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Information about linear operators t and s on the hilbert space h = ℓ2(z). How to define and find the adjoints of these operators, and provides examples for bounded and unbounded operators. Students are expected to solve problems related to these concepts.
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Math 6210 - Homework 5 Due at 4 PM on 11/10/
From Rudin: Chapter 5, # 1,2,3,4,
All of the problems will examine linear operators on the Hilbert space H = `^2 (Z). Recall that f ∈ H if f is a function f : Z −→ C
with
n∈Z
|f (n)|^2 < ∞ and the inner product of f, g ∈ H is
(f, g) =
n∈Z
f (n)g(n).
We also recall the definition of the adjoint T ∗^ of a linear operator T. If T is bounded then we saw in class that for any g ∈ H the linear map
f 7 → (T f, g)
is bounded. Therefore there is a unique element g′^ ∈ h such that (T f, g) = (f, g′) for all f ∈ H. We define T ∗g = g′.
If T is unbounded it will in general only be defined on a subspace of H which we denote dom T. Then given any g ∈ H the map f 7 → (T f, g)
is only defined for f ∈ dom T. Furthermore it will not always be bounded. The subset of H where this map is bounded is the domain of the adjoint, dom T ∗. Then for g ∈ dom T ∗^ there is a unique g′^ such that (T f, g) = (f, g′) for all f ∈ dom T. As in the bounded case we set T ∗g = g′.
(a) Show that S is unbounded. (b) Show that
dom S∗^ =
g ∈ H such that
n∈Z
n^2 |g(n)|^2 < ∞
Here are some hints. If the sum is < ∞ apply H¨olders inequality. If the sum is infinite we need to show that g 6 ∈ dom S∗^ by showing that
f 7 → (Sf, g)
is not bounded. To do this define fk ∈ dom S with k a positive integer by
fk(n) =
ng(n) if |n| ≤ k 0 if |n| > k
and observe that (Sfk, g) = ‖fk‖^22. Note that ‖fk‖ → ∞ and therefore
|(Sfk, g)| ‖fk‖ 2
(c) Show that (S∗g)(n) = ng(n) for g ∈ dom S∗. In particular S = S∗^ on dom S (which is contained in dom S∗.) However S is not self-adjoint since S and S∗^ have different domains.