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This assignment solution was submitted to Amar Sharma for Finite Element Method course at Aligarh Muslim University. It includes: Beam, Element, Generate, Stiffness, Coefficient, Direct, Approach, Equilibrium, Deflection
Typology: Exercises
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For the beam element considered in problem 5.18 generate expressions for the stiffness coefficients K 12 , K 22 , K 32 and K 42
Solution:
Direct approach is used to solve the problem i.e. basic deflection relations and static equilibrium equations. So first we do the solution comprising the deflection relations. For our convenience we replace the symbol used in the figure by the most familiar symbols i.e replacing , , , by , , , respectively.
So for the second column of the stiffness matrix i.e. K 12 , K 22 , K 32 and K 42 .we have all the other constraints equal to zero, while the θa =1. The θ is the rotation produced by the force V.
At any section along the length of the beam we have relation for bending moment which is given as
---------------------------- (ii)
Now from statics we get
------------------------------ (iii)
Now by taking sum of moments at a
----------------------------- (iv)
Thus from (i), (ii), (iii) ,(iv) we get,