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Describe how your image would appear as you approach a convex mirror? Virtual Image. Upright. The image is reduced in size and the field of view is larger ...
Typology: Lecture notes
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Object (^) real Image
Optical System
diverging (^) converging diverging
Light passes through the real image Film at the position of the real image is exposed.
Object
virtual Image
Optical System diverging diverging
Light appears to come from the virtual image but does not pass through the virtual image Film at the position of the virtual image is not exposed.
The virtual image is formed directly behind the mirror.
Light does not pass through the image
Object Image
mirror
B (^) B’
A (^) A’
object image
p q
A virtual image is formed by a plane mirror at a distance q behind the mirror.
q = -p
Parallel rays reflected by a parabolic mirror are focused at a point, called the Focal Point located on the optic axis.
Optic Axis
Parabolic mirrors can be used to focus incoming parallel rays to a small area or to direct rays diverging from a small area into parallel rays.
•Spherical mirrors are much easier to fabricate than parabolic mirrors
light light
concave convex
Focal point
Mirror C F axis
Law of Reflection
The image is real, inverted, reduced
When object distance > C
Image is virtual, upright, reduced
Ray parallel to the optic axis reflects so that the reflected ray appears to pass through the focal point.
virtual, upright, reduced
virtual, upright, reduced
p
q
p is positive for real objects.
f is positive if the light from infinity goes through the focal point. f positive for concave mirrors, f negative for convex mirrors q is positive if the light goes through the image – real image q is negative if light does not go through image – virtual image
p – object distance q – image distance f - focal length
f
p
h
h’
f
p
h
h’
A boy stands 2.0 m in front of a concave mirror with a focal length of 0.50 m. Find the position of the image. Find the magnification. Is the image real or virtual? Is the image inverted or erect? p
I q (^1) + 1 = 1 p q f (^1) = 1 − 1 q f p
q = (^) p^ fp − f^ 0.5(2.0)^ 0. 2.0 0.
= = m −
m = − qp^ = −^ 0.672.0^ = −0.
Real image
inverted
converging light
converging light
diverging light
Real Inverted reduced
Real Inverted Enlarged
Virtual Upright Enlarged At the focal point the image changes from real to virtual
Virtual Upright Reduced
30 cm
10 cm
p q f
q f p
q fp p f
( 10)(30) (^) 7.5cm 30 ( 10) = − = −
M q^ 7.5 0. p 30