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Material Type: Assignment; Class: MATH PHYSICS; Subject: Physics; University: University of California - Irvine; Term: Unknown 1989;
Typology: Assignments
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Problems, set 7. PHYSICS 212A: Mathematical Physics
F (x, a) =
∫ (^) ∞
0
e−xt t + a
dt
Write down the nth term of the series, ϕn(x), (numerate term of the series from n = 0). Obtain the remainder term Rn(x) explicitly and find the upper bound on its magnitude. Show that |Rn(x)/ϕn(x)| → 0 as x → ∞.
erfc(x) =
π
∫ (^) ∞
x
exp(−t^2 )dt =
π
exp(−x^2 )
∫ (^) ∞
0
exp(− 2 tx) exp(−t^2 )dt
The “straightforward” Laplace’s method cannot be applied since the maximum of the function in exponential is outside of the range of integration [find where], so the function is maximal at the end point; also the slope of the exponent function is not zero at this end point. Nevertheless, one can apply the ideology of the Laplace’s method here since the contribution of the integrand tends to be confined to the neighborhood of the end point as x → +∞. Expanding exp(−t^2 ) in a power series around the end point, integrate the above expression term by term to obtain an asymptotic expansion for large x. Write 4 non-zero terms. Obtain explicitly the nth term of such an expansion, (with the first term in expansion corresponding to n = 0). Write down explicitly the convergence test. Show whether this asymptotic series is converging or not.
I(x) =
∫ (^1)
0
exp
( ix
( 1 −
sin t t
)) dt
Hint. After expanding the function in exponential about its extremum extend the upper limit of integration to ∞.
I(u) =
∫ (^) ∞
−∞
dx 2 π
sin(x^2 + ux)
Hint. Change sine to exponent, then x → z. Identify saddle point(s) of the function in exponential. Bend the contour so it goes through the saddle point in the “correct” way.
In =
∫ (^1)
− 1
(1 − x^2 )n^ dx
With Mathematica, check the accuracy of the asymptotic results of (a) and (b) for n = 2. Hints. Rewrite the integrand as an exponent of a function. For (a), expand the exponential function near extremum, then show that the limits can be extended to ±∞. For (b), change the variables x → s so the integrand becomes f (s)e−s 2 , same change should ensure the limits extend to ±∞. Expand the prefactor f (s) up to the order needed and integrate term by term.
z^25
. Obtain all the terms upto this order. Observe that the coefficients increase after initial decrease, indicating the series is asymptotic. Hints. Use a[i] instead of A, B, etc. for the coefficients. Use Sum[a[i]/(z+1)i, ...] to generate the unknown power series. Using Series[f(z),{z,Infinity,n}] gives an expansion in powers of 1/z to order n. Normal[...] truncates the series (no O(1/z(n+^1 ))). Coefficient[f,1/z,i] produce coefficient of 1/zi^ in f. Using Solve on the set of equations one can equate all the coefficients in the two series. Using Table[...] one can create a list of equations to be solved.
(^1) from after Eq. 3-86 to the end of the Chapter (for possible variations in the page numeration)