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Polar equations for various conics, including hyperbolas and ellipses, along with the position of their directrixes. Students are asked to identify the type of conic and the location of the directrix based on the given polar equation.
Typology: Exercises
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Identify the conic that the polar equation represents. Also, give the position of the directrix.
r = 9 1 - 3 cos θ A) hyperbola, directrix perpendicular to the polar axis 3 left of the pole B) ellipse, directrix perpendicular to the polar axis 3 left of the pole C) ellipse, directrix perpendicular to the polar axis 3 right of the pole D) hyperbola, directrix perpendicular to the polar axis 3 right of the pole
r = (^2) + 22 sin θ
A) hyperbola, directrix parallel to the polar axis 1 above the pole B) parabola, directrix parallel to the polar axis 1 above the pole C) hyperbola, directrix perpendicular to the polar axis 1 right of the pole D) parabola, directrix perpendicular to the polar axis 1 right of the pole
r = 2 4 - 2 sin θ A) ellipse, directrix perpendicular to the polar axis 1 right of the pole B) ellipse, directrix parallel to the polar axis 1 above the pole C) ellipse, directrix parallel to the polar axis 1 below the pole D) ellipse, directrix perpendicular to the polar axis 1 left of the pole
r = 6 3 - 4 cos θ
A) ellipse, directrix is perpendicular to the polar axis at a distance 32 units to the right of the pole
B) hyperbola, directrix is perpendicular to the polar axis at a distance 3 units to the right of the pole C) hyperbola, directrix is perpendicular to the polar axis at a distance 3 2
units to the left of the pole
D) ellipse, directrix is perpendicular to the polar axis at a distance 3 units to the left of the pole
Discuss the equation and graph it.
-5 -4 -3 -2 -1 1 2 3 4 5 r
5 4 3 2 1
-5 -4 -3 -2 -1 1 2 3 4 5 r
5 4 3 2 1
-5 -4 -3 -2 -1 1 2 3 4 5 r
5 4 3 2 1
-5 -4 -3 -2 -1 1 2 3 4 5 r
5 4 3 2 1
-5 -4 -3 -2 -1 1 2 3 4 5 r
5 4 3 2 1
-5 -4 -3 -2 -1 1 2 3 4 5 r
5 4 3 2 1
Find a polar equation for the conic. A focus is at the pole.
B) r = 2 1 + cos θ
C) r = 2 1 - cos θ
D) r = 2 1 - sin θ
; directrix is perpendicular to the polar axis 2 to the left of the pole
A) r = (^4) - 28 cos θ B) r = (^4) + 24 cos θ C) r = (^4) - 24 cos θ D) r = (^4) + 28 cos θ
Convert the polar equation to a rectangular equation.
A) x2^ = - 4y + 4 B) x2^ = 4y + 4 C) y2^ = - 4x + 4 D) y2^ = 4x + 4
-5 -4 -3 -2 -1 1 2 3 4 5 r
5 4 3 2 1
-5 -4 -3 -2 -1 1 2 3 4 5 r
5 4 3 2 1
vertices 9 2
, π 2
, 3 π 2
-5 -4 -3 -2 -1 1 2 3 4 5 r
5 4 3 2 1
-5 -4 -3 -2 -1 1 2 3 4 5 r
5 4 3 2 1
unit above the pole
vertices 1 2
, π 2
, 3 π 2
-5 -4 -3 -2 -1 1 2 3 4 5 r
5 4 3 2 1
-5 -4 -3 -2 -1 1 2 3 4 5 r
5 4 3 2 1