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Here are some practice problems for the identities
Typology: Study notes
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Definition 1 For an acute angle α,
b
c a
α
csc α = c a
hypotenuse opposite leg
sec α = c b
hypotenuse adjacent leg
cot α = b a
adjacent leg opposite leg
The three trigonometric functions defined above are just reciprocals of the three others we defined
earlier:
csc α =
sin α sec α =
cos α cot α =
tan α
Exercises
Prove that tan^2 α + 1 = sec^2 α.
Prove that 1 + cot^2 α = csc^2 α.
Verify each of the following identities:
(a) tan θ · csc θ = sec θ
(b) tan^2 x = (sec x + 1)(sec x − 1)