Pascal Pyramids, Paskal Hyper-Pyramids Bilateral Multinomial Theorem | MATH 355, Papers of Geometry

Material Type: Paper; Class: College Geometry; Subject: Mathematics & Statistics; University: California State University - Long Beach; Term: Unknown 1989;

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Pascal Pyramids, Pascal Hyper-Pyramids
and a Bilateral Multinomial Theorem
Martin Erik Horn, University of Potsdam
Am Neuen Palais 10, D - 14469 Potsdam, Germany
Abstract
Part I: The two-dimensional Pascal Triangle will be generalized into a three-dimensional
Pascal Pyramid and four-, five- or whatsoever-dimensional hyper-pyramids.
Part II: The Bilateral Binomial Theorem will be generalised into a Bilateral Trinomial
Theorem resp. a Bilateral Multinomial Theorem.
Introduction
The complete Pascal Plane with its three Pascal Triangles consists of the following numbers
h)1(yh)1(x
h)1y(x
limlim 0h0h
h)!(y h)!(x
h)!y(x
y) (x,
f++++
+++
ΓΓ Γ
=
++
++
=
(1)
and looks like this if the positive directions are pointed downwards:
1 1
-4 1 1 -4
6 -3 1 1 -3 6
-4 3 -2 1 1 -2 3 -4
1 -1 1 -1 1 1 -1 1 -1 1
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
x y
If now numbers with distance 1 are added and the definition of the bilateral hypergeometric
function of [1] is used
()
...
1)(bb
)1a(a
b
a
1
1a
1b
2)(a1)(a
)2b()1b(
... 212 zzzzz b; ;a
11 H+
+
+
+++
+
+= (2)
the following bilateral hypergeometric identity is reached:
[]
1 ;1)(y );xy(
y)(x y
x
x
11 H
!!
!
2+
= x, y R (3)
This is a special case of the Bilateral Binomial Theorem [2, 3] with | z | = 1:
()
[]
z ;1)(y );xy(
)1y(x1)(y
1)(x
z1 11H
x+
++
+
=+ ΓΓ Γ x, y R ; z C (4)
M. Horn: Pascal Pyramids, Pascal Hyper-Pyramids and a Bilateral Multinomial Theorem
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Pascal Pyramids, Pascal Hyper-Pyramids

and a Bilateral Multinomial Theorem

Martin Erik Horn, University of Potsdam Am Neuen Palais 10, D - 14469 Potsdam, Germany E-Mail: [email protected]

Abstract

Part I: The two-dimensional Pascal Triangle will be generalized into a three-dimensional Pascal Pyramid and four-, five- or whatsoever-dimensional hyper-pyramids. Part II: The Bilateral Binomial Theorem will be generalised into a Bilateral Trinomial Theorem resp. a Bilateral Multinomial Theorem.

Introduction

The complete Pascal Plane with its three Pascal Triangles consists of the following numbers

(x 1 h) (y 1 h)

(x y 1 h)

lim lim

h 0 (x h)!(y h)! h 0

(x y h)!

f (x,y) + + ⋅ + +

→ →

and looks like this if the positive directions are pointed downwards:

1 1 -4 1 1 - 6 -3 1 1 -3 6 -4 3 -2 1 1 -2 3 - 1 -1 1 -1 1 1 -1 1 -1 1 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1

x y

If now numbers with distance 1 are added and the definition of the bilateral hypergeometric function of [1] is used

b (b 1)

a (a 1 ) b

a 1 a 1

b 1 (a 1) (a 2)

(b 1 ) (b 2 ) 1 H 1 a;b;z ...^ z^2 z^1 z ⋅z^2 + ⋅ +

= + −^ − (2)

the following bilateral hypergeometric identity is reached:

[( y x); (y 1); 1 ] y (x y)

x x !!^1 H^1

! 2 ⋅ − + − ⋅ −

= x, y ∈ R (3)

This is a special case of the Bilateral Binomial Theorem [2, 3] with | z | = 1:

( ) [( y x);(y 1); z] (y 1) (x y 1 )

(x 1) 1 zx^ ⋅ 1 H 1 − + −

  • ⋅ − +

Γ Γ

Γ x, y ∈ R ; z ∈ C (4)

Part I: Pascal Pyramids and Pascal Hyper-Pyramids The Pascal Plane, which consists of binomial coefficients, can be generalized into the Pascal Space using trinomial coefficients

x!x! x!

(x x x )!

(x,x ,x )

1 2 3

1 2 3

Then the Pascal Pyramid can be constructed by adding every three appropriate neighbouring numbers and writing the result beneath them:

1

1 1 1

1 2 x 2 1 2 1

1 3 3 3 6 3 1 3 3 1 1 4 4 6 12 6 4 12 12 4 1 4 6 4 1

X 3 X 1 X 2

Remark: No, there isn’t a proud 3 sitting in the middle of the second triangle at the marked red position x. This is the place for the following humble trinomial coefficient:

3

2 3

2 3

1

3

2 3

2 3

3 2

2 3

2 3

because the construction law of trinomial coefficients reads:

(x 1 , x 2 ,x 3 ) = (x 1 −1,x 2 ,x 3 )+(x 1 ,x 2 −1,x 3 )+ (x 1 ,x 2 ,x 3 − 1) (7)

But the picture above shows only a quarter of the truth, of course, for three similar pyramids can be constructed in the negative coordinate region using these numbers

(x 1 h) (y 1 h) (z 1 h)

(x y z 1 h)

limh 0 (x h)!(y h)!(z h)! limh 0

(x y z h)!

(x,y,z)

f

    • ⋅ + + ⋅ + +

→ →

as the following drawing indicates:

The next step is to increase the dimension again by considering quatronomial coefficients, which fill the four-dimensional Pascal Hyper-Space:

x! x! x !x!

(x x x x )!

(x,x ,x ,x )

1 2 3 4

1 2 3 4

(x,x ,x 1,x ) (x,x ,x ,x 1)

(x 1,x ,x ,x ) (x,x 1,x ,x )

1 2 3 4 1 2 3 4

1 2 3 4 1 2 3 4

  • − + −

By again using

(w 1 h) (x 1 h) (y 1 h) (z 1 h)

(w x y z 1 h)

f (w,x,y,z) limh 0 + + ⋅ + + ⋅ + + ⋅ + +

five Pascal Hyper-Pyramids can be found. The three-dimensional hyper-surfaces of these four-dimensional hyper-pyramids consist of the Pascal Pyramids (with some more minus- signs every now and then) sketched on the previous page.

This procedure can be continued till eternity. The multinomial coefficients

x! x !... x!

(x x ... x )!

(x,x ,...,x )

1 2 n

1 2 n

1 2 n ⋅ ⋅ ⋅

= (x 1 - 1,x 2 ,...,x 4 )+(x 1 ,x 2 - 1,...,x 4 )+...+(x 1 ,x 2 ,...,x 4 - 1) (13)

live in n-dimensional Pascal Hyper-Space, and with the help of

(x 1 h) (x 1 h)... (x 1 h)

(x x ... x 1 h) 1 2 n

1 2 n

(x,x ,...,x ) h 0

f lim

1 2 n + + ⋅ + + ⋅ ⋅ + +

n + 1 Pascal Hyper-Pyramids can be constructed. These n-dimensional hyper-pyramids possess (n – 1)-dimensional hyper-surfaces which look like the Pascal Pyramids of one dimension less and some more minus-signs every now and then.

Part II: Bilateral Multinomial Theorems

Formula (3) was found by adding numbers of distance 1 which lie on a straight line in the Pascal Plane. One dimension higher a similar formula should be found, if all numbers of distance 1 of the Pascal Space are added which lie in a straight plane. This then would result in powers of 3

∑ ∑^ (^ )

=−∞

=−∞

y x

3 n^ x;y;n x y x, y ∈ R (15)

if the series converged. But this double bilateral summation isn’t supposed to converge for it is a special case ( | z 1 | = | z 2 | = 1) of the Bilateral Trinomial Theorem

∑ ∑^ (^ )

=−∞

=−∞

x 2 x 1

( 1 z 1 z 2 )n^ x 1 ;x 2 ;n x 1 x 2 z 1 x^1 z 2 x^2 (16)

The Bilateral Trinomial Theorem can be reformulated as

∑ ∑

=−∞

=−∞ ⋅ ⋅ + −−

A A A

A

k k k

k

(n 1)

1 x y !!

x y ( )n^ (17)

where (a)k denotes the Pochhammer Symbol

x 1 , x 2 ∈ R z 1 , z 2 ∈ C

(a)

(a k) (a) (^) k Γ

Γ + = resp. (a k)

(a) (a k)k

Γ

Γ − (18)

Using the results of [2, 3] the double summation can be evaluated easily, giving a proof of formula (17) for special values of x and y.

∑ ∑ ∑ ∑

=−∞

=−∞

=−∞

=−∞ (^) − − 

A (^) A A

A

A A

k A^ k A k

k

k

k

n n k

x y

x y ! !(n 1)

Of course the binomial coefficients of (19) are generalized here as

( ) ( 1) lim lim ( ) ( ) ( 1) ( 1)

! h (^)!! h

n (^) n h n h →∞ (^) h n h →∞ h n h

  =^ =
  +^ ⋅^ −^ +^ +^ −^ ⋅^ −^ +^ −

Γ A A A Γ A Γ A

With | x | = 1 this gives

∑ ∑ ∑

=−∞

=−∞

=−∞ (^) − − 

A (^) A A

A A

A

A A

y

x y

( 1 x)

! !(n 1)

n

k (^) n

k k^ k

=−∞ 

A

A

A (^1) x

y

( 1 x)

n n (22)

And with | y | = | 1 + x | the expected result emerges:

n n

k

k k^ k

∑ ∑ + +

=−∞

=−∞ − −^1 x

y

( 1 x) 1

! !(n 1)

x y A A A

A (23)

= ( 1 +x+y)^ n (24)

The same strategy leads to a Bilateral Quatronomial Theorem:

∑ ∑ ∑

=−∞

=−∞

= −∞ ⋅ ⋅ ⋅ + −−−

m k k m k m

k m

A A A

A

(n 1)

1 x y z !!!

x y z ( )n^ (25)

with | x | = 1 , | y | = | 1 + x | and | z | = | 1 + x + y |.

And this again can be extended till eternity giving the Bilateral Multinomial Theorem:

! ) i i x ( 1 ( )

k k

1 2

k

i 1

1 xi (^) (n 1) n A A A A A (^) A

⋅∏ ∏ ∑

  • (^) ∑ = ∑ ∑ ∑

=−∞

=−∞

=−∞ (^) −

  • •• =

i k i

with | x (^) i | = | 1 + (^) ∑

=

i 1

j 1

x (^) j| and.

Epilogue

To increase the aesthetical value of the indicated results a more symmetric formulation of the Bilateral Multinomial Theorem (26) can be given:

k i=

i=1 i=

Ai ∈ R x (^) i ∈ C