PHYSICS
LAB#3-04
Name : Andres Ayala
Partners names : Michael, Anthony
Group : 04
Due date : 6/11/2020
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Physics lab report made to put the force in static equilibrium
Typology: Essays (high school)
2019/2020
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PHYSICS
LAB#3-
Name: Andres Ayala Partners names: Michael, Anthony Group: 04 Due date: 6/11/
Index
- Purpose……………………………………….
- Materials and procedure.......................
- Diagrams…………………………………......
- Observations ……………………………….
- Calculations………………………………….
- Discussion…………………………………….
- Conclusion…………………………………....
Sketch
T T Fg
Free body diagram
Observations
Calculations T1x= 0.9cos (37) = .638909408 N T2X 1.6 cos (61) = .775695392 N T1y= 0.8 sin (37) = 0.481452019 N T2y= 1.6 sin (61) = 1.399391531 N Δ (cos (cosΔ Θ1) = I cos (37)-cos (38) I or I cos (37) -cos (36) I = 0.010624756 or 0. Δ (cos Δ Θ2) = I cos (61) -cos (62) I or cos (61) - cos (60)I = 0.015338057 or 0. Δ (sin Δ Θ1) = Isin (37) - sin (38) I or sin I(37) - sin (36) I= 0.013846452 or 0. Δ (sin Δ Θ2) = Isin (61) - sin (62) I or sin I(61) - sin (60)I = 0.008327886 or 0. ΔT1x = 0. ΔT2x= 0. ΔT1y= 0. ΔT2y= 1. Δ T1x= 0.638909408(0.01/0.8 + 0.01/cos (37)) = 0. Δ T2x= 0.7756 (0.1/1.6 + 0.02/cos (61)) = 0. ΔT1y= 0.4814 (0.1/0.8 + 0.01/sin (37)) = 0. ΔT2y= 1.3993 (0.1/1.6 + 0.00/sin (61)) = 0. T1x= 0.63 + 0.08 N T2x=0.77 + 0.6 N T1y= 0.48 + 0.06 N T2y= 1.39 + 0.08 N EFx= Tzx – T1x= (0.77 + 0.06) -(0.63 + 0.08) = 0.14 + 0.14 N EFy= Tzy + T1y – Fg= (0.48 + 0.06) + (1.39 + 0.08) -1. = -0.09 + 0.14 N Conclusion