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During the study of discrete mathematics, I found this course very informative and applicable.The main points in these lecture slides are: Set Builder Notation, Universal Set, Power Set and Cardinality, Set Operations, Set Identities, Cartesian Product, Set Theory, Unordered Collection of Elements, Empty Set, Elements of Sets, Proper Subsets
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Set Theory Set Builder Notation Universal Set Power Set and Cardinality Set Operations Set Identities Cartesian Product
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Universal Set is the set containing all the objects under consideration.
It is denoted by U
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Set Builder Notation
Set Builder – characterize the elements in a set by stating the properties that the elements must have to belong to the set.
{ x | P (x) }
reads x that satisfy P(x), x such that P(x) x belongs to a universal set U.
concise definition of a set
Examples:
P = { x | x is prime number} U : Z + M={ x | x is a mammal} U: All animals Q+^ = { x ∈ R | x = p/q, for some positive integers p, q }
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A ⊆ B means “A is a subset of B” or, “B contains A”
“every element of A is also in B” or, ∀x ((x ∈ A) → (x ∈ B))
A ⊆ B means “A is a subset of B” B ⊇ A means “B is a superset of A”
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A ⊆ B means “A is a subset of B”
For Every Set S,
i) ∅ ⊆ S the empty set is a subset of every set
ii) S ⊆ S every set is a subset of itself
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A = B if and only if A and B have exactly the same elements.
iff, A ⊆ B and B ⊆ A iff, A ⊆ B and A ⊇ B iff, ∀x ((x ∈ A) ↔ (x ∈ B)).
To show equality of sets A and B, must prove both:
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Given N = {0,1,2,3,…}, | N | is infinite (natural nos.)
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Its first element is a 1. Its second element is a 2 , etc. Enclosed between parentheses (list not set).
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A x B = { (a, b) | a ∈ A ∧ b ∈ B}
Example: A= {a, b}, B= {1, 2} A × B = {(a,1), (a,2), (b,1), (b,2)} B × A = {(1,a), (1,b), (2,a), (2,b)} Not commutative!
In general, A 1 x A 2 x … x A (^) n = {(a 1 , a 2 ,…, an) | a 1 ∈ A 1 , a 2 ∈ A 2 , …, an ∈ An} |A 1 x A 2 x … x A (^) n| = |A 1 | x |A 2 | x … x |A (^) n|
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A ∩ B = { x | x ∈ A ∧ x ∈ B}
Example: A = {1,2,3}, B = {1,6} A ∩ B = {1}
intersection is empty.
Example: A = {1,2,3}, B = {9,10}, C = {2, 9} A and B are disjoint sets, but A and C are not
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Once
twice
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The set difference, A - B, is:
A - B = { x | x ∈ A ∧ x ∉ B }
Example:
It is not commutative!!