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There are 5 questions on 10 numbered pages, front and back. Check that you have all the pages. When you hand in your exam, make sure your pages are still ...
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Question True/False Complexity Heaps Trees Graphs
Max 10 30 20 20 20 100
Score
Grader
The exam is closed book and closed notes. Do not begin until instructed.
You have 90 minutes. Good luck!
Write your name and Cornell NetID at the top of every page! There are 5 questions
on 10 numbered pages, front and back. Check that you have all the pages. When you
hand in your exam, make sure your pages are still stapled together. If not, please use our
stapler to reattach all your pages!
We have scrap paper available. If you do a lot of crossing out and rewriting, you might
want to write code on scrap paper first and then copy it to the exam so that we can make
sense of what you handed in.
Write your answers in the space provided. Ambiguous answers will be considered incor-
rect. You should be able to fit your answers easily into the space provided.
In some places, we have abbreviated or condensed code to reduce the number of pages
that must be printed for the exam. In others, code has been obfuscated to make the
problem more di cult. This does not mean that its good style.
Academic Integrity Statement: I pledge that I have neither given nor received any
unauthorized aid on this exam.
(signature)
Circle T or F in the table below.
a) T F A method that computes a result in O(n
4 ) time will always run slower than a
method that computes a result in O(n
2 ) time.
b) T F If a graph with n nodes has at least n 1 edges, it is connected.
c) T F The vertices of a finite graph can be topologically sorted if and only if the graph is
acyclic.
d) T F If a graph has thousands of vertices, each having at most 5 neighbors, you should
implement the graph using an adjacency matrix instead of an adjacency list.
e) T F LinkedList
String[] is a subtype of Object[].
f) T F Method m() processes a list of size n using nested for-loops. Therefore, the
runtime of m() can’t be O(n
3 ).
g) T F In the worst case, heap-sort and selection sort have the same run time.
h) T F If a graph is bipartite, it is planar.
i) T F Suppose a and b are objects. If a.equals(b) evaluates to true, then
a.hashCode() == b.hashCode() must evaluate to true.
j) T F Suppose a and b are objects. If a.equals(b) evaluates to false, then
a.hashCode() == b.hashCode() must evaluate to false.
Aren’t
these
the
same?
If a and b are equal, the hash code for the two must be the same or hashing won’t work (see the
lecture notes for more on why). However, if they are not equal, they still might end up with the same
hash code. For example, if we have a class Point which stores x,y coordinates, and hashCode
returns x - y, The points (0, 0) and (1, 1) will both have the same hash code (0) even though they
are not equal.
(d) 6 points For each of the following tasks, state the expected and worst-case time com-
plexity. If the expected and worst-case time complexities are di↵erent, describe a situation in
which the task will take the worst-case time.
(i) (2 points) Use merge-sort to sort an array of size n.
Expected run time: O(n log n) Worst-case run time: O(n log n)
(ii) (2 points) Search for a value in a sorted array of size n.
Expected run time: O(log n) Worst-case run time: O(log n)
(iii) (2 points) Check if a binary search tree of size n contains a particular value.
Expected run time: O(log n) Worst case run time: O(n)
Suppose the binary search tree has all of it’s left pointers equal to null. Then in the
worst case, we have to traverse all n nodes to check if an element is present.
(e) 12 points Suppose we need to choose a data structure to store a changing collection
of values. For each of the usage patterns listed below, mark an “X” in the following table
to indicate which data structure serves that usage pattern best in terms of average-case time
complexity. There is exactly one best data structure for each usage pattern.
Usage Pattern ArrayList LinkedList HashSet Balanced BST Heap
(i) X
(ii) X
(iii) X
(iv) X
(v) X
(vi) X
The usage patterns:
(i) (2 points) Removing certain elements while iterating through all elements (and preserving
the ordering of the remaining elements).
(ii) (2 points) Checking if the collection contains various values
(iii) (2 points) Processing the elements in sorted order
(iv) (2 points) Adding and removing elements from indices clustered near the end of the
collection
(v) (2 points) Retrieving elements at several unpredictable indices
(vi) (2 points) Processing the elements in a priority order
(iv) Indices only makes sense for ArrayList/LinkedList. For a singly linked list,
accessing items at the end takes O(n), while for an ArrayList it is O(1)
(iii) An inorder traversal of a BST will give you sorted order in O(n) time, faster than any other option here.
(vi) “Priority” only make sense for heaps
(v) Basically the same as the answer for (iv)
(ii) Expected time O(1) for a HashSet
(i) Removing items from the middle of the list takes O(1) time in a LinkedList when you are already at the node, since
you just swap some pointers. For an ArrayList removing an item from the middle could take O(n) time because later
items have to be shifted back.
Consider creating a max-heap of ints by adding the following elements in the order presented:
(a) 8 points Below, draw the resulting heap as a tree.
Note: If you provide a valid heap for these values but not the one that arises from adding the
elements in order, you get 2 points and can still get full credit for the subsequent problems.
Solution
(b) 6 points Draw the heap you provided as an array in the table below.
Solution
(c) 4 points Now we change the value of the element with value 27 to 92. Repair the heap
you presented using the operations from class and draw the resulting heap as a tree below.
Note: If you provide a valid heap for these values but not the one that arises from performing
this operation, you get 1 point and can still get full credit for the subsequent problem.
Solution
(d) 2 points Draw the heap you provided as an array in the table below.
Solution
Confused? Search for a Piazza post
called “Prelim 2: Constructing a Heap”.
If it does not exist, create one with that
exact name and ask how heaps are
constructed.
(c) 4 points Draw the BST (binary search tree) resulting from adding the following values
one by one to an empty tree:
r, x, o, t, m, s, p, n
Note: If you provide a valid BST for these values but not the one that arises from adding
the elements in order, you get 1 point.
Solution
r
o x
m
p t
n s
(d) 8 points Now that you have practiced adding values to a BST, implement method add
of class BSTNode below.
/** An instance of this class represents a Binary Search Tree */
public class BSTNode {
private int element; // the element of this BSTNode
private BSTNode left; // left child of this BSTNode (null for an empty tree)
private BSTNode right; // right child of this BSTNode (null for an empty tree)
/** Constructor: a binary search tree containing only v */
public BSTNode(int v) {
element= v;
/** Add v to t and return t. If t is null return a new BSTNode containing v */
public static BSTNode add(int v, BSTNode t) {
if (t == null) return new BSTNode(v);
if (v == t.element) return t;
if (v < t.element) {
t.left = add(v, t.left);
return t;
t.right = add(v, t.right);
return t;
(b) 10 points The graph algorithms we have covered have applications beyond the problems
for which they were originally intended. For example, although DFS and BFS are search
algorithms, they are just ways to traverse a graph. So besides reachability, they can be used
for distance calculation and cycle detection. And, topological sort can be used to determine
shortest paths in DAGs.
For each problem listed below, mark an “X” in the following table to indicate which graph
algorithm solves the problem best in terms of worst-case time complexity. There is exactly one
best graph algorithm for each problem.
Problem Topological sort DFS BFS Dijkstra
(i) X
(ii) X
(iii) X
(iv) X
(v) X
The problems:
(i) (2 points) You are on a bike trip in a park. Your map of the park shows you places to
stop and rest, and you can calculate the distance between any two of them. You can
bike only b miles without stopping at a resting place before you fall over, exhausted, and
every mile takes you 10 minutes to bike. You are standing at the easternmost resting
place. You want to determine how to most quickly reach the westernmost resting place
without getting exhausted.
(ii) (2 points) You are intrigued by the concept of “six degrees of separation”: any two people
on the planet are connected through at most five intermediate acquaintances. You want
to test this theory at Cornell. You have a database that tells you whether any two Cornell
students are friends. You want to find a student who is “furthest away” from you, i.e. the
minimum number of intermediate friends needed to relate that student to you is greater
than or equal to that of any other student.
(iii) (2 points) You are a maze designer, and you want to make sure your preliminary design
isn’t too challenging. Write a program that, assuming there are no cycles, determines
the length of the longest path from the maze’s entrance that doesn’t eventually lead to
the maze’s exit.
(iv) (2 points) You have a list of courses you want to take at Cornell. Some are prerequisites
of others. You want to find a sequence in which to take these classes without violating
any prerequisite requirement.
(v) (2 points) Ithaca has bicycle paths, but not on every road. For each pair of intersections
A and B, your map of Ithaca tells you whether there is a bicycle path from A to B; call
such a path a direct bicicyle path. You have to write a program to calculate the minimum
number of direct bicicyle paths needed to get from one place in Ithaca to another.
10 of 10
(i) In this case, you have a graph of nodes (the oases) with edges (any path between nodes that is at most distance k) with weights (the distance between the nodes) and are
trying to find the shortest path from one node to another. Dijkstra's shortest path algorithm is how we find shortest paths.
(ii) Breadth first search visits all nodes 1 away from the source, then all 2 away, then all 3 away, etc, so it can be used to determine which nodes are furthest away.
(iii) Depth first search allows us to keep track of how many nodes are on the path from the source to the current node, so we can use this information to find the longest
path that doesn't lead to the node's exit.
(iv) Topological sort helps you find an order of the nodes such that all directed edges point forward. Since prerequisites can be modeled as arrows form the prereq to the
course, topological sort will give us an order to take the courses where courses are always after their prereqs.
(v) We're trying to find the minimum number of steps from the source to some target. Since breadth first search visits nodes at distance 1, then 2, then 3, then 4, it is useful
for finding the nodes with the fewest number of trips.