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The steps to solve the projection problem for a given matrix m and its orthogonal complement s. It includes instructions for computing the projection operator p, demonstrating that px = 0 for x ∈ s, and finding the kernel of a given matrix a. Additionally, it covers the relationship between the range and nullspace of a projection operator.
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Math 4404 Projection Operators
Hand in Thursday, July 20
v 1 =
v^2 =
Once you have the matrix P , demonstrate that P x = 0 for x ∈ S by choosing x to be a linear combination of the basis vectors of S, i.e. let x = αw 1 + βw 2 where w 1 and w 2 span S.
and S = M ⊥. Then for v =
(a) Compute what S is. (b) Compute the projection operator P which projects onto M and solves the pro- jection problem. (c) Project v onto M via the matrix P. (d) Compute v − P v and show it is orthogonal to M by taking the inner product with a linear combination of M ’s basis vectors. (e) Plot M , v, P v, and v − P v. Notice how v − P v is actually perpendicular to M. (f) Compute ker(P ). (g) Show that R^3 = ran(P ) ⊕ ker(P ). To do this, show that for any vector x ∈ R^3 that we can show there are vectors v 1 ∈ ran(P ) and v 2 ∈ ran(I − P ) such that x = v 1 + v 2.
Prove your assertion.
< P H^ x, y >=< x, P y >= 0.
It follows from this that ker(P H^ ) ⊂ ran(P )⊥. Given x ∈ ran(P )⊥, show that x ∈ ker(P H^ ). We can conclude form this that ker(P H^ ) = ran(P )⊥.