Numerical Integration - Calculus - Solved Exam, Exams of Calculus

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luce: See review shat fir Exam ( (e2(08) Ke intea yection tigs. MATH 106 Final Exam Review, Part I 3 1. Find the following. Sub w= x as au [ Fe? costa) ae = 7 J cosw ay = 2 sinw Hore sin(’) ce a = Kdy PAE -3x Pacts (b) [20 de = linn J xe" = lim rss = “eS a ieee b-260 +, b> be = : om . liw [ 2X ¢ att e* — lim e al dul NeeT Pe apes ze 3 = 7 oe 3e™% ee a lim f ~bg? 1 ? = * bate ( ra ae) , ae 4 a 4 6 ax od i dx Ax lim ° dx € (im —— oe tf gay oo |e ree bode), Hed ae, Ke b — lm In(x-4( | 45 re \n [x4] | haa~ -to 'o a4 ¢| 2 bom Iyferal = lalo-4a] 4 lm, In lena] - be[- yan a= foitiel Fractions Ba? +22—5 —_ They vol oy. t @+i@-y™ Btn -T a ee Hk eaK-F = (Ax +B) K-4) tc (xter) (xteNc-d) Ket x lb x=4: $2619 4) C53 let xz0: -5 = BCA) 43-4. SBRD leh K=1* © = (AL42\C3) + 8-2 4K -T 25 3A ~GiG = Are % | @sea*- \Le Se #a\ = Darkane 4 Blalx4l + K Recall het (e) [va wvsectadr = ae sec*x sec’x ay i J tar‘ (tan'x +) sec" chy sec’x = letan eee att Sc ay Let Go. tann so an Ztany = say. a re a : dws inte Ay = WJ Ne th bw endec = | tan gen