Structural Analysis, Assignments of Structural Analysis

Structural analysis of beams and telemetry

Typology: Assignments

2020/2021

Uploaded on 06/30/2022

sarah-mize
sarah-mize 🇺🇸

5 documents

1 / 2

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
!
!
!
!
!
!
!
Sarah Mize !
05/02/22!
Homework 3
pf2

Partial preview of the text

Download Structural Analysis and more Assignments Structural Analysis in PDF only on Docsity!

Sarah Mize ① 05/02/ Homework 3

40> A circular shaft of radius = 2 cm and length = 1m is made 08% -TD k Sarah Mize ®O =a with 2024-73 aluminum. Find the rate of twist if applied ET31GPa Ls ee 05/02/22 torque is 1 kN m. Ifthe maximum allowable @is 5*/mand ys 0.93 TI kim Homework 3 torque is 1 KN-m, design a new circular shaft that will G> as bf a the Tand @ requirements Oye SHS MPa Q 7. (000 (a) . =] 8.14 LG se Toots ated * [84 An for O 5 0.087 1220 — af 42 = asm [Rae] Tv hoses BY Gsea = Dod) conns(S) ata Te 1 ADA) ore oon eee oT, ae 24 2B Ve en Blan Bleek yah CE Bayan 2h, , Tate Te ae “Wee Be w))ak« eff ae" SoM a4 - -crcalo = ian FES o-e(2-8-) 2g tae- MBER EM | =o) caw - rae Be Bh ee ae proves the slo ttn of he ber RCBDeFleB-o wee 119) TAA ty ‘ " : pol Cand " We 7% oy THe Te 4 Su xo! ix 2 wh oe, oxy 7 ee 22h 980 Bet Bs BD ee 2) oh “ty Zales caer s- (28.62. CBM CH -(GRYE = By, Tig “so ie 6 oni ~ 3 aC, ag ale) Wbay) = eet v= — ape raenen poy 2 Sebi oer bo vito 4.101 cm, what is the shape that torsional rigidity? Consider elliptic rectangular, and equilateral triangular shapes. <.83 \o0= 1d Bi Bom=d Oe =x 0: 4102and 4.103 with == 10 L 2 = 15cm, respectively Te aA%+ hd, wade, Ts ALbge astadg, Qe 1.384, 8 sax, PE = seta Lrwrng be) be Sem sx be Ls =Wem 8 aga fg = Telnet [Glaundy-qis] be 2 Peak. Sy, Ret a wane BBA Test J Twos GO = Hrala(dls4+ Lalagadt Agqbi + Agbs - Ibs Lytle Dem Ls IDem. $2 0-3em Je Nenwcoren PDE, pont 29, (lope a4 4” id achieve the highest (including circular), I- ran @ab Be DDidcem Te table eb ag e008 oe oan Bete Ts Noon Gnmys ronpase) ns ag r5* 24,4 - = 1-884,40 A thin aluminum sheet is to be used to form a closed thin- walled section. If the total length of the wall contour is 100 3x= D0 to WE Ire yte 44428. 9emt 00> aot ab }_ antes a0’ n°) = 10.0ecm 4 io. Consider a t quare section with the cross: ction shown in Figure 4.10.4a. The wall thickn m and the average side length is 15 cm. Find t! ut open 4.3, stant. Find the shear s He distributions if @ = 2°/m, 5: HUbs(Lbs4+ Lalagd& Tamas 4Qd" 4Goudto3_ Agbi + qds - Jabs > ater)” 20% J ApMLineog PIP? pons Toe $b" = Stomaenpost eared 2.4, lode a4,00d- 4 Jeu = 90040.27 [eu = 200.207 ens!