Spin-Orbit Interaction in Hydrogen - Lecture Notes | PHYS 402, Study notes of Quantum Physics

Material Type: Notes; Professor: Anlage; Class: Quantum Physics II; Subject: Physics; University: University of Maryland; Term: Unknown 1989;

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Lecture 11 Highlights
We considered the spin-orbit interaction in Hydrogen. The objective is to
calculate the ā€œfine-structureā€ energy splitting due to the spin-orbit effect. The magnetic
moment of the electron interacts with the magnetic field created by the proton to produce
a small energy difference between the
L
r
parallel to S
r
and
L
r
anti-parallel to S
r
situations for the atom. This difference is due to ā€œspin-orbit coupling.ā€
As discussed in Griffiths page 271 the magnetic field experienced by the electron
is given (classically) by:
32
0
8
Brmc
Le
πε
r
r=,
where e is the electronic charge, is the electron mass, cis the speed of light in vacuum,
and m
r
is the proton-electron distance. Note that the magnetic field is parallel to the
electron orbital angular momentum vector. To see why, consider things from the
proton’s rest frame as the electron moves with velocity v
r
through the static electric field
E
rproduced by the proton. It will experience an effective magnetic field given by
E
c
v
B
r
r
r
Ć—āˆ’= (from relativity). By comparing the direction of this field with the direction
of the angular momentum of the electron in its orbit about the proton, this argument
shows that
B
ris parallel to
L
r.
The magnetic moment of charged ā€œspinningā€ particles is given by:
,
S
r
r
γμ
=
where
γ
is called the gyromagnetic ratio. It relates the gyration (or rotation) of the
particle (as embodied in S
r
) to the magnetic moment developed (
r
). A moving charge
creates a magnetic field. A charge moving in a ā€œsmallā€ current loop can be treated as a
magnetic moment, or magnetic dipole, at least for distances large compared to the
diameter of the current loop. For the electron the gyromagnetic ratio is found to be
e
em
e
āˆ’=
γ
to very good approximation. See Griffiths page 272 for a ā€œderivationā€ of this
result. For heavier particles like the proton the gyromagnetic ratio is much smaller due to
the larger mass in the denominator and the fact that angular momentum is quantized and
of order hfor all particles. This fact allows us to ignore the interaction of the proton’s
magnetic moment with the magnetic field created by the electron, at least for now.
The electron’s magnetic moment experiences a torque due to its motion around
the proton. There is a perturbing interaction energy given by;
B
so
r
r
ā€¢āˆ’=Ī—
μ
which becomes;
LS
rmc
Le
S
m
e
so
r
r
r
r•
āŽŸ
āŽŸ
āŽ 
āŽž
āŽœ
āŽœ
āŽ
āŽ›
•
āŽŸ
āŽ 
āŽž
āŽœ
āŽ
āŽ›āˆ’āˆ’=Ī— ~
832
0
πε
This new operator LS
r
r
•has some interesting properties. It commutes with and
, but does not commute with
2
L
2
SS
r
or
L
r
(Homework 4). This means that S
r
and
L
r are no
1
pf2

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Lecture 11 Highlights

We considered the spin-orbit interaction in Hydrogen. The objective is to calculate the ā€œfine-structureā€ energy splitting due to the spin-orbit effect. The magnetic moment of the electron interacts with the magnetic field created by the proton to produce

a small energy difference between the L

r parallel to S

r and L

r anti-parallel to S

r

situations for the atom. This difference is due to ā€œspin-orbit coupling.ā€ As discussed in Griffiths page 271 the magnetic field experienced by the electron is given (classically) by:

2 3 (^80)

B

mcr

eL

r r = ,

where e is the electronic charge, is the electron mass, c is the speed of light in vacuum, and

m r is the proton-electron distance. Note that the magnetic field is parallel to the electron orbital angular momentum vector. To see why, consider things from the proton’s rest frame as the electron moves with velocity v

r through the static electric field E

r produced by the proton. It will experience an effective magnetic field given by

E c

v B

r r r = āˆ’ Ɨ (from relativity). By comparing the direction of this field with the direction

of the angular momentum of the electron in its orbit about the proton, this argument

shows that B

r is parallel to L

r . The magnetic moment of charged ā€œspinningā€ particles is given by: S^ ,

r^ r μ = γ

where γ is called the gyromagnetic ratio. It relates the gyration (or rotation) of the

particle (as embodied in S

r ) to the magnetic moment developed ( μ

r ). A moving charge

creates a magnetic field. A charge moving in a ā€œsmallā€ current loop can be treated as a magnetic moment, or magnetic dipole, at least for distances large compared to the diameter of the current loop. For the electron the gyromagnetic ratio is found to be

e

e m

e

γ = āˆ’ to very good approximation. See Griffiths page 272 for a ā€œderivationā€ of this

result. For heavier particles like the proton the gyromagnetic ratio is much smaller due to the larger mass in the denominator and the fact that angular momentum is quantized and of order h for all particles. This fact allows us to ignore the interaction of the proton’s magnetic moment with the magnetic field created by the electron, at least for now. The electron’s magnetic moment experiences a torque due to its motion around the proton. There is a perturbing interaction energy given by;

so^ B

r r

which becomes;

S L mc r

eL S m

e so

r r r r āŽŸāŽŸ • āŽ 

This new operator S L

r r

  • has some interesting properties. It commutes with and , but does not commute with

L^2

S^2 S^ r^ or L^ r^ (Homework 4). This means that S^ r^ and L^ r^ are no

longer ā€œconstants of the motionā€ under the perturbed Hamiltonian (this follows

from Griffiths [3.71] with

Ī— +Ī— so 0

Q L

r = or S

r ). This means that l and are still ā€œgood quantum

numbersā€, but and are not. The perturbation mixes together states with different

values of and.

s m l ms m l ms Note that the proton exerts a torque on the electron spin. This means that the force of interaction between the two particles is non-central, although this effect is a

ā€œsmall perturbation.ā€ This means that S

r will precess in its motion about the proton. As a

consequence L

r will also precess, since the net external torque on the atom is zero, and

the total angular momentum of the atom, J L S

r r r = + , must remain fixed. This new total angular momentum operator J

r has properties analogous to S

r and L

r

. It has a ladder of states symmetric about zero. The ladder has a top rung and a

bottom rung. There is a operator with eigenvalues , and a operator with

eigenvalues. There are raising and lowering operators

J^2 j ( j + 1 )h^2 Jz m (^) j h J (^) ± = Jx ± iJy , and

commutators such as [ J x , Jy ] = i h Jz.

One nice feature of J

r is the fact that it is a ā€œconstant of the motionā€ for the perturbed Hamiltonian. Hence although we loose and as good quantum

numbers, we gain

Ī— +Ī— so 0 m l ms j and mj.