slides about physics - motion, Slides of Physics

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VECTORS
ARMANDO A. CAMAÑA JR., MAED, LPT
SHS INSTRUCTOR
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VECTORS

ARMANDO A. CAMAÑA JR., MAED, LPT SHS INSTRUCTOR

In Physics, physical

quantities can be

described by their

measures and is classified

as scalar quantity or vector

quantity.

Vector Quantity  (^) are quantities that described by their magnitude and direction.  (^) are used to represent things that we cannot see like a force exerts or velocity of a moving car.  (^) Vectors can be represented by an arrow. It also uses a scale in graphical solution.  (^) is the symbol to represent a vector.  (^) examples: Force downward͵ velocity of a car moving east͵ displacement of a pencil thrown upward ͵ acceleration towards the west.

Arrow tail – tells the origin of the vector  Arrow head – tells the direction of the vector  Length of the Arrow – is the magnitude of the vector

Source: https://www.mathsisfun.com/algebra/trigonometry.html

 Finding the Height of a Building. Given 67.2m adjacent to the angle of reference. Find the height of the building. With an angle of elevation of 50 degrees.  Finding the angle of reference:

Fundamentals in direction with respect to horizontal axis

5N, 48 degrees East of North 5N, 42 degrees North of East

When two given vectors are acting in the opposite direction. 

To find the magnitude and direction of
the resultant.

Subtract the magnitude of the two
vectors to get the resultant.

For the direction͵ follow the direction of
the larger magnitude.

When two vectors forming an angle 90 ᵒ with another To find the magnitude and direction of the resultant.  The diagonal form by the two vectors is the resultant.  Use Pythagorean theorem (R^2 = c^2 = a^2 + b^2 ) to find  Magnitude of the resultant.  For the direction: use SOHCAHTOA

Problem Solving:  (^) Two SHS students are walking in the corridor towards East. One has a velocity of 25 m/s and the other is 18 m/s. Calculate the magnitude and direction of the Resultant.  (^) Given: V 1 = 25 m/s East^ and V 2 = 18 m/s East  (^) Solution. R = V 1 + V 2 =^ 25 m/s, E^ +^18 m/s, E  (^) Resultant , R = 43 m/s East ( mag. and dir.)

Problem Solving:  From the library door, a SHS students walk 7 meters west towards the next room and other student walks 15 meters east to the computer room. Calculate the magnitude and direction of the resultant displacement of the two students.  (^) Given: d 1 = 7 m west and d 2 = 15 m east  (^) Solution. R = d 2

  • d 1 = 15 m, E – 7 m, W  Resultant , R = 8 m East (mag. and dir.)

Problem Solving: A car moves 5 km east and turns 45 ᵒ N of E for another 3.25 km before coming to stop. Using the above figure, find the magnitude and direction of the resultant displacement of the car.

Now try this! A tennis ball rolls 10 meters east when it hits a stone that turns the ball 80 ᵒ N of W rolling for another 15 m. Calculate magnitude and direction of the resultant displacement of the tennis ball.