

Study with the several resources on Docsity
Earn points by helping other students or get them with a premium plan
Prepare for your exams
Study with the several resources on Docsity
Earn points to download
Earn points by helping other students or get them with a premium plan
Advanced calculus problem set 8 focusing on metric spaces, completeness, and convergence. Topics include proving equivalence of conditions for a point to be in a subspace, completeness of a metric space implying closedness of a subspace, and convergence of sequences in various metric spaces. The document also covers the heine-borel theorem and properties of vector spaces and linear maps.
Typology: Assignments
1 / 2
This page cannot be seen from the preview
Don't miss anything!


Due: Friday, March 30, 2007
Math 360 - Advanced Calculus / Problem Set 8 (two pages)
Let X, d be a metric space, and A ⊆ X a non-empty subspace. Prove the following: a) For x ∈ X the following are equivalent: i) x ∈ A. ii) ∀ > 0 one has: B(x, ) ∩ A 6 = ∅. iii) ∃ (xn)n, xn ∈ A such that xn → x. b) Suppose that X is complete. Then A is complete ⇐⇒ A is closed in X.
Recall the context from HW #6, Problem 8: We consider X′, d′^ and X′′, d′′^ two metric spaces, and we endow X := X′^ × X′′^ with the metric d, which is either dmax or dsum. Prove the following: a) Let (xn)n be a sequence in X, hence xn = (x′ n, x′′ n) with x′ n ∈ X′, x′′ n ∈ X′′. Then (xn)n is convergent in X ⇐⇒ (x′ n)n and (x′′ n)n are convergent in X′, respectively X′′. b) X is complete ⇐⇒ X′^ and X′′^ are complete.
a) A is bounded ⇐⇒ A is totally bounded. b) Using the facts above and the characterization of compact metric spaces deduce the following fa- mous/important fact:
Let k be a base field. Let V , W be k-vector spaces, and f : V → W a k-linear map, i.e., a morphism of k-vector spaces. Give complete proofs of the following facts mentioned in the class: a) For λ ∈ k and v ∈ V one has: λ · v = 0V ⇐⇒ λ = 0k or v = 0V. b) ker(f ) := {v ∈ V | f (v) = 0W } and im(f ) := f (V ) are k-vector subspaces of V , respectively W. c) f is an isomorphism ⇐⇒ f is bijective, i.e., the inverse map of a bijective k-linear map is again k-linear.
Give complete proofs/answers of the following:
What is the relation between lq and lq′ for q ≤ q′?
Can you describe ker(ϕ)?
Supplement. Recall the (Bolzano–Weierstrass) characterization of compact (subspaces of) metric spaces:
Theorem Let X, d be a metric space, and A ⊆ X a non-empty subset. Then the following are equivalent: i) A is compact. ii) A is totally bounded and complete. iii) Every sequence (xn)n, xn ∈ A, has a convergent subsequence (xkm )m with xkm → x ∈ A as m → ∞.
Complete the proof of iii) ⇒ i) along the following lines: Let {Ui | i ∈ I} be an open covering of X. a) Show that for every Ui ∃ open balls Bi,j := B(xi,j , i,j ), j ∈ Ji, satisfying the following: i) Bi,j ⊆ Ui for all i ∈ I, j ∈ Ji, and Ui = ∪j∈Ji Bi,j. ii) Each i,j is of the form i,j = 1/ni,j for some natural number ni,j > 0. b) For every x ∈ A, let nx = min{ni,j | x ∈ Bi,j }, i.e., 1/nx is the maximal radius of the balls Bi,j which contain x. Show that ∃n 0 > 0 such that 1/nx > 1 /n 0 for all x ∈ A. c) Show that the set {Bi,j | i ∈ I, j ∈ Ji, ni,j < n 0 } is an open covering of A. d) Show that {Bi,j | i ∈, j ∈ Ji, ni,j < n 0 } contains a finite open covering of A, say {Bi 1 ,j 1 ,... , Bin,jn }. e) Show that {Ui 1 ,... , Uin } is a covering of A too.
[Hint: To b): By contradiction, suppose that ∀ n > 0 ∃ xn ∈ A s.t. nxn < n. W.l.o.g., (xn)n is convergent in A (WHY?). If xn → x ∈ A, reach a contradiction (HOW?). To d): By contradiction, suppose that for each m, the set of balls Bi,j with ni,j < n 0 does not contain any covering by m balls, say {Bi 1 ,j 1 ,... , Bim,jm }. Then construct inductively a sequence x 0 ,... , xm ∈ A with d(xk, xl) > 1 /n 0 for all k 6 = l, k, l ≤ m; and get finally a sequence (xm)m, xm ∈ A, which has no convergent subsequences (WHY?).]