Quiz 2 with Solution - Electronics I | ECE 340, Quizzes of Basic Electronics

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ECE 340 ELectronics University of Illinois at Chicago Quiz #2 Spring 2012 Name (print), On Pe Amplifier _ Lab: ‘fu8 hil Th2 Problem 1 (5 points) = Consider the following circuit where the opamp is assumed to oie Find voltages Vj, Vo and Vjy, and currents Jy, J2 and Jip. All work must be shown for full credit. ideal opamp assumption —Wvt Wv Since Tp =O, all of the. BV + — oe Tk ma 2mA ges Hhrowgh the ZFS Va pw FHF — 7 “O ai ae | —t—0 Vous Ws (ZmA) (zks) (obras Law ) “ fio = amd ~ V 4 y 2mA co Joker i vo hel op ¥ Vv ~ h ( taea opamp 7 = Pah = Ee aS Semprtion — a” Sisce Va sAy, the voltage Aeros the LED resirtor js 2 V,- dy =34y (wich polarity Shown > due te KVL, 2 Is BV/ikG = Baan (Ams Law ) Since T_=O0 (opamp assmption ) , I, =T, => I,=3mA (Kei) — With Ts, = 3ma ) the veltage @erass the SKS resistor is (3k2)G) dve fy Ohms Law ; Therefore the voltage acess the sha is 9y 5 with polarcty shown. Due to KVL Voce -Vp=4V 5 therefee => Voot= W+V, 2 WV t4ye [BV Using Ohm's Lau Fig = Voot BY Pi ay joka oa loka ~ i6 ’ me Mi ay : ris MHS IK mA mA 3mA g z SI] es s| [Els z a OQ Pama - Ww & 5 x on Zz lof2 Handed out: February 8, 2012