Object-Image Real Image Virtual Image, Lecture notes of Physics

Describe how your image would appear as you approach a convex mirror? Virtual Image. Upright. The image is reduced in size and the field of view is larger ...

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3.1 Images formed by Mirrors and Lenses
Images
Image formation by mirrors
Images formed by lenses
Object-Image
A physical object is usually observed by
reflected light that diverges from the
object.
An optical system (mirrors or lenses) can
produce an image of the object by
redirecting the light.
Real Image
Virtual Image
Real Image
Object real Image
Optical System
diverging converging diverging
Light passes through the real image
Film at the position of the real image is exposed.
Virtual Image
Object
virtual Image
Optical System
diverging
diverging
Light appears to come from the virtual image but does not
pass through the virtual image
Film at the position of the virtual image is not exposed.
Image formed by a plane mirror.
The virtual image is formed
directly behind the
mirror.
Light does not
pass through
the image
Object Image
Each point on the image can be determined
by tracing 2 rays from the object.
mirror
BB’
AA’
object image
pq
A virtual image is formed by a plane mirror at a distance q behin d the mirror.
q = -p
pf3
pf4
pf5
pf8
pf9
pfa

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3.1 Images formed by Mirrors and Lenses

• Images

• Image formation by mirrors

• Images formed by lenses

Object-Image

• A physical object is usually observed by

reflected light that diverges from the

object.

• An optical system (mirrors or lenses) can

produce an image of the object by

redirecting the light.

– Real Image

– Virtual Image

Real Image

Object (^) real Image

Optical System

diverging (^) converging diverging

Light passes through the real image Film at the position of the real image is exposed.

Virtual Image

Object

virtual Image

Optical System diverging diverging

Light appears to come from the virtual image but does not pass through the virtual image Film at the position of the virtual image is not exposed.

Image formed by a plane mirror.

The virtual image is formed directly behind the mirror.

Light does not pass through the image

Object Image

Each point on the image can be determined

by tracing 2 rays from the object.

mirror

B (^) B’

A (^) A’

object image

p q

A virtual image is formed by a plane mirror at a distance q behind the mirror.

q = -p

Parabolic Mirrors

Parallel rays reflected by a parabolic mirror are focused at a point, called the Focal Point located on the optic axis.

Optic Axis

Parabolic Reflector

Parabolic mirrors can be used to focus incoming parallel rays to a small area or to direct rays diverging from a small area into parallel rays.

Spherical mirrors

•Spherical mirrors are much easier to fabricate than parabolic mirrors

  • A spherical mirror is an approximation of a parabolic mirror for small curvatures. (i.e. for paraxial rays –close to parallel to the optic axis.
  • Spherical mirrors can be convex or concave

light light

concave convex

Parallel beams focus at the focal point of

a Concave Mirror.

Focal point

Ray tracing with a concave spherical mirrors

  • A ray parallel to the mirror axis reflects through the focal point, F which is at a point half the radius distance from the mirror along the optic axis.
  • A ray passing through the focal point reflects parallel to the mirror axis
  • A ray striking the center of the mirror reflects symmetrically around the mirror axis
  • A ray that passes through the center of curvature C reflects and passes back through itself

Mirror C F axis

R

F

Law of Reflection

The position of the image can be

determined from two rays from the

object.

F

C

The image is real, inverted, reduced

When object distance > C

O<F

Virtual Image

Upright

Enlarged

Convex Mirror

Image is virtual, upright, reduced

Ray parallel to the optic axis reflects so that the reflected ray appears to pass through the focal point.

Focal Point

A Convex Mirror always forms

virtual images

virtual, upright, reduced

virtual, upright, reduced

Question

Describe how your image would appear as

you approach a convex mirror?

Virtual Image

Upright

The image is

reduced in size

and the field of

view is larger.

Virtual Image

Upright

Virtual Image

Upright

Mirror Equation

• f

O

I

p

q

p q f

p is positive for real objects.

f is positive if the light from infinity goes through the focal point. f positive for concave mirrors, f negative for convex mirrors q is positive if the light goes through the image – real image q is negative if light does not go through image – virtual image

p – object distance q – image distance f - focal length

Magnification

f

O

I

p

M =^ h^ '= − q q

h p

h

h’

q –positive – image is real

M is negative - the image is inverted.

Magnification

f

O

I

p

' q

h q

M

h p

h

h’

q is negative – the image is virtual

M is positive – the image is upright.

Question

A boy stands 2.0 m in front of a concave mirror with a focal length of 0.50 m. Find the position of the image. Find the magnification. Is the image real or virtual? Is the image inverted or erect? p

O

I q (^1) + 1 = 1 p q f (^1) = 1 − 1 q f p

q = (^) p^ fpf^ 0.5(2.0)^ 0. 2.0 0.

= = m

m = − qp^ = −^ 0.672.0^ = −0.

Real image

inverted

Image formed by refraction

• Light rays are deflected by refraction through

media with different refractive indexes.

• An image is formed by refraction across flat or

curved interfaces and by passage through

lenses.

Ray diagram for a converging

lenses

Object Image

A converging lens can form real

and virtual images

converging light

converging light

diverging light

Real Inverted reduced

Real Inverted Enlarged

Virtual Upright Enlarged At the focal point the image changes from real to virtual

Question

How will an object viewed through a

converging lens appear as the lens is

brought closer to the object?

Real Image

Inverted

Real Image

Inverted

Magnified

Virtual Image

Upright

Magnified

Virtual image

Upright

Parallel light though a diverging

lens appears to go through the

focal point.

A virtual image is formed.

Image formed by a Diverging lens

Virtual Upright Reduced

A Diverging lens always forms a

virtual image

Question

How will the image of an object formed by a

diverging lens change as the lens is

brought closer to the object?

Virtual Image

Upright

Reduced

Example

F

30 cm

10 cm

An object is placed 30 cm in front of a diverging

lens with a focal length of -10 cm. Find the

image distance and magnification

p q f

q f p

q fp p f

( 10)(30) (^) 7.5cm 30 ( 10) = − = −

− − Virtual image

M q^ 7.5 0. p 30

= − = − − = Upright image

reduced