Prepare for your exams
Get points
Guidelines and tips
Sell on Docsity
Docsity AI

Prepare for your exams

Study with the several resources on Docsity

Earn points to download

Earn points by helping other students or get them with a premium plan

Guidelines and tips

Sell on Docsity

Docsity AI

Prepare for your exams

Study with the several resources on Docsity

Find documents

Prepare for your exams with the study notes shared by other students like you on Docsity

Search for your university

Find the specific documents for your university's exams

Docsity AINEW

Summarize your documents, ask them questions, convert them into quizzes and concept maps

Explore questions

Clear up your doubts by reading the answers to questions asked by your fellow students

Earn points to download

Earn points by helping other students or get them with a premium plan

Share documents

20 Points

For each uploaded document

Answer questions

5 Points

For each given answer (max 1 per day)

All the ways to get free points

Get points immediately

Choose a premium plan with all the points you need

Study Opportunities

Choose your next study program

Get in touch with the best universities in the world. Search through thousands of universities and official partners

Community

Ask the community

Ask the community for help and clear up your study doubts

Free resources

Our save-the-student-ebooks!

Download our free guides on studying techniques, anxiety management strategies, and thesis advice from Docsity tutors

Solved Examples on the Power System Stability | ECE 504, Study notes of Electrical and Electronics Engineering

University of Idaho (U of I)Electrical and Electronics Engineering

Material Type: Notes; Class: ST:Control Systems and Critical Infrastructures; Subject: Electrical & Computer Engr; University: University of Idaho; Term: Spring 2007;

Typology: Study notes

Pre 2010

Uploaded on 08/19/2009

koofers-user-le0 🇺🇸

(1)

10 documents

1 / 3

This page cannot be seen from the preview

Don't miss anything!

ECE 504 ST:

Power System Stability Example 12.3 University of Idaho

Session 38d

Rfd 0.0006:= LLfd 0.153:=

Given: P 0.9:= Q 0.3:= Vas 1.0 ej36⋅deg⋅

⋅:=

Steady State

Small Signal

Ksdinc 1

sat Asat

⋅eBsat Ψat0 ΨTI

−

()

⋅

⋅+

:= Ksdinc 0.4337=

Ksqinc Ksdinc

RE0:=

RTRaRE

+:= RT310

3−

×=

XE0.65:=

Lmdi Ksdinc Lmdu

⋅:= Lmdi 0.7156=

Lmqi Ksqinc Lmqu

⋅:= Lmqi 0.694=

Ldi Lmdi LL

+:= Ldi 0.8756=

Lqi Lmqi LL

+:= Lqi 0.854=

kVA kW:= MVA 106W:= rev 1:= j1−:= mΩ10 3−Ω⋅:=

ORIGIN 1:=

Example 12.3 All values are in pu unless noted otherwise.

Xdu 1.81:= Xqu 1.76:= Xdp 0.3:= XL0.16:=

Ra0.003:= Tdop 8.0 sec⋅:= H 3.5:= KD0.0:=

Asat 0.031:= Bsat 6.93:= ΨTI 0.8:= Ldp Xdp

Lmdu 1.65:= Lmqu 1.60:= LLXL

:= Xs0.65:=

C:\JLAW\CLASSES\S07 ECE 504

\HANDOUTS\Small Signal

\s38d.mcd

Page 1 of 3 April 20, 2007

Discover Study notes of Electrical and Electronics Engineering University of Idaho (U of I)

Partial preview of the text

Download Solved Examples on the Power System Stability | ECE 504 and more Study notes Electrical and Electronics Engineering in PDF only on Docsity!

Power System Stability Session 38d

R

:= 0.0006 L

Lfd

Given: (^) P := 0.9 Q := 0.3 V as

1.0 e

j 36⋅ ⋅deg := ⋅

Steady State

Small Signal

K

sdinc

1 B

sat

A

sat

⋅ e

B sat

Ψ at

Ψ TI

−

⋅

K

sdinc

K

sqinc

K

sdinc

R

E

R

T

R

E

:= + R

T

− 3 = ×

X

E

L

mdi

K

sdinc

L

mdu

:= ⋅ L

mdi

L

mqi

K

sqinc

L

mqu

L

mqi

L

mdi

L

:= + L

L

mqi

L

:= + L

kVA := kW MVA 10

6 := W rev := 1 j := − 1 mΩ 10

− 3 := ⋅Ω

ORIGIN := 1

Example 12.3 All values are in pu unless noted otherwise.

X

:= 1.81 X

:= 1.76 X

:= 0.3 X

L

R

:= 0.003 T

dop

:= 8.0 sec⋅ H := 3.5 K D

A

sat

:= 0.031 B

sat

TI

:= 0.8 L

X

L

mdu

:= 1.65 L

mqu

:= 1.60 L

L

X

L

:= X

C:\JLAW\CLASSES\S07 ECE 504

\HANDOUTS\Small Signal

Page 1 of 3 April 20, 2007

Power System Stability Session 38d

a 3 3,

− 2 ⋅ 60 ⋅ πR fd

L

Lfd

L

mdpi

L

Lfd

− m 2

L

mdpi

a := ⋅ 3 2,

− 2 ⋅ 60 ⋅ πR fd

L

Lfd

m 1

⋅ L

mdpi

a := ⋅ 3 1,

a 2 3,

a := 0 2 2,

a := 0 2 1,

:=2 60⋅ ⋅π

a 1 3,

K

2 H⋅

a := 1 2,

K

2 H⋅

a := 1 1,

K

D

2 H⋅

K

K =0.

n 2

L

mqi

I

⋅ m 2

L

mdpi

I

L

mdpi

L

Lfd

I

K

K =0.

n 1

L

mqi

I

⋅ m 1

L

mdpi

I

n 2

n =0. 2

R

T

D

L

mdi

L

mdi

L

Lfd

m 2

m =0. 2

X

D

L

mdi

L

mdi

L

Lfd

n 1

n =0. 1

E

B

R

T

sin δ 0

⋅ X

cos δ 0

D

m 1

m =1. 1

E

B

X

sin δ 0

⋅ R

T

cos δ 0

D

D R

T

2 X Tq

X

X =0.

X

E

X

mdpi

+ X

L

X

mdpi

L

mdpi

X

X =1.

X

E

X

L

mdpi

X

L

X :=

L

X

mdi

L

mdi

L

mdpi

L

mdi

L

Lfd

C:\JLAW\CLASSES\S07 ECE 504

\HANDOUTS\Small Signal

Page 2 of 3 April 20, 2007

Solved Examples on the Power System Stability | ECE 504, Study notes of Electrical and Electronics Engineering

Related documents

Partial preview of the text

Download Solved Examples on the Power System Stability | ECE 504 and more Study notes Electrical and Electronics Engineering in PDF only on Docsity!

R

:= 0.0006 L

K

1 B

A

K

K

K

R

E

R

T

R

R

E

:= + R

T

X

E

L

K

L

:= ⋅ L

L

K

L

L

L

L

L

L

:= + L

L

L

L

L

:= + L

ORIGIN := 1

Example 12.3 All values are in pu unless noted otherwise.

X

:= 1.81 X

:= 1.76 X

:= 0.3 X

L

R

:= 0.003 T

A

:= 0.031 B

TI

:= 0.8 L

X

L

:= 1.65 L

:= 1.60 L

L

X

L

:= X

L

L

L

L

L

⋅ L

K

2 H⋅

K

2 H⋅

K

D

2 H⋅

K

K =0.

L

I

L