Snubber Development II-Advanced Physics-Project Presentation, Slides of Advanced Physics

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 Introduction

 Snubber Development

 Types of Snubber

 Principle of operation of Mechanical Snubber

 Modification of the Test Rig

 Pro E Model of Snubber test Rig

 Designing of the main components

 Summary and Conclusions

 Future Work

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Presentation Layout

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 Snubbers traces its history back to 1955-1960 when focus were given to the fact that to utilize the huge amount of energy with in fissile elements for peaceful purposes

 There is a tremendous amount of heat with in the core of nuclear reactor

 To remove this heat and make possible the safe operation of the plant pumps having 96000 gallons per minute discharge are used

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Snubber Development

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Snubber Development (Contd..)

 Due to this high discharge vibration are produced in the primary loop

 Shock loads are also induced as a result of earth quack

 So in order to protect the equipments from these tremendous amount disturbing forces snubber were developed

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 Snubber has the following types

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Types of Snubber

Mechanical

Hydraulic

Mechanical Snubber having Pallets

Adjustable Hydraulic Snubber

Rotary Type Snubber

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Tabular Member Gears

Snubber Casing

Sliding Way

Pallet Member

End Attached^ Rack to Pipe

Mechanical Snubber

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Exploded View of Mechanical Snubber

Rack

Pallet

Shaft

Escapement Wheel

Bolts

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Lever Arm

Housing

Fixed External Structure

Pipe

Clamp

Connecting Link

Bearing Shaft

Gear

Pallet

Escapement Wheel

Pinion

Rotary Snubber

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 Due to certain limitation of this type of design the test rig is now changed

 This crank type of machine can not be used in the high load application

 Misalignment of the snubber can also take place

 Controlling the speed of the motor to the desired limits is also a problem

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Modification

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Working Mechanism of Test Rig

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Available Data

 Outer diameter =0.089 m  Wall thickness=0.015 m  Inner diameter=0.058 m  Area of the cylinder =2.68 ×10-3^ m^2  Force to be transmitted=735.75 N as  Pressure= Force /Area  Pressure =274.62 KN/m^2

 t ≥ d/  0 .015 m ≥ 0.003 m

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Stress in the Cylinder

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pi = internal pressure in the tube or cylinder (KPa) po = external pressure in the tube or cylinder (KPa) ri = internal radius of tube or cylinder (m) ro = external radius of tube or cylinder (m)

Stress are lees than the yield Stress so design is safe

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