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Quiz 3A Solutions for Basic Physics I | Physics 3, Quizzes of Physics

University of California - Irvine Physics

Material Type: Quiz; Class: BASIC PHYSICS I; Subject: Physics; University: University of California - Irvine; Term: Unknown 1989;

Typology: Quizzes

Pre 2010

Uploaded on 09/17/2009

koofers-user-jaf-1 🇺🇸

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Physics 3A: Basic Physics I

Quiz #3a : Solutions

Name: SolutionsXXXXXXXXXXXXXX__

Student ID #:_________________________

Discussion Section:____________________

Date:________________________________

Signature:____________________________



r



x



i



y



j

vxf



vicos



i



constant

vyf



visin



i



gt

xf



xi



vicos



i



t

yf



yi



vicos



i



t



1

2gt2

ac



v2

r

at



d

 

v



d t

yf





tan



i



xf





g

2vi

2cos2



i



xf

2

T



2



r

v

h



vi

2sin2



i



2g

R



vi

2sin



2



i



g

ar



ac



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v2

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vPO '





vPO



vO' O

g



9.80 m



s2

(circle the letter of your answer)

1. (2 pts) A blue BMW car is driven off a horizontal cliff. One second later a red VW

car is driven off the same cliff with the same velocity as the BMW. At what point in

the motion after the VW leaves the cliff will the VW have a speed faster than the

BMW? Only consider times prior to the BMW hitting the ground. (ignore air

resistance)

a.) Just before the BMW hits the ground

b.) Just as the VW leaves the cliff

c.) When the VW is halfway to the ground

d.) Depends on the relative masses of the two cars

e.) The VW never has a speed faster than the BMW

2. (2 pts) An electron is traveling in a two dimensional plane. If its acceleration vector is

always perpendicular to its velocity and its acceletion vector has a constant magnitude,

what can you say about its motion?

a.) Its velocity vector's direction and magnitude are constantly changing.

b.) Its velocity vector is changing only in magnitude

c.) Its undergoing uniform circular motion.

d.) Its acceleration vector is constant.

e.) None of the above

3. (6 pts) An astronaut is fastened securely to the end of a rotating mechanical arm which

is 15.0 m long. a.) Determine how fast the astronaut needs to be moving (in m/s) to

experience an acceleration of 3.50g. b.) What is the rotation rate (in revolutions per

second) for this speed? (use back of sheet as well, circle your final answer and

show all work)

Discover Quizzes of Physics University of California - Irvine

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Download Quiz 3A Solutions for Basic Physics I | Physics 3 and more Quizzes Physics in PDF only on Docsity!

Physics 3A: Basic Physics I Quiz #3a : Solutions

Name: SolutionsXXXXXXXXXXXXXX__ Student ID #:_________________________ Discussion Section:____________________ Date:________________________________ Signature:____________________________

r x

i

y

j vxf vi cos^

i ^ constant^ vyf vi sin^

i g t x f xi vi cos

i t

y f yi vi cos

i t^

g t^2 ac v

2 r

at

d v

d t

y f

tan^

i x^ f

g 2 vi^2 cos^2

^

i

x (^2) f

T

2 r

v

h

vi^2 sin^2

^

i 2 g

R

vi^2 sin

(^) i g

ar ac

v^2 r

vPO '

vPO vO ' O

g 9.80 m s^2

(circle the letter of your answer)

(2 pts) A blue BMW car is driven off a horizontal cliff. One second later a red VW car is driven off the same cliff with the same velocity as the BMW. At what point in the motion after the VW leaves the cliff will the VW have a speed faster than the BMW? Only consider times prior to the BMW hitting the ground. (ignore air resistance)

a.) Just before the BMW hits the ground b.) Just as the VW leaves the cliff c.) When the VW is halfway to the ground d.) Depends on the relative masses of the two cars e.) The VW never has a speed faster than the BMW

(2 pts) An electron is traveling in a two dimensional plane. If its acceleration vector is always perpendicular to its velocity and its acceletion vector has a constant magnitude, what can you say about its motion?

a.) Its velocity vector's direction and magnitude are constantly changing. b.) Its velocity vector is changing only in magnitude c.) Its undergoing uniform circular motion. d.) Its acceleration vector is constant. e.) None of the above

(6 pts) An astronaut is fastened securely to the end of a rotating mechanical arm which is 15.0 m long. a.) Determine how fast the astronaut needs to be moving (in m/s) to experience an acceleration of 3.50g. b.) What is the rotation rate (in revolutions per second) for this speed? (use back of sheet as well, circle your final answer and show all work)

concept: uniform circular motion.

a.) Use ac

v^2 r

v

ac r^

3.50 g r

v

3.^

15.0 22.6 m s

b.) first compute distance of 1 revolution (1 lap): d 2 r 2

15.0 94.2 m

so v^

22.6 m 1 s

1 rev

Quiz 3A Solutions for Basic Physics I | Physics 3, Quizzes of Physics

Related documents

Partial preview of the text

Download Quiz 3A Solutions for Basic Physics I | Physics 3 and more Quizzes Physics in PDF only on Docsity!

r x

j vxf vi cos^

i ^ constant^ vyf vi sin^

i g t x f xi vi cos

y f yi vi cos

g t^2 ac v

at

d v

y f

i x^ f

^

T

2 r

h

^

R

ar ac

vPO '

vPO vO ' O

g 9.80 m s^2

a.) Use ac

v

ac r^

v

3.^

15.0 22.6 m s

b.) first compute distance of 1 revolution (1 lap): d 2 r 2

15.0 94.2 m

so v^

94.2 m

0.240 rev s

Quiz 3A Solutions for Basic Physics I | Physics 3, Quizzes of Physics

Related documents

Partial preview of the text

Download Quiz 3A Solutions for Basic Physics I | Physics 3 and more Quizzes Physics in PDF only on Docsity!

r x

j vxf  vi cos^

i ^ constant^ vyf  vi sin^

i  g t x f  xi vi cos

y f  yi vi cos

g t^2 ac  v

at 

d v

y f 

i  x^ f

^

T 

2  r

h 

^

R 

ar  ac 

vPO ' 

vPO vO ' O

g  9.80 m s^2

a.) Use ac 

v 

ac r^ 

v 

3.^

15.0  22.6 m s

b.) first compute distance of 1 revolution (1 lap): d  2  r  2

15.0  94.2 m

so v^ 

94.2 m 

0.240 rev s

j vxf vi cos^

i ^ constant^ vyf vi sin^

i g t x f xi vi cos

y f yi vi cos

g t^2 ac v

at

d v

y f

i x^ f

^

T

2 r

h

^

R

ar ac

vPO '

vPO vO ' O

g 9.80 m s^2

a.) Use ac

v

ac r^

v

15.0 22.6 m s

b.) first compute distance of 1 revolution (1 lap): d 2 r 2

15.0 94.2 m

so v^

94.2 m

0.240 rev s