Solutions for Assignment 3 - Solid State Nanoelectronics | ELEG 667, Assignments of Electrical and Electronics Engineering

Material Type: Assignment; Class: ELECTRIC POWER II; Subject: Electrical Engineering; University: University of Delaware; Term: Fall 2005;

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ELEG 667–016; MSEG-667-016 - Solid State Nanoelectronics – Fall 2005
Solution
Homework #3 - due Thursday, 22 September 2005, in class
1. Ferroelectric criterion for atoms: Consider a system of two neutral atoms separated by a
fixed distance a, each atom having a polarizability α. Find the relation between a and α for such
a system to be ferroelectric. Hint: The dipolar field is strongest along the axis of the dipole.
2. Saturation polarization at Curie point: In a first-order transition, the equilibrium condition:
(T-Θ)/C |g4|Ps2 + g6Ps4 = 0
with T set equal Tc gives one equation for the polarization Ps(Tc) at the transition temperature. A
further condition at the Curie point is that F(Ps,Tc) = F(0,Tc).
(a) Combining these two conditions, show that Ps2(Tc) = 3|g4| / 4g6.
(b) Using this result, show that Tc = Θ + 3 C g42 / 16g6.
Solutions:
1. For field along z axis due to p1; Ez(at p2) = 2p1/a3. p2 = αEz = 2αp1/a3. This has solution p1 = p2
0 if 33
1
2a; a
2
α= α= .
2. (a). One condition is, from the minimization,
()
24
C0 4s 6s
TT gP gP 0.γ− + =
The other condition is
()
246
c0s 4s 6s
111
TTP gP gP 0.
246
γ− + =
Thus
24 2 4
4s 6s 4s 6s
11
gP gP gP gP;
23
−+= +
22
4
6s 4 s
6
g
21 3
gP g ; P .
32 4g
==
(b) From the first line of part (a),
()
22
2
444
c0
666
ggg
39 3
TT .
4g 16g 16g
γ− = =

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ELEG 667–016; MSEG-667-016 - Solid State Nanoelectronics – Fall 2005

Solution

Homework #3 - due Thursday, 22 September 2005, in class

  1. Ferroelectric criterion for atoms: Consider a system of two neutral atoms separated by a

fixed distance a , each atom having a polarizability α. Find the relation between a and α for such

a system to be ferroelectric. Hint: The dipolar field is strongest along the axis of the dipole.

  1. Saturation polarization at Curie point: In a first-order transition, the equilibrium condition:

(T-Θ)/C − |g 4 |Ps

2

  • g 6 Ps

4 = 0

with T set equal Tc gives one equation for the polarization Ps (Tc) at the transition temperature. A

further condition at the Curie point is that F(Ps ,Tc) = F(0,Tc).

(a) Combining these two conditions, show that Ps

2 (Tc) = 3|g 4 | / 4g 6.

(b) Using this result, show that Tc = Θ + 3 C g 4

2 / 16g 6.

Solutions:

  1. For field along z axis due to p 1 ; Ez(at p 2 ) = 2 p 1 /a

3

. p 2 = αEz = 2α p 1 /a

3

. This has solution p 1 = p 2

≠ 0 if

2 a ; a 2

α = α =.

  1. (a). One condition is, from the minimization,

2 4 γ TC − T 0 − g 4 Ps + g P 6 s =.

The other condition is

2 4 6 c 0 s 4 s 6 s

T T P g P g P 0. 2 4 6

γ − − + =

Thus

2 4 2 4 4 s 6 s 4 s 6 s

g P g P g P g P ; 2 3

2 2 4 6 s 4 s 6

2 1 3 g g P g ; P. 3 2 4 g

(b) From the first line of part (a),

(^2 2 ) (^4 4 ) c 0 6 6 6

3 g^9 g^3 g T T. 4 g 16 g 16 g

γ − = − =