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This assignment solution was submitted to Amar Sharma for Finite Element Method course at Aligarh Muslim University. It includes: Shape, Function, Simple, Element, Equations, Putting, Values, Determine, Three-dimensional
Typology: Exercises
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Determine the shape function of a 3-D simple element: ɸ = a 1 +a 2 x+a 3 y+a 4 z ɳT= { 1 x y z } [N] = [Ni Nj Nk Nl] [NT] = { Ni Nj Nk Nl} Ni [N] = Nj Nk Nl Ni ʃNNtds = ʃʃʃvNNTdV = ʃʃʃv Nj [Ni Nj Nk Nl] dV Nk Nl ʃʃʃv(Ni^2 Nj^2 Nk^2 Nl^2 )dV As Ni=L 1 Nj = L 2 Nk = L 3 Nl = L 4 ʃʃʃv L 12 L 22 L 32 L 42 dV According to Equation 3. ʃʃʃv L 12 L 22 L 32 L 42 dV = α!β!ϒ!δ!6V/(α+β+ϒ+δ+3)! Putting the above values we have 2!2!2!2!6V/(2+2+2+2+3)!