Solving Applications Systems - Intermediate Algebra - Solved Assignment, Exercises of Algebra

Its the important key points of solved assignment of Intermediate Algebra are:Solving Applications Systems, Solving Applications, Solving by Elinimation, Solving Quadratic Equations, Solving Applications by Factoring, Solving Systems by Substitution, Solving Application Problems

Typology: Exercises

2012/2013

Uploaded on 01/07/2013

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Intermediate
Algebra
Name
Chapter
4.3:
Solving
Applications
of Systems of
Linear
Equations in 2 Variables J4
1. The combined
land
area of
my
neighbor's property and mine
is
139,973
square
feet.
The difference
between the two
land
areas
of our properties is 573
square
feet.
If
my
neighbors have the larger
land
area, determine the
land
area of each of our properties.
^ - A
LetA_
=
m\6 \m
\^^Ad1bcf
^
Let
- a\>a ^
w^u^
^:?\rprVu^
V^M;'^
-
Equattbns:
i:
^
Answers:
69,700
sq.
ft. =
my property
70,273
sq.
ft. =
my neighbor's property
2.
At
a
professional
football
game, the cost of
2
bottles of water and 3 pretzels is $16.50. The cost of
4
bottles of water and 1 pretzel is $15.50. Determine the cost of
a
bottle of water and the cost of a pretzel.
Let
y
=
cm 4 \T hc^'i
Let
ti, =
cr.S\^ \
Equat
"7*
Answers:
$3 =
water bottle
$3.50
= pretzel
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Intermediate Algebra Name Chapter 4.3: Solving Applications of Systems of Linear Equations in 2 Variables

J

  1. The combined land area of my neighbor's property and mine is 139,973 square feet. The difference between the two land areas of our properties is 573 square feet. If my neighbors have the larger land area, determine the land area of each of our properties. ^ - A

Let A_ = m\6 \m ^^Ad1bcf ^

Let - a>a ^ w^u^ ^:?\rprVu^ V^M;'^ -

Equattbns:i:

^

Answers: 69,700 sq. ft. = my property 70,273 sq. ft. = my neighbor's property

  1. At a professional football game, the cost of 2 bottles of water and 3 pretzels is $16.50. The cost of 4 bottles of water and 1 pretzel is $15.50. Determine the cost of a bottle of water and the cost of a pretzel.

Let y = cm 4 \T hc^'i

Let ti, = cr.S^ \

Equat

"7*

Answers: $3 = water bottle $3.50 = pretzel

  1. Say you have a 512-MB memory card and a 4-GB memory card for your digital camera. Together the two memory cards can store a total of 1042 photos. The 4-GB memory card can store 10 more than seven times the number of photos the 512-MB memory card can store. How many photos can each memory card store?

Equation.

Let X = mtftotc xJao \D5 5^-^^5 cm stc<Y,

Answers: 129 photos = 512-MB 913 photo = 4-GB

  1. A rowing team, while practicing, rowed an average of 16.7 miles per hour with the current and 9.7 miles per hour against the current. Determine the team's rowing speed in still water and the speed of the current. ^

L e t X - vaa'ocj yyrUn •3'i\

Equations:

z

Answers: 13.2 mph = the team's rowing speed in still water 3.5 mph = the speed of the current

  1. A guy and a girl were hanging out in Santa Cruz. Afterwards, the girl drives home to Scotts Valley at an average speed of 60 miles per hour and the guy drives home to Watsonville at an average speed of 50 miles per hour. If the sum of their driving times is 0.56 hours and if the sum of the distances driven is 30 miles determine the time each person spent drivijig home.

L e t ^ = _

Let V>=

Equations:

1C ^

Answers: 0.36 hours = the guy 0.2 hours = the girl's time

- s t i i n e - r - r

  1. Job A pays an armual salary of $38,000 with a pay increase of $1000 each year. The annual salary for Job A , v4 (0,is the function^(/) = 1000r +38000, where t is the number of years since 2010. Job B pays an annual salary of $45,500 with a pay increase of $500 each year. The annual salary for Job B, B(t),is the function 5(0 = 500? + 45500, where / is the number of years since 2010. Solve the system of equations to determine the year both salaries will be the same. What will be the salary in that year?

Answer: In 2025 both salaries will be $53,000 per year