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This assignment solution was submitted to Amar Sharma for Finite Element Method course at Aligarh Muslim University. It includes: Beam, Element, Generate, Stiffness, Coefficient, Deflection, Equations, Static, Equilibrium
Typology: Exercises
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Direct approach is used to solve the problem i,e basic deflection relations and static equilibrium equations. So first we do the solution comprising the deflection relations. For our convenience we replace the symbol used in the figure by the most familiar symbols which are given below; Va = q 1 θa = q 2 Vb = q 3 θb = q 4 So for the forth column of the stiffness matrix we have all the other constraints equal to zero, while the θb =1. The θ is the rotation produced by the force V. At any section along the length of the beam we have relation for bending moment which is given as
Now at x = 0 , θ = θa = 0 Thus at x = l, w = wb = ………………………………………. (3) ……………… (4) Now utilizing the second set of boundary conditions Now at x = 0 , θ = Wa = 0 So we have Hence we get ……………………………….(a) at x = l, w = θb =