Review Sheet for Statistical Methods for Bioscience I | STAT 571, Study notes of Data Analysis & Statistical Methods

Material Type: Notes; Class: Statistical Methods for Bioscience I; Subject: STATISTICS; University: University of Wisconsin - Madison; Term: Fall 2003;

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Stat 571 Discussion #4 Fall, 2003
Review
1. The mean and variance of XBinomial(n,p) are E(X) = np, V ar(X) = np(1 p).
2. If X1,X2, ..., Xnconstitute a random sample from a distribution with mean µand variance
σ2, then:
E(¯
X) = µand V ar(¯
X) = σ2/n
E(
n
X
i=1
Xi) = and V ar(
n
X
i=1
Xi) = 2
3. Let random sample X1, X2,···, XnN(µ, σ2), then random variables ¯
Xand Pn
i=1 Xiare
distributed as
¯
XN(µ, σ2
n) and
n
X
i=1
XiN(nµ, 2).
4. Central Limit Theorem
For a random sample X1, X2,···, Xn(when n is large) from an arbitrary distribution with
mean µand variance σ2,¯
Xwill be approximately distributed by ¯
XN(µ, σ2
n) .
5. Let XB(n, p), then the normal approximation for Xis
XN(np, np(1 p)).
The proportion Y=X
ncan be approximated by a normal distribution N(p, p(1 p)/n).
The requirement is that np 5 and n(1 p)5 for both approximations.
6. Let random sample X1, X2,···, XnN(µ, σ2), then random variable
V2=(n1)S2
σ2χ2
n1,
where S2is the sample variance defined as S2=1
n1Pn
i=1(Xi¯
X)2.
Practice Problem
1. Suppose the random variable X is distributed as N(100,144).
(a) Consider a random sample with n= 16, what is the distribution of ¯
X=1
16 P16
i=1 Xi?
(b) Find out Pr( ¯
X < 103).
(c) What is the distribution of P16
i=1 Xi?
(d) How large does nhave to be in order that V ar(¯
X) = 1 ?
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Review

  1. The mean and variance of X∼ Binomial(n,p) are E(X) = np, V ar(X) = np(1 − p).
  2. If X 1 , X 2 , ..., Xn constitute a random sample from a distribution with mean μ and variance σ^2 , then: E( X¯) = μ and V ar( X¯) = σ^2 /n

E(

∑^ n i=

Xi) = nμ and V ar(

∑^ n i=

Xi) = nσ^2

  1. Let random sample X 1 , X 2 , · · · , Xn ∼ N (μ, σ^2 ), then random variables X¯ and ∑ni=1 Xi are distributed as X¯ ∼ N (μ, σ^2 n )^ and

∑^ n i=

Xi ∼ N (nμ, nσ^2 ).

  1. Central Limit Theorem For a random sample X 1 , X 2 , · · · , Xn (when n is large) from an arbitrary distribution with mean μ and variance σ^2 , X¯ will be approximately distributed by X¯ ∼ N (μ, σ n^2 ).
  2. Let X ∼ B(n, p), then the normal approximation for X is

X ∼ N (np, np(1 − p)).

The proportion Y = X n can be approximated by a normal distribution N (p, p(1 − p)/n). The requirement is that np ≥ 5 and n(1 − p) ≥ 5 for both approximations.

  1. Let random sample X 1 , X 2 , · · · , Xn ∼ N (μ, σ^2 ), then random variable

V 2 = (n^ −^ 1)S

2 σ^2 ∼^ χ

(^2) n− 1 ,

where S^2 is the sample variance defined as S^2 = (^) n^1 − 1 ∑ni=1(Xi − X¯)^2.

Practice Problem

  1. Suppose the random variable X is distributed as N (100, 144).

(a) Consider a random sample with n = 16, what is the distribution of X¯ = 161 ∑^16 i=1 Xi? (b) Find out Pr( X <¯ 103). (c) What is the distribution of ∑^16 i=1 Xi? (d) How large does n have to be in order that V ar( X¯) = 1?

  1. Suppose that 20% of the trees in a forest are infected with a certain type of parasite. Let X denote the number of trees having the parasite in a random sample of 300 trees.

(a) Compute Pr(49 ≤ X ≤ 71). (b) Define Y to be the proportion of trees having parasite: Y = X/300.Find Pr(Y < 0 .25).

  1. Suppose we have observations from a N (μ, σ^2 ) distribution. Compute the following:

μ σ^2 n a Pr(S^2 ≤ a) b P r(S^2 ≥ b) − 24 20 11 7 9 250 7 29. 025. 6 8 8. 5. 95

  1. There are two coins, a green one and a red one. The green coin is fair(probability of heads is 0.5), whereas the red coin has probability of heads equal to 0.8.

(a) Suppose the green coin is flipped independently twice and the red coin is flipped once. Assume that the flips of the green and red coins are independent of each other. Find the probability that the total number of heads is exactly 2. (b) Let X be the total number of heads from the 4 flips. Find the probability distribution of X. (c) Find the expected value of X and the variance of X.