Problem Set #5 - Materials Selection | EMA 4714, Assignments of Materials science

Material Type: Assignment; Professor: Mecholsky; Class: MATERIALS SELECTION; Subject: MATERIALS ENGINEERING; University: University of Florida; Term: Unknown 1989;

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Problem Set 5
EMA 4714 - Materials Selection and Failure Analysis
Due Wednesday, February 28, 2001 - 11:45 am
Dieter Exercise 8.8
In an aerospace application, total cost of a component can be expressed by:
Ct = Cf + CmW + PW
where: Cf = cost of fabrication
Cm = material coast, $/lb
W = weight of component, lb
P = penalty factor by which performance is jeopardized, $/lb
[a] Discuss the various strategies available to minimize Ct.
[b] Determine whether material B can be economically substituted for material A if [1] there is no
weight penalty factor and [2] the weight penallty is $100 per lb.
***************************************************************************
[a] [i] Lower Cf by changing to a lower cost process [or a place where processing costs are lower]
or increase production rate [reducing cost per component].
[ii] Lower material cost [Cm].
[iii] Lower component weight [W] by redesign - involves analysis of function and property
relationship.
[iv] Lower W by selection of alternate [higher strength] material which is likely to be more
expensive. If CB > CA, but WB < WA, selection of material B will be justified when the total
costs of using B are less than those for using A:
CBWB < CAWA
CB < CA[WA/WB]
CB < CA/[1-f]
where f = [WA - WB]/WA
[b] assuming Cf(A) = Cf(B), when weight is penalized [P factor introduced], use of B is justified if:
CBWB + PWB < CAWA + PWA
CB < CA/[1-f] + Pf/[1-f]
f = [90 - 2]/90 = 0.978
2100B901A
W, lbCm, $/lbmaterial
pf3

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Problem Set 5 EMA 4714 - Materials Selection and Failure Analysis Due Wednesday, February 28, 2001 - 11:45 am

Dieter Exercise 8.

In an aerospace application, total cost of a component can be expressed by: Ct = Cf + CmW + PW where: Cf = cost of fabrication Cm = material coast, $/lb W = weight of component, lb P = penalty factor by which performance is jeopardized, $/lb

[a] Discuss the various strategies available to minimize Ct. [b] Determine whether material B can be economically substituted for material A if [1] there is no weight penalty factor and [2] the weight penallty is $100 per lb.

[a] [i] Lower Cf by changing to a lower cost process [or a place where processing costs are lower] or increase production rate [reducing cost per component]. [ii] Lower material cost [Cm]. [iii] Lower component weight [W] by redesign - involves analysis of function and property relationship. [iv] Lower W by selection of alternate [higher strength] material which is likely to be more expensive. If CB > CA, but WB < WA, selection of material B will be justified when the total costs of using B are less than those for using A:

CBWB < CAWA CB < CA[WA/WB] CB < CA/[1-f] where f = [WA - WB]/WA

[b] assuming Cf(A) = Cf(B), when weight is penalized [P factor introduced], use of B is justified if:

CBWB + PWB < CAWA + PWA CB < CA/[1-f] + Pf/[1-f] f = [90 - 2]/90 = 0.

B 100 2

A 1 90

material Cm, $/lb W, lb

[1] with P = 0, use of B is justified when CB < 1/[1-0.978] < $45.

[2] with P =100, use of B is justified when CB < 1/0.022 + [100][0.978]/0.022 = $

Dieter Exercise 8.

Select a group of candidate materials for an energy-storing flywheel using the Ashby charts. First develop the performance index M from the following information about flywheels:

Consider the flywheel to be a solid disk of radius R and thickness t, rotating with an angular velocity ω. The energy stored in the flywheel is:

U = Jω^2 /2 = [1/2][πρR^4 t/2]ω^2

J = polar moment of inertia for the disk

The quantity to be maximized [objective function] is the kinetic energy per unit mass. The maximum stress [constraint] in the spinning disk is given by:

σmax = [(3 + ν)/8]ρR^2 ω^2


flywheel mass, m, = πR^2 tρ Kinetic energy stored, U, = [π/4]ρR^4 tω^2 Objective function, U/m = R^2 ω^2 /4; R^2 = 4[U/m]/ω^2 Constraint, σmax < σt: σ = {(3 + ν)/8}ρR^2 ω^2 ; R^2 = σt/{[(3 + ν)/8][ρω^2 }

Clearing free variable, R, U/m = [2/(3 + ν)][σt/ρ], where M = σσt/ρρ