Understanding Dominant and Recessive Alleles in Population Genetics - Prof. T. Tichnell, Study notes of Introduction to Cultural Anthropology

An introduction to population genetics, focusing on mendelian genetics, punnett squares, pedigrees, codominance, and the hardy-weinberg equilibrium. Learn about dominant and recessive alleles, the role of codominance in creating blended traits, and how the hardy-weinberg equilibrium helps determine the frequency of alleles in a population.

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2011/2012

Uploaded on 01/08/2012

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POPULATION GENETICS
Mendelian Genetics
- Monk in what is now Czech r
-8 years breeding pea plants
- Came up w/ what we now call dominant and recessive alleles
- Dominant Alleles are expressed in an orgs phenotype
while masking the effect of another allele, if that
allele is pres
- Recessive Alleles are expressed only if homozygously
expressed.
Punnett Squares
M
A A
a Aa Aa
F
a Aa Aa
Pedigrees
Codominance
- When more than one allele is dominant
- Both are expressed, creating a blended or mixed trait
Ex: Blood Types
Hardy Weinberg Equilibrium
Hardy and Weinberg recognized that some alleles are in
equilibrium, meaning that they do not change.
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POPULATION GENETICS

Mendelian Genetics

  • Monk in what is now Czech r -8 years breeding pea plants
  • Came up w/ what we now call dominant and recessive alleles
    • Dominant Alleles are expressed in an orgs phenotype while masking the effect of another allele, if that allele is pres
    • Recessive Alleles are expressed only if homozygously expressed. Punnett Squares M A A a Aa Aa F a Aa Aa Pedigrees Codominance
  • When more than one allele is dominant
  • Both are expressed, creating a blended or mixed trait Ex: Blood Types Hardy Weinberg Equilibrium Hardy and Weinberg recognized that some alleles are in equilibrium, meaning that they do not change.

Assumptions

  • No mutation, nat. selection, or gene flow happening
  • Large population
  • Mating is random
  • All member of the pop produce the same number of offspring. Ps & Qs A (p) a(q) A (p) p2 qp a(q) qp q 1 = p2 + 2pq + q so.....1 = p + q (freq. of dominant + recessive) Ex. of the Equation Since X% of our class have hitchhikers thumb, what % of the class are carriers (heterozyg) for the trait? 50% means a freq. of 0. 0.5 = q q = sqr0.5 = 0. p = 1 - 0.71 = 0. Freq. of heterozyg. = 2pq = 2(0.71*0.29) = 0.41 or 41% are carriers.