example 2 (pg 253)

Example 3 (pg 258)