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This is solution to one of problems in Numerical Analysis. This is matlab code. Its helpful to students of Computer Science, Electrical and Mechanical Engineering. This code also help to understand algorithm and logic behind the problem. This code includes: Pade, Rational, Approximation, Algorithm, Obtain, Nonnegative, Integers, Output, Coefficients, Maclaurin, Polynomial
Typology: Exercises
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% To obtain the rational approximation % % r(x) = p(x) / q(x) % = (p0 + p1x + ... + Pnx^n) / (q0 + q1x + ... + qmx^m) % % for a given function f(x): % % INPUT nonnegative integers m and n. % % OUTPUT coefficients q0, q1, ... , qm, p0, p1, ... , pn. % % The coefficients of the Maclaurin polynomial a0, a1, ... could % be calculated instead of input as is assumed in this program. syms('OK', 'LM', 'LN', 'BN', 'FLAG', 'I', 'AA', 'AAA'); syms('NAME', 'INP', 'N', 'M', 'NROW', 'NN', 'Q', 'P', 'J'); syms('A', 'IMAX', 'AMAX', 'JJ', 'IP', 'JP', 'NCOPY', 'I1'); syms('J1', 'XM', 'K', 'N1', 'PP', 'N2', 'SUM', 'KK', 'LL', 'OUP'); TRUE = 1; FALSE = 0; fprintf(1,'This is Pade Approximation.\n\n'); OK = FALSE; while OK == FALSE fprintf(1,'Input m and n on separate lines.\n'); LM = input(' '); LN = input(' '); BN = LM+LN; if LM >= 0 & LN >= 0 OK = TRUE; else fprintf(1,'m and n must both be nonnegative.\n'); end; if LM == 0 & LN == 0 OK = FALSE; fprintf(1,'Not both m and n can be zero\n'); end; end; OK = FALSE; while OK == FALSE fprintf(1,'The MacLaurin coefficients a(0), a(1), ... , a(N)\n'); fprintf(1,'are to be input.\n'); fprintf(1,'Choice of input method:\n'); fprintf(1,'1. Input entry by entry from keyboard\n'); fprintf(1,'2. Input data from a text file\n'); fprintf(1,'Choose 1 or 2 please\n'); FLAG = input(' '); if FLAG == 1 | FLAG == 2 OK = TRUE; end; end; AA = zeros(1,BN+1); if FLAG == 1 fprintf(1,'Input in order a(0) to a(N)\n');
for I = 0 : BN fprintf(1,'Input A( %d ) \n',I); AA(I+1) = input(' '); end; end; if FLAG == 2 fprintf(1,'As many entries as desired can be placed\n'); fprintf(1,'on each line of the file each separated by blank.\n'); fprintf(1,'Has such a text file been created?\n'); fprintf(1,'Enter Y or N\n'); AAA = input(' ','s'); if AAA == 'Y' | AAA == 'y' fprintf(1,'Input the file name in the form - '); fprintf(1,'drive:\name.ext\n'); fprintf(1,'for example: A:\DATA.DTA\n'); NAME = input(' ','s'); INP = fopen(NAME,'rt'); for I = 0 : BN AA(I+1) = fscanf(INP, '%f',1); end; fclose(INP); else fprintf(1,'Please create the input file.\n'); fprintf(1,'The program will end so the input file can '); fprintf(1,'be created.\n'); OK = FALSE; end; end; if OK == TRUE % STEP 1 N = BN; M = N+1; % STEP 2 - performed in input NROW = zeros(1,N); for I = 1 : N NROW(I) = I; end; % initialize row pointer for linear system NN = N-1; % STEP 3 Q = zeros(1, LM + 1); P = zeros(1, LN + 1); A = zeros(N,N+1); Q(1) = 1; P(1) = AA(1); % STEP 4 % Set up a linear system, but use A(i,j) instead of B(i,j). for I = 1 : N % STEP 5 for J = 1 : I- if J <= LN A(I,J) = 0; end; end;
for K = JJ : M A(J1,K) = A(J1,K)-XM * A(I1,K); end; % STEP 18 A(J1,I) = 0; end; end; I = I+1; end; if OK == TRUE % STEP 19 N1 = NROW(N); if abs(A(N1,N)) <= 1.0e- OK = FALSE; % system has no unique solution else % STEP 20 % Start backward substitution. if LM > 0 Q(LM+1) = A(N1,M)/A(N1,N); A(N1,M) = Q(LM+1); end; PP = 1; % STEP 21 for K = LN+1 : NN I = NN-K+LN+1; JJ = I+1; N2 = NROW(I); SUM = A(N2,N+1); for KK = JJ : N LL = NROW(KK); SUM = SUM-A(N2,KK)A(LL,M); end; A(N2,M) = SUM/A(N2,I); Q(LM-PP+1) = A(N2,M); PP = PP+1; end; % STEP 22 for K = 1 : LN I = LN-K+1; N2 = NROW(I); SUM = A(N2,N+1); for KK = LN+1 : N LL = NROW(KK); SUM = SUM-A(N2,KK)A(LL,M); end; A(N2,M) = SUM; P(LN-K+2) = A(N2,M); end; % STEP 23 % procedure completed successfully fprintf(1,'Choice of output method:\n');
fprintf(1,'1. Output to screen\n'); fprintf(1,'2. Output to text file\n'); fprintf(1,'Enter 1 or 2\n'); FLAG = input(' '); if FLAG == 2 fprintf(1,'Input the file name in the form - drive:\name.ext\n'); fprintf(1,'for example: A:\OUTPUT.DTA\n'); NAME = input(' ','s'); OUP = fopen(NAME,'wt'); else OUP = 1; end; fprintf(OUP, 'PADE RATIONAL APPROXIMATION\n\n'); fprintf(OUP, 'Denominator Coefficients Q(0), ..., Q(M) \n'); for I = 0 : LM fprintf(OUP, ' %11.8f', Q(I+1)); end; fprintf(OUP, '\n'); fprintf(OUP, 'Numerator Coefficients P(0), ..., P(N)\n'); for I = 0 : LN fprintf(OUP, ' %11.8f', P(I+1)); end; fprintf(OUP, '\n'); if OUP ~= 1 fclose(OUP); fprintf(1,'Output file %s created successfully \n',NAME); end; end; end; if OK == FALSE fprintf(1,'System has no unique solution\n'); end; end;