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Material Type: Notes; Professor: Anlage; Class: Quantum Physics II; Subject: Physics; University: University of Maryland; Term: Unknown 1989;
Typology: Study notes
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Lecture 11 Highlights
We considered the spin-orbit interaction in Hydrogen. The objective is to calculate the āfine-structureā energy splitting due to the spin-orbit effect. The magnetic moment of the electron interacts with the magnetic field created by the proton to produce
a small energy difference between the L
r parallel to S
r and L
r anti-parallel to S
r
situations for the atom. This difference is due to āspin-orbit coupling.ā As discussed in Griffiths page 271 the magnetic field experienced by the electron is given (classically) by:
2 3 (^80)
mcr
eL
r r = ,
where e is the electronic charge, is the electron mass, c is the speed of light in vacuum, and
m r is the proton-electron distance. Note that the magnetic field is parallel to the electron orbital angular momentum vector. To see why, consider things from the protonās rest frame as the electron moves with velocity v
r through the static electric field E
r produced by the proton. It will experience an effective magnetic field given by
E c
v B
r r r = ā Ć (from relativity). By comparing the direction of this field with the direction
of the angular momentum of the electron in its orbit about the proton, this argument
shows that B
r is parallel to L
r . The magnetic moment of charged āspinningā particles is given by: S^ ,
r^ r μ = γ
where γ is called the gyromagnetic ratio. It relates the gyration (or rotation) of the
particle (as embodied in S
r ) to the magnetic moment developed ( μ
r ). A moving charge
creates a magnetic field. A charge moving in a āsmallā current loop can be treated as a magnetic moment, or magnetic dipole, at least for distances large compared to the diameter of the current loop. For the electron the gyromagnetic ratio is found to be
e
e m
e
result. For heavier particles like the proton the gyromagnetic ratio is much smaller due to the larger mass in the denominator and the fact that angular momentum is quantized and of order h for all particles. This fact allows us to ignore the interaction of the protonās magnetic moment with the magnetic field created by the electron, at least for now. The electronās magnetic moment experiences a torque due to its motion around the proton. There is a perturbing interaction energy given by;
so^ B
r r
which becomes;
S L mc r
eL S m
e so
r r r r āā ⢠ā
This new operator S L
r r
S^2 S^ r^ or L^ r^ (Homework 4). This means that S^ r^ and L^ r^ are no
longer āconstants of the motionā under the perturbed Hamiltonian (this follows
from Griffiths [3.71] with
Ī +Ī so 0
Q L
r = or S
r ). This means that l and are still āgood quantum
numbersā, but and are not. The perturbation mixes together states with different
values of and.
s m l ms m l ms Note that the proton exerts a torque on the electron spin. This means that the force of interaction between the two particles is non-central, although this effect is a
āsmall perturbation.ā This means that S
r will precess in its motion about the proton. As a
consequence L
r will also precess, since the net external torque on the atom is zero, and
the total angular momentum of the atom, J L S
r r r = + , must remain fixed. This new total angular momentum operator J
r has properties analogous to S
r and L
r
. It has a ladder of states symmetric about zero. The ladder has a top rung and a
bottom rung. There is a operator with eigenvalues , and a operator with
eigenvalues. There are raising and lowering operators
J^2 j ( j + 1 )h^2 Jz m (^) j h J (^) ± = Jx ± iJy , and
One nice feature of J
r is the fact that it is a āconstant of the motionā for the perturbed Hamiltonian. Hence although we loose and as good quantum
numbers, we gain
Ī +Ī so 0 m l ms j and mj.